若sinx-2cosy=根号2cosx+2sinx=2则sin(x-y) 已知sinx+siny=根号2/2,则cosx+cosy的取...

\u82e5sinx-2cosy=2\uff0ccosx+2siny=2\uff0c\u5219sin\uff08x-y\uff09=?14?14

\u7531sinx-2cosy=2\uff0ccosx+2siny=2\uff0c\u5f97\uff08sinx-2cosy\uff092=2\uff0c\uff08cosx+2siny\uff092=4\uff0c\u5373sin2x-4sinxcosy+4cos2y=2\u4e14cos2x+4cosxsiny+4sin2y=4\uff0c\u4e24\u5f0f\u76f8\u52a0\u5f971+4sin\uff08y-x\uff09+4=2+4=6\uff0c\u5373sin\uff08x-y\uff09=-14\uff0c\u6545\u7b54\u6848\u4e3a\uff1a?14\uff1b

\u56e0\u4e3acos(x-y)\u7684\u503c\u57df\u662f\u3010-1,1\u3011\uff0c\u6240\u4ee5-1\u2264(2t^2-3)/4\u22641 \u3002

2cosx^2+4sinx^2+16sinxcosx=4
=>2sinx^2+16sinxcosx=2
=>1-cos2x+8sin2x=2
=>8sin2x-cos2x=1 (1)
sin2x^2+cos2x^2 = 1 (2)
(1)和(2)=>sin2x=0或者sin2x=16/65
当sin2x=0时 cos2x = -1 =>2x = (2k+1)pai=>x=(k+1/2)pai
sinx = 1 cosx=0
或者sinx=-1 cosx=0 (sinx-2cosy=2不可能满足)
sinx=1 cosy= -1/2=>siny = (3/4)^(1/2)

sin(x-y) = sinxcosy-sinycosx=sinxcosy=1*(-1/2) = -1/2

当sin2x=16/65时,cos2x=63/65=>1-sinx^2=cos2x=63/65=>sinx^2 = 2/65=>sinx=(2/65)^(1/2)
由根号2cosx+2sinx=2=>sinx>=0 cosx>=0

cosx = (63/65)^(1/2)
2cosy= 2-(2/65)^(1/2) siny可求
再代入原式,可求结果

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