物理爆破题求解！！！
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烧完引火线所用的时间：t=L / v =96cm / 0.8cm/s=120s在这段时间内，引爆手能跑出的距离：S＝vt＝5m/s x 120s＝600m>500m
能跑到安全区
绛旓細宸茬煡锛涘紩绾块暱s1=96cm,v1=0.8cm/s锛寁2=5m/s锛宻2=0.5km 姹傦紱鐏嚎鐕冨畬鐨勬椂闂磘1,鍙婁汉鍦╰1鍐呰窇鐨勮矾绋媠3 瑙;t1=s1/v1=96cm/0.8cm/s =120s s3=t1脳v2=120s脳5m/s=600m s3>s2 绛旓細浠栬兘娲荤潃璺戝埌0.5km杩
绛旓細瑙ｏ細瀵肩伀绱㈢噧鐑у畬鎵鐢ㄧ殑鏃堕棿锛歵=S1/v1=92/0.8=115s 鍦ㄨ繖娈垫椂闂村唴鐐圭伀鑰呰兘璺戝嚭鐨勬渶澶ц窛绂伙細S锛漹t=5m/s x 115s=575m>500m 绛旓細浠栬兘鍦ㄧ垎鐐镐箣鍓嶈窇鍒扮鐖嗙偢鍦扮偣500m鐨勫畨鍏ㄥ尯
绛旓細杩欏嚑骞存潵锛屽箍瑗跨殑灞卞尯鍏矾寤鸿杩呯寷鍙戝睍锛屽湪灞卞尯寮灞变慨璺椂锛岀粡甯哥敤鍒鐖嗙牬鎶鏈傚湪涓娆＄垎鐮翠腑锛屾柦宸ヨ呯敤涓鏉88cm闀跨殑瀵肩伀绾挎潵浣胯鍦ㄩ捇瀛旈噷鐨勭偢鑽垎鐐搞傚鐏嚎鐕冪儳鐨勫钩鍧囬熷害鏄0.8cm/s锛岀偣鐏呯偣鐫瀵肩伀绾夸互鍚庯紝浠5m/s鐨勫钩鍧囬熷害璺戝紑锛屼粬鑳藉湪鐖嗙偢鍓嶈窇鍒拌窛绂荤垎鐐哥偣500m鐨勫畨鍏ㄥ湴鍖哄悧锛熻浣犵敤涓ょ鏂规硶璁＄畻骞...
绛旓細瑙ｏ細0.8m=80cm T=S/V=80cm/2cm/s=40s S=VT=40s*5m/s=200m>180m 鎵浠ヨ兘璺戝埌180m澶栫殑瀹夊叏鍖
绛旓細杩欐槸鐪嬫椂闂寸殑锛100CM/0.8CM/S=125S,杩欐槸鐖嗙偢瑕佺殑鏃堕棿锛500M/5M/S=100S锛岃繖鏄埌瀹夊叏鍖虹殑鏃堕棿锛岀湅鏉ョ偢涓嶆浠
绛旓細1銆佺偢寮逛粠鐐圭噧鍒扮垎鐐搁渶瑕佺殑鏃堕棿涓猴細t=s/v=96cm/0.8cm/s=120s 鍦ㄦ鏃堕棿鐐圭伀鑰呭彲浠ヨ窇寮鐨勮窛绂讳负锛歴`=v`*t=3m/s*120s=360m>100m 鎵浠ユ槸鍙互瀹夊叏璺戝紑鐨勩2銆佽鍓嶄竴鍗婃椂闂翠负t锛屽垯鍏ㄧ▼璺濈涓10km/h*t+15km/h*t=25t 鑰屽叏绋嬫椂闂翠负2t锛屽垯骞冲潎閫熷害涓25t/2t=12.5m/s 3銆佽鍏ㄧ▼涓4L...
绛旓細16cm/0.8cm=20s 20s*5m/s=100m 鑳借窇鍑烘潵锛
绛旓細1.瀵肩伀绱1.2m,閭鐖嗙牬鏃堕棿涓1.2/0.01=120s浜鸿窇鍒500m澶,蹇界暐瀵肩伀绱㈤暱搴,瑕500/5=100s,鎵浠ュ彲浠ュ埌瀹夊叏鍦板甫 2.瀵肩伀绱1.2m,閭ｇ垎鐮存椂闂翠负1.2/0.01=120s,浜鸿窇120s璺120*5=600m>500m鏁呰兘鍒板畨鍏ㄥ湴甯 3.瀵肩伀绱1.2m,閭ｇ垎鐮存椂闂翠负1.2/0.01=120s;瑕佹兂鍒板畨鍏ㄥ湴甯︿汉鐨勯熷害鍒板皯涓500/120=4....
绛旓細鐢ㄤ笁绉嶆柟娉...涓嶈繃閮界粰浣犲垪鍑烘潵鍚.1.鐐歌嵂鐖嗙偢闇瑕佺殑鏃堕棿涓:90/0.6=150s.鍦ㄨ繖娈垫椂闂村唴鐐圭伀鑰呯殑浣嶇Щ涓:150*5=750m>700m.鎵浠ョ偣鐏呰兘鍦ㄧ垎鐐稿墠璺戝埌绂荤垎鐐稿湴鐐700m杩滅殑瀹夊叏鍦板尯.2.鐐圭伀鑰呰窇鍒板畨鍏ㄥ湴鍖洪渶瑕佺殑鏃堕棿涓700/5=140s.鐐歌嵂鐖嗙偢鐨勬椂闂翠负90/0.6=150s>140s,鎵浠ョ偣鐏呰兘鍦ㄧ垎鐐稿墠璺戝埌绂荤垎鐐...
绛旓細F=5*10^5*S(闈㈢Н)V(宀╃煶)=S*L=0.1S m(宀╃煶)=V*瀵嗗害=2700*0.1S 宀╃煶鐖嗙偢鍔犻熷害a=F/m=5*10^6/2700 --- 浣嗘槸杩欓噷鏈変釜闂,鍗崇垎鐐镐笌浜烘墍澶勫湴鏂圭殑鐩稿楂樺害涓庡博鐭抽琛岃搴︾殑闂. 涓嶅悓鐨勯珮搴﹀拰瑙掑害浼氬奖鍝嶅博鐭抽琛岀殑璺濈. 鎴戣涓棰樼洰缂轰箯蹇呰鐨勫亣璁.鑷劧涓嶈兘缁х画璁＄畻涓嬪幓....
