C语言填空题
c\u8bed\u8a00\u586b\u7a7a\u98981.p!=person[3]
2.old=p->age
3.q->name,old
\u5f3a\u70c8\u7684\u72af\u7f6a\u611f
\u7b2c\u4e00\u9898
#include
main()
{ char b[]={'0','1','2','3','4','5','6','7','8','9',
'A','B','C','D','E','F',};
int c[64],d,i=0,base;
long n;
printf("enter a number :\n"); scanf("%ld",&n);
printf("enter new base :\n"); scanf("%d",&base);
do
{ c[i]= n%base ;
i++;
n= n/base ;
} while ( n != 0 );
printf("transmite new base:\n");
for (--i;i>=0;--i)
{ d=c[i];
printf("%c",b[d]);
}
printf("\n");
}
\u7b2c\u4e8c\u9898
#include
void main()
{
char s[]="12345678"; int v[4]={0,1,1,0},k,i;
for (k=0; s[k];k++)
{
switch ( s[k] )
{
case'1': i=0;
case'2': i=1;
case'3': i=2;
case'4': i=3;
}
v[i]=s[k]-'0';
}
for(k=0;k<4;k++) printf("%d ", v[k] );
}
\u7b2c\u4e09\u9898
#define N 15
#include
main()
{
int i,n;
float sum,f;
n=0;
sum=0;
printf("please input 15 numbers.\n");
for (i=1; i<=N ;i++)
{
scanf ("%f",&f);
if (f<=0) n-- ;
sum+=f;
n++ ;
}
printf("The sum of positive number is %d,and it's average is %f\n",n, sum/n );
}
0x3a: 00111010
--------------------------
~0x3a: 11000101
0x3a<<2: 11101000
------------------------- 取异或(^)
00101101
即十六进制的0x2d 即八进制 055
0x3A转化成二进制位111010，与~x异或就是111111，再左移两位就是111100，转换成八进制就是74.
运行下面的程序即可:
#include <stdio.h>
int
main( void ){
char x = 0x3a;
printf( "%o", ~x^x<<2 );
return 0;
}
所以结果是37777777455
这个结果是在64位机上得出的,
十六进制：2D
八进制：55
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