怎么用Python中的for循环求1+2+3+…+100的值？ 首先是python语言，有没有人知道怎样用for语句来求1+...
python\u4e2dfor\u8bed\u53e5\u6765\u6c42 1+2+3+\u2026\u2026+100=\uff1fsum=0
for i in range(101):
sum+=i
print(sum)
\u6269\u5c55\u8d44\u6599
Python\u7684\u8bbe\u8ba1\u76ee\u6807\u4e4b\u4e00\u662f\u8ba9\u4ee3\u7801\u5177\u5907\u9ad8\u5ea6\u7684\u53ef\u9605\u8bfb\u6027\u3002\u5b83\u8bbe\u8ba1\u65f6\u5c3d\u91cf\u4f7f\u7528\u5176\u5b83\u8bed\u8a00\u7ecf\u5e38\u4f7f\u7528\u7684\u6807\u70b9\u7b26\u53f7\u548c\u82f1\u6587\u5355\u5b57\uff0c\u8ba9\u4ee3\u7801\u770b\u8d77\u6765\u6574\u6d01\u7f8e\u89c2\u3002\u5b83\u4e0d\u50cf\u5176\u4ed6\u7684\u9759\u6001\u8bed\u8a00\u5982C\u3001Pascal\u90a3\u6837\u9700\u8981\u91cd\u590d\u4e66\u5199\u58f0\u660e\u8bed\u53e5\uff0c\u4e5f\u4e0d\u50cf\u5b83\u4eec\u7684\u8bed\u6cd5\u90a3\u6837\u7ecf\u5e38\u6709\u7279\u6b8a\u60c5\u51b5\u548c\u610f\u5916\u3002
Python\u5f00\u53d1\u8005\u6709\u610f\u8ba9\u8fdd\u53cd\u4e86\u7f29\u8fdb\u89c4\u5219\u7684\u7a0b\u5e8f\u4e0d\u80fd\u901a\u8fc7\u7f16\u8bd1\uff0c\u4ee5\u6b64\u6765\u5f3a\u5236\u7a0b\u5e8f\u5458\u517b\u6210\u826f\u597d\u7684\u7f16\u7a0b\u4e60\u60ef\u3002\u5e76\u4e14Python\u8bed\u8a00\u5229\u7528\u7f29\u8fdb\u8868\u793a\u8bed\u53e5\u5757\u7684\u5f00\u59cb\u548c\u9000\u51fa\uff08Off-side\u89c4\u5219\uff09\uff0c\u800c\u975e\u4f7f\u7528\u82b1\u62ec\u53f7\u6216\u8005\u67d0\u79cd\u5173\u952e\u5b57\u3002\u589e\u52a0\u7f29\u8fdb\u8868\u793a\u8bed\u53e5\u5757\u7684\u5f00\u59cb\uff0c\u800c\u51cf\u5c11\u7f29\u8fdb\u5219\u8868\u793a\u8bed\u53e5\u5757\u7684\u9000\u51fa\u3002\u7f29\u8fdb\u6210\u4e3a\u4e86\u8bed\u6cd5\u7684\u4e00\u90e8\u5206\u3002
\u6709\u4e00\u79cd\u6c42\u6cd5\u662f\uff1asum(range(1,101))\u3002\u5176\u4e2drange(1,101)\u751f\u6210\u4e00\u4e2alist\uff0c\u91cc\u9762\u5b58\u4e861,2,3,...,100\u3002sum\u53ef\u4ee5\u5bf9\u4e00\u4e2alist\u6c42\u548c\u3002
num = 0for i in range(1,101):
num += i
print num
s=0
for i in range(1,101):
s+=i
print(s)
def getsum=(n):
sum=0
for i in range(n):
sum+=(i+1)
return sum
getsum(100)
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