java:获取字符串中第一个不是数字或者标点符号或者空格的位置
\u4e3a\u4ec0\u4e48JAVA\u7a0b\u5e8f\u5185\u5e26\u7a7a\u683c\u7684\u5b57\u7b26\u4e32\u6bd4\u8f83\u540e\u6570\u4e0d\u51fa\u6765\uff1f\u5e94\u8be5\u662f\u88ab\u53bb\u7a7a\u683c\u4e86\uff0ctrim\uff08\uff09\uff1b
\u6bd4\u8f83\u4e2d\u53ef\u80fd\u8c03\u7528\u4e86\u8fd9\u4e2a\u65b9\u6cd5
\u4f60\u53ef\u4ee5\u628a\u7a0b\u5e8f\u8d34\u51fa\u6765\uff0c\u66f4\u597d\u89e3\u51b3
\u53ef\u4ee5\u5408\u5e76\u3002replaceAll\u65b9\u6cd5\u7b2c\u4e00\u4e2a\u53c2\u6570\u662f\u6307\u6b63\u5219\u8868\u8fbe\u5f0f\u3002\u6240\u4ee5\u4f7f\u7528\u4e00\u4e2a\u5c31\u884c\u3002
s.replaceAll("\u3002+|\uff0c+|,+|.+","\n");\u5176\u4e2d|\u4ee3\u8868\u6216\uff0c+\u4fee\u9970\u524d\u9762\u7684\u5b57\u7b26\u51fa\u73b0\u81f3\u5c111\u6b21\u3002
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Test {
public static void main(String[] args) {
String testStr="122, 3. 92啊a";
String regex="[^\\p{Punct}\\p{Space}\\p{Digit}]";
Matcher matcher=Pattern.compile(regex).matcher(testStr);
if(matcher.find()) {
int index=matcher.start();
System.out.println("第一个不是数字标点或空格的位置是:"+index);
}else {
System.out.println("第一个不是数字标点或空格的位置:在该字符串中不存在！");
}
}
}
不说了，上程序，看不明白了说啊。
你这个范围有点大,不好写的(光标点符号就好多)
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