关于二进制逆序的java程序,为什么网上说我答案错误?我觉得结果对啊 在java中 我是这样逆序的，请问哪错了
\u6211\u7528C#\u5199\u4e2a\u4e8c\u8fdb\u5236\u6210\u5341\u8fdb\u5236\u7684\u7a0b\u5e8f2^i\u7ed3\u679c\u4e0d\u5bf9\uff01flg=(int)Math.Pow(2,i);
\u6700\u540e\u4e00\u4e2afor\u5faa\u73af\u91cc\u9762\u7684i\u4e0d\u5e94\u8be5\u7b49\u4e8ea.length\uff0c\u8fd9\u6837\u5c31\u6570\u7ec4\u8d8a\u754c\u4e86\uff0c\u6570\u7ec4\u6700\u5927\u7684\u5143\u7d20\u4e0d\u662fa.length\u800c\u662fa.length-1
程序的逻辑不清晰。理清楚了就写好了。
请参考修改的
给你提供个更简便的方法，请参考
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int T = scanner.nextInt();
for(int i = 0; i < T; i++) {
long num = scanner.nextLong();
String str = Long.toBinaryString(num);
int len = str.length();
if(len <= 32) {
for(int j = 32; j > len; j--)
str = "0" + str;
String rev = new StringBuilder(str).reverse().toString();
long out = Long.valueOf(rev, 2).longValue();
System.out.println("Input: " + num + " (Binary: " + str + ")");
System.out.println("Output: " + out + " (Binary: " + rev + ")");
} else {
System.out.println("Overflow");
}
}
scanner.close();
}
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