C语言中x+y>b&&a/b==x是什么意思？ c语言里，a/b什么意思?
C\u8bed\u8a00\u4e2dx+=y,x-=y\u5206\u522b\u8868\u793a\u4ec0\u4e48\u610f\u601dx+=y \u5c31\u662fx=x+y\u7684\u7b80\u5199\u3002x-=y \u5c31\u662fx=x-y\u7684\u7b80\u5199
1\u3001+=; -= \u662f\u590d\u5408\u7684\u8d4b\u503c\u8fd0\u7b97\u7b26\u3002
2\u3001C\u8bed\u8a00\u91c7\u7528\u590d\u5408\u8fd0\u7b97\u7b26 \u4e00\u662f\u7b80\u5316\u7a0b\u5e8f\u3002\u4e8c\u662f\u4e3a\u4e86\u63d0\u9ad8\u7f16\u8bd1\u6548\u7387\uff0c\u80fd\u4ea7\u751f\u8d28\u91cf\u8f83\u9ad8\u7684\u76ee\u6807\u4ee3\u7801\u3002
3\u3001\u5ef6\u4f38\u77e5\u8bc6\u70b9\uff1ax*=y \u5c31\u662fx=x*y\u7684\u7b80\u5199\uff0c\u4f9d\u6b21\u7c7b\u63a8\u3002
\u6269\u5c55\u8d44\u6599
C\u8bed\u8a00\u7684\u987a\u5e8f\u7ed3\u6784\uff1a
\u987a\u5e8f\u7ed3\u6784\u7684\u7a0b\u5e8f\u8bbe\u8ba1\u662f\u6700\u7b80\u5355\u7684\uff0c\u53ea\u8981\u6309\u7167\u89e3\u51b3\u95ee\u9898\u7684\u987a\u5e8f\u5199\u51fa\u76f8\u5e94\u7684\u8bed\u53e5\u5c31\u884c\uff0c\u5b83\u7684\u6267\u884c\u987a\u5e8f\u662f\u81ea\u4e0a\u800c\u4e0b\uff0c\u4f9d\u6b21\u6267\u884c\u3002
\u4f8b\u5982\uff1aa = 3\uff0cb = 5\uff0c\u73b0\u4ea4\u6362a\uff0cb\u7684\u503c\uff0c\u8fd9\u4e2a\u95ee\u9898\u5c31\u597d\u50cf\u4ea4\u6362\u4e24\u4e2a\u676f\u5b50\u6c34\uff0c\u8fd9\u5f53\u7136\u8981\u7528\u5230\u7b2c\u4e09\u4e2a\u676f\u5b50\uff0c\u5047\u5982\u7b2c\u4e09\u4e2a\u676f\u5b50\u662fc\uff0c\u90a3\u4e48\u6b63\u786e\u7684\u7a0b\u5e8f\u4e3a\uff1ac = a\uff1b a = b\uff1b b = c\uff1b\u6267\u884c\u7ed3\u679c\u662fa = 5\uff0cb = c = 3\u5982\u679c\u6539\u53d8\u5176\u987a\u5e8f\uff0c\u5199\u6210\uff1aa = b\uff1b c = a\uff1b b =c\uff1b\u5219\u6267\u884c\u7ed3\u679c\u5c31\u53d8\u6210a = b = c = 5\uff0c\u4e0d\u80fd\u8fbe\u5230\u9884\u671f\u7684\u76ee\u7684\uff0c\u521d\u5b66\u8005\u6700\u5bb9\u6613\u72af\u8fd9\u79cd\u9519\u8bef\u3002
\u987a\u5e8f\u7ed3\u6784\u53ef\u4ee5\u72ec\u7acb\u4f7f\u7528\u6784\u6210\u4e00\u4e2a\u7b80\u5355\u7684\u5b8c\u6574\u7a0b\u5e8f\uff0c\u5e38\u89c1\u7684\u8f93\u5165\u3001\u8ba1\u7b97\uff0c\u8f93\u51fa\u4e09\u6b65\u66f2\u7684\u7a0b\u5e8f\u5c31\u662f\u987a\u5e8f\u7ed3\u6784\uff0c\u4f8b\u5982\u8ba1\u7b97\u5706\u7684\u9762\u79ef\uff0c\u5176\u7a0b\u5e8f\u7684\u8bed\u53e5\u987a\u5e8f\u5c31\u662f\u8f93\u5165\u5706\u7684\u534a\u5f84r\uff0c\u8ba1\u7b97s = 3.14159*r*r\uff0c\u8f93\u51fa\u5706\u7684\u9762\u79efs\u3002
\u4e0d\u8fc7\u5927\u591a\u6570\u60c5\u51b5\u4e0b\u987a\u5e8f\u7ed3\u6784\u90fd\u662f\u4f5c\u4e3a\u7a0b\u5e8f\u7684\u4e00\u90e8\u5206\uff0c\u4e0e\u5176\u5b83\u7ed3\u6784\u4e00\u8d77\u6784\u6210\u4e00\u4e2a\u590d\u6742\u7684\u7a0b\u5e8f\uff0c\u4f8b\u5982\u5206\u652f\u7ed3\u6784\u4e2d\u7684\u590d\u5408\u8bed\u53e5\u3001\u5faa\u73af\u7ed3\u6784\u4e2d\u7684\u5faa\u73af\u4f53\u7b49\u3002
\u53c2\u8003\u8d44\u6599
\u767e\u5ea6\u767e\u79d1-C\u8bed\u8a00
/\u7684\u610f\u601d\u662f\u9664\u6cd5\uff0ca\u548cb\u662f\u6574\u6570\uff0c\u6240\u4ee5a/b\u7b97\u51fa\u6765\u662f\u6574\u6570\u3002
c\u8bed\u8a00\u8fd0\u7b97\u7b26\uff1a
!\u903b\u8f91\u975e\u8fd0\u7b97\u7b26
~\u6309\u4f4d\u53d6\u53cd\u8fd0\u7b97\u7b26
++\u81ea\u589e\u8fd0\u7b97\u7b26
--\u81ea\u51cf\u8fd0\u7b97\u7b26
-\u8d1f\u53f7\u8fd0\u7b97\u7b26
(\u7c7b\u578b)\u7c7b\u578b\u8f6c\u6362\u8fd0\u7b97\u7b26
*\u6307\u9488\u8fd0\u7b97\u7b26
&\u5730\u5740\u4e0e\u8fd0\u7b97\u7b26
sizeof\u957f\u5ea6\u8fd0\u7b97\u7b26
\u6269\u5c55\u8d44\u6599
c\u8bed\u8a00\u7684\u7279\u70b9
1\u3001\u5728\u6807\u51c6C\u8bed\u8a00\u7684\u6587\u6863\u91cc\uff0c\u5bf9\u64cd\u4f5c\u7b26\u7684\u7ed3\u5408\u6027\u5e76\u6ca1\u6709\u505a\u51fa\u975e\u5e38\u6e05\u695a\u7684\u89e3\u91ca\u3002\u4e00\u4e2a\u6ee1\u5206\u7684\u56de\u7b54\u662f:\u5b83\u662f\u4ef2\u88c1\u8005\uff0c\u5728\u51e0\u4e2a\u64cd\u4f5c\u7b26\u5177\u6709\u76f8\u540c\u7684\u4f18\u5148\u7ea7\u65f6\u51b3\u5b9a\u5148\u6267\u884c\u54ea\u4e00\u4e2a\u3002
2\u3001C\u8bed\u8a00\u4e5f\u5c0634\u79cd\u8fd0\u7b97\u7b26\u89c4\u5b9a\u4e86\u4e0d\u540c\u7684\u7ed3\u5408\u6027\u3002\u5927\u591a\u6570\u8fd0\u7b97\u7b26\u7ed3\u5408\u65b9\u5411\u662f\u201c\u81ea\u5de6\u81f3\u53f3\u201d\uff0c\u5373\uff1a\u5148\u5de6\u540e\u53f3\uff0c\u4e5f\u53eb\u201c\u5de6\u7ed3\u5408\u6027\u201d\uff0c\u4f8b\u5982a\uff0db+c\uff0c\u8868\u8fbe\u5f0f\u4e2d\u6709\uff0d\u548c+\u4e24\u79cd\u8fd0\u7b97\u7b26\uff0c\u4e14\u4f18\u5148\u7ea7\u76f8\u540c\u3002
3\u3001C\u8bed\u8a00\u6709\u4e09\u7c7b\u8fd0\u7b97\u7b26\u7684\u7ed3\u5408\u65b9\u5411\u662f\u4ece\u53f3\u81f3\u5de6\uff0c\u4e5f\u53eb\u201c\u53f3\u7ed3\u5408\u6027\u201d\uff0c\u5373:\u5355\u76ee\u8fd0\u7b97\u7b26\u3001\u6761\u4ef6\u8fd0\u7b97\u7b26\u3001\u4ee5\u53ca\u8d4b\u503c\u8fd0\u7b97\u7b26\u3002
\u53c2\u8003\u8d44\u6599\u6765\u6e90\uff1a\u767e\u5ea6\u767e\u79d1\u2014c\u8bed\u8a00\u8fd0\u7b97\u7b26\u53f7
C语言中x+y>b&&a/b==x，就是先判断x+y>b是否满足，如果此条件满足，再判断a/b是否等于x。
判断的结果只有两种可能，满足，或不满足。
绛旓細杈撳嚭璇彞涓(x ,y)鏄楀彿琛ㄨ揪寮,鍙緭鍑簓 鍊,鑰寉 鐨鍊煎湪鍓嶉潰宸茬粡鍜寈 鍊艰繘琛屼簡璋冩崲,褰撶劧杈撳嚭100浜
绛旓細鍖呮嫭main锛鐨澶栭儴#include int x,y,z;void year(int a,int b,int c);int main(){ int i,a,b,c;for(i=1;i<=1;i++){ scanf("%d,%d,%d",&a,&b,&c);printf("a=%d\n",a);printf("b=%d\n",b);printf("c=%d\n",c);}杩欓噷x y z灏辨槸鍏ㄥ眬鍙橀噺锛屽叾浠栭兘鏄眬閮ㄥ彉閲 ...
绛旓細杩欐浠ｇ爜鍦 C 璇█涓瀹氫箟浜嗕袱涓彉閲 x 鍜 y銆傚叾涓 x 鐨勭被鍨嬩负 float锛屽嵆娴偣鏁帮紝骞朵笖鍒濆鍊间负 10銆倅 鐨勭被鍨嬩篃涓 float锛屼絾娌℃湁鍒濆鍊硷紝鍥犳 y 鐨勫兼槸鏈畾涔夌殑銆俧loat 绫诲瀷鐨勫彉閲忔槸鐢ㄦ潵瀛樺偍鍗曠簿搴︽诞鐐规暟鐨勶紝鍗曠簿搴︽诞鐐规暟鍗犵敤 4 涓瓧鑺傜殑鍐呭瓨绌洪棿锛屽彲浠ョ敤鏉ヨ〃绀鸿緝澶ц寖鍥村唴鐨勫皬鏁板硷紝绮惧害杈冧綆銆
绛旓細鍥犱负C璇█涓瓁鐨勪簩娆℃柟鐢▁*x琛ㄧず鎴栬呯敤鍑芥暟pow(x,2)琛ㄧず (闇瑕佸寘鍚ご鏂囦欢#include<math.h>)鎵浠y=x^2鍦–璇█涓笉鏄〃绀簒鐨勪簩娆℃柟,鑰屾槸x鎸変綅寮傛垨2,鍥犳缁撴灉涓嶅.鍙﹀,棰樼洰瑕佹眰杈撳叆涓涓疄鏁,鎵浠,y瑕佽瀹氫箟涓篸ouble鍨,杈撳叆杈撳嚭鏍煎紡绗%d瑕佹敼鎴%lf 鏀规鍚庣殑绋嬪簭濡備笅(瑙佸浘,鏀瑰姩鐨勫湴鏂硅娉ㄩ噴)...
绛旓細x+=y 灏辨槸x=x+y鐨绠鍐欍倄-=y 灏辨槸x=x-y鐨勭畝鍐 1銆+=; -= 鏄鍚堢殑璧嬪艰繍绠楃銆2銆C璇█閲囩敤澶嶅悎杩愮畻绗 涓鏄畝鍖栫▼搴忋備簩鏄负浜嗘彁楂樼紪璇戞晥鐜囷紝鑳戒骇鐢熻川閲忚緝楂樼殑鐩爣浠ｇ爜銆3銆佸欢浼哥煡璇嗙偣锛歺*=y 灏辨槸x=x*y鐨勭畝鍐欙紝渚濇绫绘帹銆
绛旓細濡傛灉x銆亂閮藉凡缁忓湪鍓嶉潰瀹氫箟杩囷紝涓旀渶鍚庢湁鍒嗗彿锛屽嵆锛歺=y;y=x;灏辨槸瀵圭殑锛屽惁鍒欓敊浜嗐傚疄闄呬笂鍙渶瑕佹墽琛寈=y;璧嬪煎悗锛寈鍜y鐨鍊煎氨鐩稿悓浜嗭紝y=x;灞炲浣欍傚綋鐒讹紝鍔犱笂鐨勮瘽锛岃娉曚篃鏄鐨勩
绛旓細浠ｇ爜濡備笅:include <stdio.h>#include <stdlib.h>int func(int x, int y){if (x > y) {return 1;}else if (x < y) {return -1;}else {return 0;}}int main(){int x, y, ret;printf("璇疯緭鍏,y鐨鍊硷細");scanf("%d%d", &x, &y);ret = func(x, y);printf("%d\n",...
绛旓細x+=y 绛変环浜巟 = x + yx-=y 绛変环浜 x = x - y 鍚岀悊x*=y 绛変环浜巟 = x * y銆傚浠ヤ笅浠ｇ爜锛歩nt main(){ int a = 1;int b = 2;int c = 1;a+=b; //绛変环浜巃 = a + b c = c + b; //绛変环浜巆+=b printf("%d %d" ,a ,c); //杈撳嚭a鍜宑 return 0;} 缁撴灉鍥...
绛旓細include<stdio.h> int add(int a,int b){ return a+b;} int sub(int a,int b){ return a-b;} int mul(int a,int b){ return a*b;} float divi(int a,int b){ return 1.0*a/b;} void main(){ int x,y;scanf("%d%d",&x,&y);printf("x+y=%d\n",add(x,y));p...
绛旓細8銆佷俊浠诲氨鏄竴鎶婂垁锛屼綘缁欎簡鍒汉锛屼粬灏辨湁涓や釜閫夋嫨锛屾崊浣犳垨鑰呬繚鎶や綘锛屽お鐪嬮噸鎰熸儏鐨勪汉灏辨槸杩欐牱锛屽鏄撴弧瓒筹紝鏇村鏄撳彈浼ゃ9銆佹绘槸璇曞浘灏嗘墍鏈夌殑杩囧線鍏ㄩ儴鎶涘純锛屽彲绾电劧濡傛鎴戣繕鏄湪姊︿腑鎯婇啋锛屽湪澶滈噷鍝常锛屽害鏃ュ骞磋埇搴︽暟鐫杩欎竴娈典笉鍐嶄笌浣犵浉鍏崇殑鍒嗙宀佹湀銆10銆佹病鏈夎冻澶鐨勮瑷鑳借〃杈炬垜瀵逛綘鐨勭埍锛屾病鏈夎冻澶熺殑...
