设二维随机变量(X,Y)的概率密度为f(x,y)=2-x-y 设二维随机变量(X,Y)的概率密度为:f(x,y)=4.8y...

\u8bbe\u4e8c\u7ef4\u968f\u673a\u53d8\u91cf x y \u7684\u6982\u7387\u5bc6\u5ea6\u51fd\u6570\u4e3afxy=2-x-y\uff0c

\u89e3\uff1a(1)\u4f9d\u636e\u5b9a\u4e49\uff0cX\u7684\u8fb9\u7f18\u5bc6\u5ea6fX(x)=\u222b(-\u221e,\u221e)f(x,y)dy=\u222b(0,1)(2-x-y)dy=3/2-x\u3002\u540c\u7406\uff0cX\u7684\u8fb9\u7f18\u5bc6\u5ea6fY(y)=\u222b(-\u221e,\u221e)f(x,y)dx=\u222b(0,1)(2-x-y)dx=3/2-y\u3002
\u663e\u7136\uff0cfX(x)*fY(y)\u2260f(x,y)\uff0c\u2234X\u3001Y\u4e0d\u76f8\u4e92\u72ec\u7acb\u3002
(2)\uff0cP(X+Y\u22641)=P(X\u22641-Y)=\u222b(0,1)dy\u222b(0,1-y)(2-x-y)dx=(1/2)\u222b(0,1)(3-4y+y²)dy=2/3\u3002
\u4f9b\u53c2\u8003\u3002

\u89e3\uff1a
f(y)=
\u222b(-\u221e\u5230\u221e)f(x,y)dx
=\u222b(y\u52301)4.8y(2-x)dx
=2.4xy(4-x)|(y\u52301)
=2.4y(3-4y+y²) (0
\u5173\u4e8ex\u7684\u8fb9\u9645\u5bc6\u5ea6\u51fd\u6570Px(x):
\u5f530\u2264x\u22641\u65f6
Px(x)=\u222bf(x,y)dy,\u5173\u4e8ey\u4ece\uff0d\u221e\u79ef\u5230\uff0b\u221e=\u222b\uff082-x-y\uff09dy,\u5173\u4e8ey\u4ece0\u79ef\u52301
\u5176\u4e2d\u539f\u51fd\u6570\u4e3a\uff1a\uff082*y-x*y-y²/2\uff09
Px(x)=(2-x-½)-0=3/2-x
\u5f53x\uff1e1\u6216\u8005x\uff1c0\u65f6
Px(x)=0
\u5173\u4e8ey\u7684\u8fb9\u9645\u5bc6\u5ea6\u51fd\u6570Py(y):
\u5f530\u2264x\u22641\u65f6
Py(y)=\u222bf(x,y)dx,\u5173\u4e8ex\u4ece\uff0d\u221e\u79ef\u5230\uff0b\u221e=\u222b\uff082-x-y\uff09x,\u5173\u4e8ex\u4ece0\u79ef\u52301
\u5176\u4e2d\u539f\u51fd\u6570\u4e3a\uff1a\uff082*x-x²/2-x*y\uff09
Py(y)=(2-½-y)-0=3/2-y
\u5f53y\uff1e1\u6216\u8005y\uff1c0\u65f6
Py(y)=0

\u6269\u5c55\u8d44\u6599
\u6c42\u8fb9\u7f18\u6982\u7387\u5bc6\u5ea6\u7684\u65b9\u6cd5\uff1a
\u6c42y\u7684\u8fb9\u7f18\u5bc6\u5ea6,\u5bf9x\u4f5c\u5168\u79ef\u5206\uff0c\u6c42x\u7684\u8fb9\u7f18\u5bc6\u5ea6,\u5bf9y\u4f5c\u5168\u79ef\u5206\uff0c\u5168\u90e8\u662f\u5e38\u6570\u8303\u56f4\u5f88\u5bb9\u6613\u5224\u65ad\uff0c\u5982\u679c\u6709\u975e\u77e9\u5f62\u8303\u56f4\u7684\u8054\u5408\u5bc6\u5ea6\u51fd\u6570\u3002
\u4f8b\uff1a
\u6982\u7387\u8f6c\u5316\u4e3a\u9762\u79ef\uff1a
\u8054\u5408\u6982\u7387P(X=a,Y=b)\uff0c\u6ee1\u8db3X=a\u4e14Y=b\u7684\u9762\u79ef\uff0c\u8fb9\u7f18\u6982\u7387P(X=a)\uff0c\u4e0d\u8003\u8651Y\u7684\u53d6\u503c\uff0c\u6240\u6709\u6ee1\u8db3X=a\u7684\u533a\u57df\u7684\u603b\u9762\u79ef\uff0c\u6761\u4ef6\u6982\u7387P(X=a|Y=b)\uff0c\u5728Y=b\u7684\u524d\u63d0\u4e0b\uff0c\u6ee1\u8db3X=a\u7684\u9762\u79ef\uff08\u6bd4\u4f8b\uff09\u3002

∫(0~1)∫(2y~1) 2-x-y dxdy
=∫(0~1){ (2-y)x-x²/2 |(2y~1) } dy
=∫(0~1)(2-y)(1-2y)-(1-4y²)/2 dy
=∫(0~1) 2-5y+2y²-(1-4y²)/2 dy
= 2y-2.5y²+(2/3)y³-(y-4y³/3)/2 (y=1)
=2-2.5+2/3-(-1/6)
=5/6-0.5
=4/12
=1/3

z=x+y
当z=x+y<=1时
x不超过z
卷积
∫(0~z)f(x,z-x) dx
=∫(0~z) 2-z dx
= (2-z)x (x:0~z)
=(2-z)z

当z=x+y>1时
卷积
x~(z-1~1) 就是方块右上角
∫(z-1~1) f(x,z-x) dx
= (2-z)(2-z+1)
=(2-z)²

fz(z)=(2-z)z (0<x<=1)
=(2-z)² (1<x<2)
=0 else

  • 璁句簩缁撮殢鏈哄彉閲(X,Y)鐨勬鐜瀵嗗害涓篺(x,y)= e鐨-y娆℃柟,0<x<y 0, 鍏朵粬
    绛旓細3銆佹潯浠跺垎甯冿紝搴旇鍐欐垚 fX(x|Y=y)鑰岄潪f尉(x|畏=y)锛岃〃绀篩=y鐨勬潯浠跺垎甯冿紝鎸夐鐩剰鎬濓紝姝ゅy鐞嗚В涓烘煇涓甯告暟锛屽垯fX(x|Y=y)=f(x,y)/fY(y)=e^(-y)/ye^(-y)=1/y锛沠Y(y)=ye^(-y)闅忔満鍙橀噺Y鐨勮竟娌垮垎甯冦4銆佹潯浠姒傜巼锛屼技搴斿啓鎴怭锛圶<2|Y<1)锛屼篃鏄Н鍒嗚绠楋細P锛圶<2|Y<1)锛...
  • 璁句簩缁撮殢鏈哄彉閲(X,Y)鐨勬鐜瀵嗗害涓篺(x,y)=2?x?y,0<x<1,0<y<10,otherwis...
    绛旓細瑙g瓟锛氥愯瑙c戯紙 I锛夌敱浜 fz(z)锛濃埆+鈭?鈭漟(x锛z?2x)dx锛屽叾涓璮(x锛寊?2x)锛2?x?(z?2x)锛0锛渪锛1锛0锛渮?2x锛10锛屽叾浠=2+x?z锛0锛渪锛1锛2x锛渮锛1+2x0锛屽叾浠栨晠锛1锛夊綋z鈮0鎴杬鈮3鏃讹紝fz锛坺锛=0锛2锛夊綋0锛渮锛1鏃讹紝鏈塮z(z)锛濃埆z20(2+x?z)dx锛漽?38z2锛3锛夊綋1...
  • 璁句簩缁撮殢鏈哄彉閲(x,y)鐨勬鐜瀵嗗害涓篺(x,y) x+y
    绛旓細鍙埄鐢ㄨ仈鍚姒傜巼瀵嗗害鐨勪簩閲嶇Н鍒嗕负1锛屾眰鍑簁=2銆傝竟闄呭瘑搴﹀嚱鏁扮殑姹傝В锛屾湰璐ㄥ氨鏄冨療绉垎锛屽彧瑕佽浣忚竟缂樻鐜囧瘑搴﹀氨鏄鑱斿悎瀵嗗害鍑芥暟姹傜Н鍒嗭紝褰撴垜浠眰鍏充簬Y鐨勮竟闄呭瘑搴﹀嚱鏁版椂灏辨槸瀵逛簬f锛坸锛寉锛夌殑鑱斿悎瀵嗗害鍑芥暟鍏充簬X姹傜Н鍒嗭紝姹俌鐨勮竟闄呭瘑搴﹀嚱鏁板垯鍚岀悊銆傜浜岄儴鍒嗘槸姹闅忔満鍙橀噺鍑芥暟鐨勫瘑搴︼紝涓鑸敤鍒嗗竷鍑芥暟娉曪紝鍗冲厛鐢...
  • 璁句簩缁撮殢鏈哄彉閲(x,y)鐨勬鐜瀵嗗害涓篺(x,y)=k
    绛旓細鍙埄鐢ㄨ仈鍚姒傜巼瀵嗗害鐨勪簩閲嶇Н鍒嗕负1锛屾眰鍑簁=2銆傝竟闄呭瘑搴﹀嚱鏁扮殑姹傝В锛屾湰璐ㄥ氨鏄冨療绉垎锛屽彧瑕佽浣忚竟缂樻鐜囧瘑搴﹀氨鏄鑱斿悎瀵嗗害鍑芥暟姹傜Н鍒嗭紝褰撴垜浠眰鍏充簬Y鐨勮竟闄呭瘑搴﹀嚱鏁版椂灏辨槸瀵逛簬f锛坸锛寉锛夌殑鑱斿悎瀵嗗害鍑芥暟鍏充簬X姹傜Н鍒嗭紝姹俌鐨勮竟闄呭瘑搴﹀嚱鏁板垯鍚岀悊銆傜浜岄儴鍒嗘槸姹闅忔満鍙橀噺鍑芥暟鐨勫瘑搴︼紝涓鑸敤鍒嗗竷鍑芥暟娉曪紝鍗冲厛鐢...
  • 璁句簩缁撮殢鏈哄彉閲(X,Y)鐨勬鐜鍒嗗竷涓 鑻ラ殢鏈轰簨浠秢X=0}涓巤X+Y=1}鐩镐簰鐙珛...
    绛旓細P(X=0)=1/2+b,P(X+Y=1)=a+b,P(X=0,X+Y=1)=b 鈭祘X=0}涓巤X+Y=1}鐩镐簰鐙珛 鈭碢(X=0)路P(X+Y=1)=P(X=0,X+Y=1)鈭(1/2+b)(a+b)=b 鍙堚埖 1/2+1/4+a+b=1 鎵浠ワ細a=1/12 b=1/6
  • 璁句簩缁撮殢鏈哄彉閲(X,Y)鐨勬鐜瀵嗗害涓:f(x,y)=12y^2,0
    绛旓細EX=鈭埆[0<=y<=x<=1] xf(x,y)dxdy=鈭玔0->1]鈭玔0->x] 12xy²dydx=4/5 EY=鈭埆[0<=y<=x<=1] yf(x,y)dxdy=鈭玔0->1]鈭玔0->x] 12y³dydx=3/5 E(X²+Y²)=鈭埆[0<=y<=x<=1] (x²+y²)f(x,y)dxdy=鈭玔0->1]鈭玔0->x...
  • 姒傜巼璁:璁句簩缁撮殢鏈哄彉閲(X,Y)鐨勬鐜瀵嗗害涓
    绛旓細涓嶇x0锛寉0璋佸ぇ璋佸皬锛屾寚鐨勬槸 Y=y0鐩寸嚎浠ヤ笅銆乆=x0鐩寸嚎涔嬪彸鍖哄煙鍐呯殑绉垎锛岃岃繖涓尯鍩熷唴铏界劧 x>y澶勫瘑搴﹀嚱鏁颁负0锛屼絾杩樻槸鏈 x<y鐨勭偣鐨勩備緥濡傦細璁句簩缁撮殢鏈哄彉閲(X,Y)鐨勬鐜瀵嗗害涓 f(x,y)=kx(x-y),0 1)瀵筜浠庯紞X鍒癤绉垎銆瀵筙浠0鍒2绉垎 琚Н鍑芥暟KX(X-Y) 鍋氫簩閲嶇Н鍒嗙瓑浜1 姹傚緱K=8 ...
  • 璁句簩缁撮殢鏈哄彉閲(X,Y)鐨勬鐜瀵嗗害涓篺(x,y)=6x, 0鈮鈮鈮10, 鍏朵粬,鍒橮{...
    绛旓細濡傚彸鍥炬墍绀猴細灏姒傜巼杞寲涓洪潰绉疍涓婄Н鍒嗭紝鐢遍璁撅紝鏈夛細P{X+Y鈮1}=?Df(x锛寉)dxdy鈺愨埆120(6x?12x2)dx锛14锛屾晠绛旀涓猴細14锛
  • 璁句簩缁撮殢鏈哄彉閲(X,Y)鐨勬鐜瀵嗗害涓篺(x,y)=2,0鈮<=0,0鈮鈮,=0,鍏朵粬...
    绛旓細0,1)dx鈭(0,x)(x+y)f(x,y)dy=鈭(0,1)3x²dx=1銆(2)锛孍(XY)=鈭(0,1)dx鈭(0,x)xyf(x,y)dy=鈭(0,1)x³dx=1/4銆(3)锛屸埖x+y=1涓巠=x鐨勪氦鐐逛负(1/2,1/2)銆侾(X+Y鈮1)=鈭(0,1/2)dy鈭(y,1-y)f(x,y)dy=2鈭(0,1/2)锛1-2y)dy=1/2銆
  • 璁句簩缁撮殢鏈哄彉閲(X,Y)鐨勬鐜鍒嗗竷涓 鑻ラ殢鏈轰簨浠秢X=0}涓巤X+Y=1}鐩镐簰鐙珛...
    绛旓細绠鍗曡绠椾竴涓嬪嵆鍙紝绛旀濡傚浘鎵绀
  • 本站交流只代表网友个人观点,与本站立场无关
    欢迎反馈与建议,请联系电邮
    2024© 车视网