c语言猜数字游戏编程思路

分析:
先产生一个随机数N。
然后输入数I,如果A大于N,则提示大于信息。
如果I小于N,则提示小于信息。
直到I==N,则输出成功信息。
这是我用C语言写的。
环境:
WIN-C
,TORBO
C,如果是C++环境把倒数第二排getch();删掉!
已经调试成功:
main()
{
int
i=0,n;
srand(time(0));
n=rand()%100+1;
while(i!=n)
{printf("please
input
a
number:\n");scanf("%d",&i);if(i>n)printf("this
number
is
too
big!\n");if(i<n)printf("this
number
is
too
smaller!\n");}
if(i==n)
printf("PASS!%3d",n);
getch();
}
提示:
srand(time(0));
n=rand()%100+1;
是用来生成一个1~100以内的随机数,如果你改,把100改成50或者200。如(n=rand()%50+1;


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