python中如何根据嵌套列表内的元素进行排序 python 怎么快速获取嵌套列表内的每一个元素？
python\u4e2dflat\u5c06\u5d4c\u5957\u5217\u8868\u4e2d\u7684\u5143\u7d20\u6309\u987a\u5e8f\u6392\u5217\u5728\u4e00\u4e2a\u5217\u8868\u4e2d\u6309\u7167\u4f60\u7684\u8981\u6c42\u7f16\u5199\u7684Python\u7a0b\u5e8f\u5982\u4e0b
def flat(nestedlist):
outcome = [nestedlist[i][j] for i in range(len(nestedlist)) for j in range(len(nestedlist[i]))]
return outcome
print(flat([[1,2,3],[4,5,6],[7,8,9]]))
\u6e90\u4ee3\u7801(\u6ce8\u610f\u6e90\u4ee3\u7801\u7684\u7f29\u8fdb)
aa = [[(55736,)], [(55739,)], [(55740,), (55801,)], [(55748,)], [(55783,), (55786,), (55787,), (55788,)], [(55817,), (55821,)], [(55818,)]]def getelement(aa): for elem in aa: if type(elem)==type([]): for element in getelement(elem): yield element else:yield elemfor elem in getelement(aa):print(elem)(55736,)(55739,)(55740,)(55801,)(55748,)(55783,)(55786,)(55787,)(55788,)(55817,)(55821,)(55818,)
# -*- coding: utf-8 -*-
import operator
target_list = [["A",3],["B",2],["C",1]]
'''
sorted默认为从小到大排序，如果从大到小，请使用:
target_list.sort(key=operator.itemgetter(1), reverse=True)
'''
target_list.sort(key=operator.itemgetter(1))
print(target_list)
楼主你好，按以上代码就可以得到想要的结果。
python本身还提供了非常丰富的排序功能，该需求还有另外的形式能够实现，请自行阅读官方文档研究。望采纳，谢谢！
参考资料：https://docs.python.org/2/howto/sorting.html#sortinghowto
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