一辆汽车沿平直公路从甲站开往乙站,起动加速度为2m/s2,加速行驶5秒,后匀速行驶2分钟,然后刹车,滑行5

\u4e00\u8f86\u6c7d\u8f66\u6cbf\u5e73\u76f4\u516c\u8def\u4ece\u7532\u7ad9\u51fa\u53d1\u5f00\u5f80\u4e59\u7ad9\uff0c\u8d77\u52a8\u52a0\u901f\u5ea6\u4e3a2m/s2\uff0c\u52a0\u901f\u884c\u9a765\u79d2\uff0c\u540e\u5300\u901f\u884c\u9a762\u5206\u949f\uff0c\u7136\u540e\u5239\u8f66\u505a

\uff081\uff09\u6c7d\u8f66\u505a\u5300\u52a0\u901f\u8fd0\u52a8\u65f6\u7684\u52a0\u901f\u5ea6a=2m/s2\uff0c\u52a0\u901f\u8fd0\u52a8\u7684\u65f6\u95f4\u4e3a5s\uff0c\u5219\u6c7d\u8f66\u5728\u5300\u52a0\u901f\u8fc7\u7a0b\u4e2d\u7684\u4f4d\u79fbx1\uff1d12at2\uff1d12\u00d72\u00d752m\uff1d25m\u6839\u636e\u901f\u5ea6\u65f6\u95f4\u5173\u7cfb\u53ef\u77e5\uff0c\u52a0\u901f5s\u540e\u6c7d\u8f66\u7684\u901f\u5ea6v=at=2\u00d75m/s=10m/s\uff0c\u5219\u6c7d\u8f66\u5728\u5300\u901f\u8fd0\u52a82\u5206\u949f\u65f6\u95f4\u5185\u7684\u4f4d\u79fbx2=vt=10\u00d7120m=1200m\u6c7d\u8f66\u505a\u5300\u51cf\u901f\u8fd0\u52a8\u7684\u4f4d\u79fbx3=50m\u6240\u4ee5\u7532\u4e59\u4e24\u7ad9\u95f4\u7684\u8ddd\u79bbx=x1+x2+x3=25+1200+50m=1275m\uff082\uff09\u6c7d\u8f66\u505a\u5300\u51cf\u901f\u8fd0\u52a8\u7684\u521d\u901f\u5ea6v0=10m/s\uff0c\u672b\u901f\u5ea6v=0\uff0c\u4ea7\u751f\u7684\u4f4d\u79fbx3=50m\u5219\u6839\u636e\u5300\u53d8\u901f\u76f4\u7ebf\u8fd0\u52a8\u7684\u5e73\u5747\u901f\u5ea6\u516c\u5f0f\u77e5\uff0c\u5300\u51cf\u901f\u8fd0\u52a8\u8fc7\u7a0b\u4e2d\u7684\u5e73\u5747\u901f\u5ea6.v3\uff1dv+v02\uff1d0+102m/s\uff1d5m/s\u6240\u4ee5\u5300\u51cf\u901f\u8fd0\u52a8\u8fc7\u7a0b\u65f6\u95f4t3\uff1dx3.v3\uff1d505s\uff1d10s\u6240\u4ee5\u6c7d\u8f66\u4ece\u7532\u81f3\u4e59\u6240\u7528\u65f6\u95f4t=t1+t2+t3=5+120+10s=135s\u5219\u6c7d\u8f66\u4ece\u7532\u5230\u4e59\u7684\u5e73\u5747\u901f\u5ea6.v\uff1dxt\uff1d1275135m/s\u22489.4m/s\u7b54\uff1a\uff081\uff09\u7532\u4e59\u4e24\u7ad9\u4e4b\u95f4\u7684\u8ddd\u79bb\u4e3a1275m\uff0e\uff082\uff09\u6c7d\u8f66\u4ece\u7532\u7ad9\u5230\u4e59\u7ad9\u7684\u5e73\u5747\u901f\u5ea6\u4e3a9.4m/s\uff0e

\u6839\u636ex=v0t+12at2\u5f97\u8d77\u52a8\u9636\u6bb5\u52a0\u901f\u8fd0\u52a8\u901a\u8fc7\u7684\u8ddd\u79bb\u4e3a\uff1ax=12\u00d72\u00d725\uff1d25m\uff0c\u5300\u901f\u8fd0\u52a8\u7684\u901f\u5ea6\u4e3a\uff1av=at=2\u00d75=10m/s\u6545\u7b54\u6848\u4e3a\uff1a25\uff0c10

解答:解:起动阶段行驶位移为:S1=
1
2
at12

匀速行驶的速度为:V=at1
匀速行驶的位移为:S2=Vt2  
刹车段的位移为:S3=
V
2
t3

汽车从甲站到乙站的平均速度为:
V=
S1+S2+S3
t1+t2+t3
25+1200+50
5+120+10
m/s=
1275
135
m/s=9.44m/s

答:汽车从甲站到乙站的平均速度为9.44m/s.

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