Java语言，编写一个程序能将用户输入的个任意长度的整数，求出各个位上的数，并逆序输出。 Java中从键盘下输入任意整数，逆序输出其各位数字
java\u7f16\u5199\u4e00\u4e2a\u7a0b\u5e8f\uff0c\u7528\u6237\u8f93\u5165\u4e00\u4e2a\u6b63\u6574\u6570\uff0c\u628a\u5b83\u7684\u5404\u4f4d\u6570\u5b57\u98a0\u5012\u4e00\u4e0b\uff0c\u5e76\u8f93\u51fa\u98a0\u5012\u540e\u7ed3\u679c\u4ee3\u7801\u5982\u4e0b\uff1a
import java.util.Scanner;public class ReverseNumber { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.println("\u8bf7\u8f93\u5165\u4e00\u4e2a\u6574\u6570\uff1a"); int num = scanner.nextInt(); StringBuilder stringBuilder = new StringBuilder(); String reverseStr = stringBuilder.append(num).reverse().toString(); System.out.println(reverseStr); //\u5982\u679c\u60f3\u8981\u6574\u578b\uff0c\u518d\u8f6c\u6362\u4e00\u6b21 int reverseNum = Integer.valueOf(reverseStr);// System.out.println(reverseNum); }}
public static void main(String []args){ Scanner in=new Scanner(System.in); int n=in.nextInt(); while(n!=0){ System.out.print(n%10); n/=10; }}
运行结果：
代码如下:
import java.util.Scanner;
public class App {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.print("请输入一个整数：");
int number = scanner.nextInt();
while (number != 0) {
int x = number % 10;
System.out.print(x + " ");
number /= 10;
}
}
}
import java.io.BufferedInputStream;
import java.util.Scanner;
public class test1 {
public static void main(String[] args) {
Scanner cin = new Scanner(new BufferedInputStream(System.in));
String str = cin.next();
cin.close();
for (int i = str.length() - 1; i >= 0; --i) {
System.out.print(str.charAt(i));
}
System.out.println();
}
}
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