八年级物理(下)计算题!帮我解解吧? 人教版八年级下册物理计算题(50道)及答案,答案要详细 速度...

\u516b\u5e74\u7ea7\u7269\u7406\u8ba1\u7b97\u9898 \u6c42\u597d\u5fc3\u4eba\u5e2e\u89e3\u4e0b \u5341\u5206\u611f\u8c22\uff01\uff08\u4f1a\u91c7\u7eb3\u7684\uff09

LZ\u60a8\u597d
(1)[\u76f4\u63a5\u5199\u7b54\u6848\u5373\u53ef]
\u58f6\u5634\u6c34\u9762\u8ddd\u79bb\u58f6\u5e95\u8ddd\u79bbh2=h1=8cm,\u91c7\u7528\u7684\u662f\u8fde\u901a\u5668\u539f\u7406
(2)\u5df2\u77e5\u03c1=1X10^3 kg/m^3 g=10N/kg h1=8cm=8X10^-2 m S=10cm^2=10^-3 m^2

\u6c42F
\u89e3P=\u03c1gh=1X10^3 X10X8X10^-2 =800 Pa
F=PS=800X 10^-3 =0.8N

\u7b54:\u5bb9\u5668\u5e95\u90e8\u53d7\u6c34\u538b\u529b0.8N
(3)\u5df2\u77e5m\u6c34=1kg m\u58f6=1kg S=10^-3 m^2 g=10N/kg
\u6c42P
\u89e3 F=G=(m\u6c34+m\u58f6)g=(1+1)X10N=20N
P=F/S=20/10^-3=2X10^4Pa
\u7b54:\u5bb9\u5668\u5e95\u90e8\u5bf9\u684c\u9762\u7684\u538b\u5f3a\u4e3a2X10^4Pa

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1.装有4节干电池的手电筒,小灯泡灯丝电阻是10欧姆,求:手电筒工作时通过灯丝的电流强度时多少安培?
干电池4节,电压U=4*1.5=6V
根据欧姆定律 I=U/R=6伏/10欧=0.6安
2.小明家的用电器工作时的电功率如右表: 电器 功率/w
(1)所有用电器的总功率是多少? 照明电器 200
(2)所有用电器同时工作,家庭 厨房电器 450
电路的总电流时多大? 电视机 100
冰箱 125
洗衣机 225
P=P1+P2+…+Pn=(200+450+100+125+225)瓦=1100瓦
所有用电器工作时 根据P=UI知 I=P/U=1100瓦/220伏=5安
3.一个规格为“220v 880w”的电炉,接在家庭电路中使用10分钟,求:
(1)通过电炉的电流; (2)电炉的电阻; (3)产生的热量。
由P=UI知I=P/U=880瓦/220伏=4安
由欧姆定律知电阻R=U/I=220伏/4安=55欧
热量Q=W=Pt=880瓦*(10*60)秒=52800焦

1.干电池4节,电压U=4*1.5=6V
根据欧姆定律 I=U/R=6伏/10欧=0.6安

2.P=P1+P2+…+Pn=(200+450+100+125+225)瓦=1100瓦
所有用电器工作时 根据P=UI知 I=P/U=1100瓦/220伏=5安

3.由P=UI知I=P/U=880瓦/220伏=4安
由欧姆定律知电阻R=U/I=220伏/4安=55欧
热量Q=W=Pt=880瓦*(10*60)秒=52800焦

楼下的呢别抄我的啊 汗~~

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