编程题:1:定义含有10个元素的数组,并将数组中的元素按逆序从新存放后输出。 编程题:1:定义含有10个元素的数组,并将数组中的元素按逆序...

\u4e00\u3001\u5efa\u7acb\u4e00\u4e2a10\u4e2a\u5143\u7d20\u7684int\u6570\u7ec4\uff0c 1) \u968f\u673a\u8d4b\u503c 100\u4ee5\u5185\u7684\u6574\u6570 2) \u6309\u964d\u5e8f\u6392\u5e8f 3) \u8f93\u51fa\u6392\u5e8f\u540e\u7684\u6570\u7ec4\u5143\u7d20

#include
#include
#include
int main()
{
int a[10];
int i,j,t;
srand(time(NULL));
for(i = 0; i < 10; i ++)
a[i] = rand()%100;
for(i = 0; i < 9; i ++)
for(j = i+1; j < 10; j ++)
if(a[i]<a[j])
{
t = a[i];
a[i] = a[j];
a[j] = t;
}
for(i = 0; i < 10; i ++)
printf("%d ", a[i]);
}

#include
void main()
{
int i, j, a[10],temp;
for (i = 0; i < 10; i++)
scanf("%d",&a[i]);
printf("\n");
for (i = 0; i < 9; i++)
for (j = i+1; j < 10; j++)
if (a[j]<a[i])
{
temp = a[i];
a[i] = a[j];
a[j] = temp;
}
for (i = 0; i < 10; i++)
printf("%3d",a[i]);
}

#include <stdio.h>
void main()
{
int i, j, a[10],temp;
for (i = 0; i < 10; i++)
scanf("%d",&a[i]);
printf("\n");
for (i = 0,j=9; i< =9&&j>=0; i++,j--)//交换首尾的数,实现逆序存放
{
temp = a[i];
a[i] = a[j];
a[j] = temp;
}
for (i = 0; i < 10; i++)
printf("%3d",a[i]);
}

#include <stdio.h>
void main()
{
int i, j, a[10],temp;
for (i = 0; i < 10; i++)
scanf("%d",&a[i]);
printf("\n");
for (i = 0; i < 9; i++)
for (j = i+1; j < 10; j++)
if (a[j]<a[i])
{
temp = a[i];
a[i] = a[j];
a[j] = temp;
}
for (i = 0; i < 10; i++)
printf("%3d",a[i]);
}

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