4道初2因式分解题
\u521d2\u56e0\u5f0f\u5206\u89e3\u9898-3x(x-2y+11)
1.x^2n+x^n-1/9y^2+1/4
=(x^n)^2+(x^n)+1/4-(1/9)y^2
=[(x^n)^2+(x^n)+1/4]-(1/9)y^2
=[x^n+1/2]^2-[(1/3)y]^2
=[x^n+1/2+(1/3)y]*[x^n+1/2-(1/3)y]
2.
x^4-11x^2y^2+y^4
=x^4+(3x^3y-3x^2y)-[-x^2y^2-9x^2y^2-x^2y^2]+(3xy^3-3xy^3)+y^4
=(x^4+3x^3y-x^2y^2)+(-3x^3y-9x^2y^2+3xy^3)+(-x^2y^2-3xy^3+y^4)
=x^2(x^2+3xy-y^2)-3xy(x^2+3xy-y^2)-y^2(x^2+3xy-y^2)
=(x^2+3xy-y^2)(x^2-3xy-y^2)
3.
(2x^2-3x+1)^2-22x^2+33x-1
=(2x^2-3x+1)^2-22x^2+33x-11+10
=(2x^2-3x+1)^2-11(2x^2-3x+1)+10
=(2x^2-3x+1-1)(2x^2-3x+1-10)
=(2x^2-3x)(2x^2-3x-9)
=x(2x-3)(x-3)(2x+3)
4.x^4+7x^3+14x^2+7x+1
=x^4+7x^3+(12x^2+2x^2)+7x+1
=(x^4+7x^3+12x^2)+(x^2+x^2)+(3x+4x)+1
=(x^2+3x)(x^2+4x)+(x^2+3x)+(x^2+4x+1)
=(x^2+3x)(x^2+4x+1)+(x^2+4x+1)
=(x^2+3x+1)(x^2+4x+1)
答案分别为：
1/36 ×(3 + 6 X^n - 2 y) (3 + 6 X^n + 2 y)
不能再分解了
(-3 + x) x (-3 + 2 x) (3 + 2 x)
(1 + 3 X + X^2) (1 + 4 X + X^2)
I DON"T KNOW
绛旓細3.x^2+3xy+2y^2+4x+5y+3=(x+y+a)(x+2y+b)瑙ｅ嚭,a=1,b=3 鎵浠,x^2+3xy+2y^2+4x+5y+3=(x+y+1)(x+2y+3)杩欐槸涓绉嶅緟瀹氱郴鏁版硶 4.12*A^((3N+1)-32*A^(2N-1)+24*A^(N-1)=4A^(N-1)[3A^(2N+1)-8*A^N+6]...
绛旓細=(x-y)(2y-x)绗鍥涢亾锛氾紙X鐨勫钩鏂-4B鐨勫钩鏂癸級+8AB-4AX =x^2-4b^2+8ab-4ax =(x^2-4ax+4a^2)-(4b^2-8ab+4a^2)=(x-2a)^2-(2a-2b)^2 =[(x-2a)+(2a-2b)][(x-2a)-(2a-2b)]=(x-2b)(x-4a+2b)绗5閬擄紙3A n+1鐨勫钩鏂-9A N-1鐨勫钩鏂癸級闄わ紙-涓夊垎涔嬩竴AN-2鐨勫钩...
绛旓細1銆3a(a-b)³-2b(b-a)³=3a(a-b)³+2b(a-b)³=(3a+2b)(a-b)³2銆12x²y-6xy²-8x³y³=2xy(6x-3y+4x²y²)3銆9y²-4x²=(3y)²-(2x)²=(3y+2x)(3y-2x)4銆4x²-4xy-9+y&#...
绛旓細1銆佸師寮=(2x^)2-2*2x+1^2=锛2X-1)^2 2銆佸師寮=-3锛圶^2-2XY+Y^2)-3(X-Y)^2 3銆佸師寮=3a(X^2+2XY+Y^2)=3a(X+Y)^2 4銆佸師寮=(a+b)^2-2*6(a+b)+6^2=(a+b-6)^2 5銆佸師寮=1^2+2*5*t+(5t)^2=锛1+5t)^2 6銆佸師寮=m^2-2*7*m+7^2=(m-7)^2 ...
绛旓細鍥涢亾鍒濅簩鍥犲紡鍒嗚В姹傝В绛,閲嶈祻 m(m+n)(m-n)-m(m+n)²,鍏朵腑m+n=1,mn=-1/2,姹俶,n鐨勫8(x²-2y²)-x(7x+y)+xy鍒嗚В鍥犲紡m²(m-1)-4(1-m²)鍒嗚В鍥犲紡鑻²+y²-4x+6y+13=0,姹2x+3y鐨勫... m(m+n)(m-n)-m(m+n)²,鍏朵腑m+n=1,mn=-1/2,姹俶,n鐨勫8(x...
绛旓細9锛2x-y锛塣2-16锛坸+2y锛塣2 =銆3锛2x-y锛夈慯2-銆4锛坸+2y锛夈慯2 =銆3锛2x-y锛-4锛坸+2y锛夈*銆3锛2x-y锛+4锛坸+2y銆=锛2x-11y锛夛紙10x+5y锛121锛坅-b锛塣2-169锛坅+b锛塣2 = 銆 11锛坅-b锛夈慯2-銆13锛坅+b锛夈慯2 =銆11锛坅-b锛-13锛坅+b锛夈*銆11锛坅-b锛+13锛...
绛旓細50銆24a^3b^2梅3ab^2=8a^2,9,鍥犲紡鍒嗚В3a3b2c锛6a2b2c2锛9ab2c3锛3ab^2 c(a^2-2ac+3c^2)3.鍥犲紡鍒嗚Вxy锛6锛2x锛3y锛(x-3)(y-2)4.鍥犲紡鍒嗚Вx2(x锛峺)锛媦2(y锛峹)锛(x+y)(x-y)^2 5.鍥犲紡鍒嗚В2x2锛(a锛2b)x锛峚b锛(2x-a)(x+b)6.鍥犲紡鍒嗚Вa4锛9a2b2锛漚^2(a+3b)...
绛旓細x-y)²(x+y)a(1锛峚锛夛紞锛坅锛1)²=a(1-a)-(1-a)²=(1-a)(a-1+a)=(1-a)(2a-1)(a锛4锛²锛嶏紙2a锛8锛=(a-4)²-2(a-4)=(a-4)(a-4-2)=(a-4)(a-6)(x+2)(x+3)+(x锛2)(x+2)=(x+2)[(x+3)+(x-2)=(x+2)(2x+1)
绛旓細1.鑻2x3锛3x2锛媘x锛1涓簒锛1鐨勫嶅紡,鍒檓锛 2.鍥犲紡鍒嗚В3a3b2c锛6a2b2c2锛9ab2c3锛 3.鍥犲紡鍒嗚Вxy锛6锛2x锛3y锛 4.鍥犲紡鍒嗚Вx2(x锛峺)锛媦2(y锛峹)锛 5.鍥犲紡鍒嗚В2x2锛(a锛2b)x锛峚b锛 6.鍥犲紡鍒嗚Вa4锛9a2b2锛 7.鑻ュ凡鐭3锛3x2锛...
绛旓細1.8a-4a^-4= -4锛坅^-2a+1锛=-4锛坅-1锛塣 2.9(x+y)^-81(x-y)^ =[3(x+y)]^-[9(x-y)]^ =(3x+3y+9x-9y)(3x+3y-9x+9y)=(12x-6y)(12y-6x)=36(2x-y)(2y-x)3.4b^c^-(b^+c^-a^)^ =(2bc)^-(b^+c^-a^)^ =(2bc+b^+c^-a^)(2bc-b^-c^+a^)=...
