4个电阻相等都是1欧姆,中间接中点,求ab端电阻 每条线段的电阻为1欧姆,求AB间的电阻
4\u4e2a\u7535\u963b\u76f8\u7b49\u90fd\u662f1\u6b27\u59c6\uff0c\u6c42ab\u7aef\u7535\u963b\u8fd9\u662f\u4e00\u4e2a\u53ef\u8c03\u7535\u963b\u554a\uff0c\u4e2d\u95f4\u7684\u4f4d\u7f6e\u662f\u591a\u5c11\uff1f\u662f\u8fd9\u6bcf\u4e2a\u76840.5\u5904\u5417\uff1f\u8fd8\u662f\u3002\u3002\u3002\uff1f
\u8bbeAB\u95f4\u7535\u963b\u4e3aRa\uff0c\u7535\u6d41\u4e3a\u4e0a\u4e0b\u6d41\u52a8
\u5728\u4ee5AB\u4e3a\u8fb9\u7ec4\u6210\u7684\u6b63\u65b9\u5f62\u4e32\u8054\u7535\u8def\u4e2d\u5404\u6761\u7535\u963b\u963b\u503c\u90fd\u662fRa
\u56e0\u4e3a\u8bbe\u7535\u6d41\u4e0a\u4e0b\u6d41\u52a8\uff0c\u5c06\u4e0a\u4e0b\u65b9\u5411\u4e0a\u7684\u7535\u963b\u4e00\u5206\u4e3a\u4e8c\uff08\u5e76\u8054\uff09\uff0c\u6bcf\u4e2a\u963b\u503c\u4e3a2Ra\uff0c\u53d6\u9760\u8fd1AB\u7684\u7535\u963b\uff0c\u5219AB\u4e0a\u65b9\u7684\u7535\u963b\u603b\u503c\u4e3a5Ra\uff0c\u4e0b\u65b9\u7684\u4e5f\u662f5Ra\uff0c\u603b\u51712.5Ra
\u6240\u4ee5\u9664\u4e86\u7ebf\u6bb5AB\u4e0a\u7684\u7535\u963b1\u6b27\u4e4b\u5916AB\u7684\u7535\u963b\u4e3a2.5Ra
\u6839\u636e\u516c\u5f0f\u5f97\u51fa\uff081\u00d72.5Ra)/(1+2.5Ra)=Ra 1.5=2.5Ra
Ra=3/5\u6b27\u59c6
\u6240\u4ee5AB\u95f4\u7684\u963b\u503c\u662f3/5\u6b27\u59c6
R1连接R3的导线相当于将R2以及R1、R3的左半部分短路
实际上这个电路的等效电路为,R1、R3右半部分串联再与R4并联
也就是相当于两个1欧的电阻并联,就是0.5欧
绛旓細锛1锛変覆鑱旂數璺 鍦ㄥ浘1涓紝鍥犱负R1鍜孯2涓茶仈锛屽洜姝ら氳繃瀹冧滑鐨勭數娴鐩稿悓锛璁綬1涓ょ鐢靛帇涓篣1锛R2涓ょ鐢靛帇涓篣2锛屽垯鏈 锛屽浘2涓湁锛氾紝缁煎悎浠ヤ笂鎺ㄥ锛屾湁锛氾紝鍥犳鍙互寰楀埌鏈変覆鑱旂數璺鎬荤數闃鍜屽垎鐢甸樆鐨勫叧绯伙細锛屾帹璁猴細涓茶仈鐢佃矾鐨勬荤數闃绘瘮浠讳綍涓涓垎鐢甸樆閮澶с(2) 骞惰仈鐢佃矾 绛夋晥鐢甸樆鐢佃矾濡傚浘3銆佸浘4鎵绀恒備袱涓浘...
绛旓細鍚岀悊锛屼笌 E 鐩歌繛鐨勪笁鏉℃1鐨勫彟涓変釜椤剁偣涔熸槸绛夌數浣嶇殑銆傜敤涓夋潯杈呭姪绾挎妸閭 3 涓偣杩炴帴璧锋潵鎴愪负鍙涓涓瓑鐢典綅鐐癸紙璁捐繖涓瓑鐢典綅鐐逛负 C锛夈傝繖涓椂鍊 E 鐐逛笌 C 鐐逛篃鍏辨湁 涓涓數闃骞惰仈銆傚垯瀹冧滑涔嬮棿鐨勭瓑鏁堢數闃 Rce = 1/3(惟)銆傝繖涓椂鍊欙紝鍦ㄤ袱涓瓑鐢典綅鐐 B銆丆 涔嬮棿鍏辨湁 6 涓數闃诲苟鑱斻傚垯瀹冧滑涔嬮棿...
绛旓細骞惰仈鐨勬敮璺數娴佷笉鍙樹负I锛岃屽共璺數娴佷负鏀矾鐢垫祦涔嬪拰鍗砃*I锛屾荤數闃讳负鐢靛帇闄や互鐢垫祦锛屾墍浠ヤ负鍗曚釜鐢甸樆鐨 1/N銆傛敮璺澶氭椂锛屽共璺數娴=鍘熸敮璺數娴佸拰+鏂板鏀矾鐢垫祦锛岀數娴佸澶э紝鎵浠ユ荤數闃诲噺灏忋傛煇涓鏀矾鐢甸樆澧炲ぇ锛岃鏀矾鐢垫祦鍑忓皬锛岃屽叾浠栨敮璺數娴佸張涓嶅彉锛屽共璺數娴佷篃鍑忓皬锛屾墍浠ユ荤數闃诲澶с
绛旓細4涓涓茶仈锛40娆у 4涓苟鑱旓細2.5娆у 涓や袱骞惰仈鍚庡啀涓茶仈锛10娆у 3涓苟鑱斿悗鍐嶅悓鍙涓涓覆鑱旓細13.33娆у 3涓覆鑱斿悗鍐嶅悓鍙︿竴涓苟鑱旓細7.5娆у 妤间笂灏戜簡锛1锛涓や釜涓茶仈浠ュ悗鍜屼竴涓苟鑱旓紝鐒跺悗鍐嶄覆鑱斾竴涓锛岀數闃讳负锛16.666娆у 2锛屼袱涓苟鑱旂劧鍚庝覆鑱斾竴涓紝鍐嶅苟鑱斾竴涓紝鐢甸樆涓猴細6 3锛屼袱涓覆鑱斾互鍚庡拰涓...
绛旓細灏嗕笁涓數闃涓茶仈锛岀數璺腑浜х敓鐨勭數娴佹渶灏忥紝鐢垫祦I=U/R=3/(10+10+10)=0.1A锛屽皢涓変釜鐢甸樆骞惰仈锛屽垯绾胯矾涓殑鐢垫祦鏈澶э紝鐢垫祦I=3/锛10/3锛=0.9A
绛旓細2.鑰冩煡骞惰仈鐢佃矾鐨勭數闃 澶嶄範骞惰仈鐢佃矾鐨勬荤數闃诲叕寮 =++鈥︹ 鍥犱负骞惰仈鐢佃矾鐨勭數闃诲叕寮鏄竴涓垎鏁板叕寮,涓嶆槗璁$畻,璁颁綇涓嬮潰鐨勮寰,鍙互甯姪浣犺绠楃數闃 (1)涓涓數闃骞惰仈:R= . (2)n涓鐩稿悓鐨勭數闃籖1骞惰仈;R= . (3)骞惰仈鍚庣殑鎬荤數闃讳竴瀹氬皬浜庡垎鐢甸樆涓渶灏忕殑涓涓. (4)涓や釜鐢甸樆R1銆丷2骞惰仈,褰揜1涓嶅彉,R2澧炲ぇ鏃,鎬荤數闃...
绛旓細涓変釜闃诲鐩哥瓑鐨勭數闃讳覆鑱旀椂鎬荤數闃鐨9鍊嶃備竴銆佺數闃 1銆佸浣撳鐢垫祦鐨勯樆纰嶄綔鐢ㄥ氨鍙瀵间綋鐨勭數闃汇傜數闃伙紙Resistance锛岄氬父鐢ㄢ淩鈥濊〃绀猴級鏄竴涓墿鐞嗛噺锛屽湪鐗╃悊瀛︿腑琛ㄧず瀵间綋瀵圭數娴侀樆纰嶄綔鐢ㄧ殑澶у皬銆2銆佸浣撶殑鐢甸樆瓒婂ぇ锛岃〃绀哄浣撳鐢垫祦鐨勯樆纰嶄綔鐢ㄨ秺澶с備笉鍚岀殑瀵间綋锛岀數闃涓鑸笉鍚岋紝鐢甸樆鏄浣撴湰韬殑涓绉嶆ц川銆傚浣...
绛旓細棣栧厛锛屽湪涓茶仈鐢佃矾涓紝鐢垫祦鏄澶鐩哥瓑鐨勩傝繖鏄洜涓轰覆鑱旂數璺腑锛屾墍鏈夊厓浠堕兘鏄氳繃鍚屼竴鐢垫祦婧愪緵鐢碉紝鍥犳鐢垫祦鍦ㄦ暣涓數璺腑鏄鐩稿悓鐨勩傛牴鎹娆у瀹氬緥锛岀數娴両涓庣數闃籖鎴愬弽姣旓紝鑰岀數鍘媀涓庣數闃籖鎴愭姣斻傚洜姝わ紝鍦ㄤ覆鑱旂數璺腑锛屽鏋涓涓數闃澧炲ぇ锛屽叾涓ょ鐨勭數鍘嬩篃浼氬澶э紝鑰岄氳繃瀹冪殑鐢垫祦鍒欎細鍑忓皬銆傝繖绉嶅叧绯诲彲浠ョ敤鏉ョ悊瑙e拰...
绛旓細鍦ㄩ棴鍚堢數璺腑锛屾煇涓數闃鍙戠敓鍙樺寲浼氬鏁翠釜鐢佃矾浜х敓褰卞搷锛岃屾暣浣撶殑鍙樺寲鍙堝埗绾︾潃灞閮ㄣ傚鐞嗚繖涓绫诲瀷鐨勯鐩椂锛屽繀椤昏娓呭鐢佃矾鐢甸樆鏄嚜鍙橀噺锛屾牴鎹棴鍚堢數璺娆у瀹氬緥锛屽垽鏂數鍘嬨佺數娴佸己搴︾殑鍙樺寲锛庡垎鏋愯В绛旇繖绫讳範棰樼殑涓鑸楠ゆ槸锛氾紙1锛夌‘瀹氬鐢佃矾鐢甸樆R濡備綍鍙樺寲锛屾牴鎹棴鍚堢數璺濮嗗畾寰嬬‘瀹氱數璺殑鎬荤數娴佸浣曞彉鍖栥傦紙2锛...
绛旓細涓や釜鐏场骞惰仈璧锋潵锛屽垯瀹冧滑鐨勭數鍘鐩哥瓑锛鏈澶х數鍘嬪垎鍒涓4*1=4鍜1*2=2锛屾墍浠ュ畠浠厑璁搁氳繃鐨勬渶澶х數鍘嬩负2V 锛2V鐨勭數鍘嬩笅瀹氬鐢甸樆R1閫氳繃鐨勭數娴佷负0.5A锛孯2涓2A锛屾墍浠ュ共璺渶澶х數娴佷笉瓒呰繃0.5+2=2.5A