3.0g偏二甲肼在O2中充分燃烧后生成4.4gCO2,3.6gH2O,
解4.4g
CO2中
C的质量为
4.4/44×12=1.2g
碳元素的质量分数＝
1.2/3＝40％
3.6gH2O
中
H的质量为
3.6/18*2
=0.4g
1.4gN2中
N的质量为
1.4g
3g
偏二甲肼中
C
1.2g
H
0.4g
N
1.4g
60g偏二甲肼中
C
24
g
H
8
g
N
28
g
化学式
C2H8N2
绛旓細C 2 H 8 N 2 锛1锛鍋忎簩鐢茶偧鏄敱纰炽佹阿銆佹爱涓夌鍏冪礌缁勬垚鐨勫寲鍚堢墿锛2锛夋瘡涓亸浜岀敳鑲煎垎瀛愮敱2涓⒊鍘熷瓙銆8涓阿鍘熷瓙銆2涓爱鍘熷瓙鏋勬垚
绛旓細3.瑙勫畾鍙噧鐗╁畬鍏ㄧ噧鐑х敓鎴愮ǔ瀹氬寲鍚堢墿鎵鏀惧嚭鐨勭儹閲忎负鏍囧噯锛庯紙渚嬪锛欻2S(g)+1/2O2锛坓锛===H20锛坙锛+S鈫; 螖H1锛岀敱浜庣敓鎴愮殑S娌℃湁鐕冪儳瀹屽叏锛屾墍浠ヨ繖涓弽搴旀斁鍑虹殑鐑噺螖H1涓嶈兘浣滀负H2S鐨勭噧鐑х儹锛屽綋H2S(g)+3/2O2锛坓锛===H20锛坙锛+SO2锛坓锛夛紱螖H2锛岃繖鏃舵按鐨勭姸鎬佷负绋冲畾鐨勬恫鎬侊紝鑰屼篃鐢熸垚绋冲畾...
绛旓細鍋忎簩鐢茶偧鐕冪儳鐨勫寲瀛﹀紡浠嬬粛濡備笅锛欳2H8N2+6O2=鐕冪儳=2CO2+4H2O+2NO2銆傚亸浜岀敳鑲肩粨鏋勫紡涓轰负涓涓狽鍘熷瓙杩炵潃涓や釜鐢插熀锛-CH3锛変互鍙婁竴涓皑鍩猴紙-NH2锛夈傚叿浣撶殑缁撴瀯寮忓涓嬪浘鎵绀恒傚亸浜岀敳鑲硷紝鍙堝悕1,1-浜岀敳鍩鸿偧銆1,1-浜岀敳鍩鸿仈姘紝鏄竴绉嶆湁鏈哄寲鍚堢墿锛屽寲瀛﹀紡C2H8N2锛屼负鏃犺壊娑蹭綋锛屾湁鍓ф瘨銆傚亸浜岀敳鑲兼槸瀵煎脊銆...
绛旓細鈶鍋忎簩鐢茶偧涓纰冲厓绱犵殑璐ㄩ噺涓猴細4.4g脳1244=1.2g锛涘亸浜岀敳鑲间腑H鍏冪礌鐨勮川閲忎负锛3.6g脳218=0.4g锛涘亸浜岀敳鑲间腑N鍏冪礌鐨勮川閲忎负锛1.4g锛涘亸浜岀敳鑲间腑姘у厓绱犵殑璐ㄩ噺涓猴細3.0g-1.2g-0.4g-1.4g=0锛涙晠鍋忎簩鐢茶偧鐢盋銆丠銆丯涓夌鍏冪礌缁勬垚锛涒憽鍋忎簩鐢茶偧涓⒊鍏冪礌鐨勮川閲忓垎鏁颁负锛1.2g3.0g脳100%=40%锛涒憿鍋忎簩鐢茶偧涓瑿...
绛旓細(CH3)2NNH2 + O2 == N2 + CO2 + H2O 閰嶅钩锛氱偣鐕 C2N2H8 + 4 O2 === N2 + 2 CO2 + 4 H2O 鏈涢噰绾筹紝璋㈣阿
绛旓細鍥轰綋鎺ㄨ繘鍓侫PCP鐨勪緥瀛愪腑锛屾隘鍖栨阿鐨勫瓨鍦ㄥ鑷村叾姘存憾娑叉垚涓虹洂閰革紝浣嗗鎵炬洿鐜繚鐨勯夋嫨鏄涓氳秼鍔匡紝渚嬪鏃犳按鑲鍜岄珮姘㈢⒊姣旂殑鐢茬兎鐕冩枡銆傛恫姘㈡恫姘х噧鐑т骇鐢熺殑浜х墿鏇村姞绾噣锛屼富瑕佸寘鎷按銆佹阿姘旓紝浠ュ強鏋佸皯閲忕殑姘ф皵銆佽繃姘у寲姘佹阿姘ф牴绂诲瓙锛屼互鍙婂井閲忕殑姘у厓绱犮傚敖绠＄函姘寸噧鐑х殑姒傚康鐪嬩技鐜繚锛屼絾瀹為檯鐏鎺掓斁涓紝鍏跺崰姣旂浉瀵硅緝...
绛旓細鍙堝洜涓鸿鐗╄川鍒嗗瓙涓叾涓湁涓涓爱鍘熷瓙浠ャ 瀛樺湪锛屼笖涓嶄笌H鍘熷瓙鐩存帴鐩歌繛锛屾嵁姝ゅ彲鐭ュ叾缁撴瀯绠寮忔槸 銆傦紙2锛5.00g鈥鍋忎簩鐢茶偧鈥濆畬鍏ㄧ噧鐑ф椂鍙斁鍑212.5kJ鐑噺锛屽垯1mol璇ュ寲鍚堢墿鍙嶅簲鏀惧嚭鐨勭儹閲忔槸 锛屾墍浠ヨ鍙嶅簲鐨勭儹鍖栧鏂圭▼寮忔槸C 2 H 8 N 2 锛坙锛夛紜2N 2 O 4 锛坙锛夛紳2CO 2 锛坓锛夛紜4H 2 O...
绛旓細鏄恫鎬佽仈姘ㄥ拰浜屾哀鍖栨爱锛岀敓鎴愭爱姘斿拰姘磋捀姘旓紝鏄棤姣掔殑锛岀幆淇濈殑
绛旓細鐨勭墿璐ㄧ殑閲忎负1mol锛屽垎瀛愮殑璐ㄩ噺涓1mol脳60g/mol=60 g锛屾晠B姝ｇ‘锛汣.1 mol鍋忎簩鐢茶偧锛圕2H8N2锛 鐨勮川閲忎负60g锛屽亸浜岀敳鑲硷紙C2H8N2锛 鐨勬懇灏旇川閲忎负60 g/mol锛屾晠C閿欒锛汥.6g鍋忎簩鐢茶偧锛圕2H8N2锛 鐨勭墿璐ㄧ殑閲忎负6g60g/mol=0.1mol锛屽惈鏈0.1NA涓亸浜岀敳鑲硷紙C2H8N2锛 鍒嗗瓙锛屾晠D閿欒锛屾晠閫塀锛
绛旓細C2H8N2+2N2O4=2CO2锛堟皵浣擄級+3N2锛堟皵浣擄級+4H2O锛堟皵浣擄級 娉細鍋忎簩鐢茶偧锛圕2H8N2)甯镐綔涓虹伀绠殑鐕冩枡浣跨敤锛屽洓姘у寲浜屾爱锛圢2O4)浣滀负姘у寲鍓傦紝鐕冪儳浜х敓鐨勫法澶ц兘閲忚兘鎶婄伀绠佸叆澶┖
