X的平方减2x等于-x加2怎么解?
移项ⅹ^2-ⅹ-2=0(ⅹ-2)(ⅹ+1)=0
ⅹ1=-1，ⅹ2=2.
绛旓細x^2-2x=0 x(x-2)=0 x=0鎴杧=2
绛旓細y=x-2x 鐨鍥捐薄鏄釜寮鍙ｅ悜涓婄殑鎶涚墿绾匡紝鍥惧涓嬶細鍙岄挬鍑芥暟鍥惧儚 鍑芥暟f(x)=ax+b/x,(a>0,b>0)鍙仛鍙岄挬鍑芥暟銆傝鍑芥暟鏄鍑芥暟锛屽浘璞″叧浜庡師鐐瑰绉般備綅浜庣涓銆佷笁璞￠檺銆傚綋x>0鏃讹紝鐢卞熀鏈笉绛夊紡鍙緱锛歽 鈮2鈭歛b锛屽綋涓斾粎褰揳x=b/x,鍗硏=鈭(b/a)鏃跺彇绛夊彿銆傛晠鍏堕《鐐瑰潗鏍囦负(鈭(b/a)锛2鈭歛b)锛...
绛旓細瑙ｏ細x²-2x=7 x²-2x+1=7+1 锛坸-1锛²=8 x-1=卤鈭8=卤2鈭2 x=1卤2鈭2 鎵浠ュ師鏂圭▼鐨勪袱涓牴涓 x1=1+2鈭2 x2=1-2鈭2
绛旓細瑙ｏ細杩欎釜鐢ㄥ叕寮忔硶瑙ｆ柟绋嬪氨鍙互浜 x²-2x=4 x²-2x-4=0 a=1 ,b=-2,c=-4 b²-4ac=(-2)²-4脳1脳锛-4锛=20锛0 x= 锛2卤鈭20锛/2=1卤鈭5 鎵浠1=1+鈭5 X2=1-鈭5
绛旓細鏈涓轰竴鍏冧竴娆℃柟绋嬬殑璁＄畻锛岃缁嗚繃绋嬪涓嬶細(x+1)/2-(x+2)/6=1+2x/3,涓よ竟鍚屾椂涔樹互6锛屽彲鏈:3(x+1)-x-2=6+4x,3x+3-x-2=6+4x,2x+1=6+4x,2x-4x=6-1,-2x=5,x=-5/2銆傝缁嗚绠楁楠 姝ら楠岀畻杩囩▼濡備笅锛氬乏杈=(x+1)/2-(x+2)/6=(-5/2+1)/2-(-5/2+2)/6=-3/4+...
绛旓細杩囩▼濡備笅锛歺²-x=2 x²-x-2=0 (x-2)(x+1)=0 x₁=2锛寈₂=-1 鎬ц川 鍙惈鏈変竴涓湭鐭ユ暟锛堜竴鍏冿級锛屽苟涓旀湭鐭ユ暟椤圭殑鏈楂樻鏁版槸2锛浜娆★級鐨勬暣寮忔柟绋嬪彨鍋氫竴鍏冧簩娆℃柟绋嬨備竴鍏冧簩娆℃柟绋嬬粡杩囨暣鐞嗛兘鍙寲鎴愪竴鑸舰寮廰x+bx+c=0锛坅鈮0锛夈傚叾涓璦x鍙綔浜屾椤癸紝a鏄簩娆￠」绯绘暟...
绛旓細灏卞彲浠ョ洿鎺ュ緱鍑猴細X-1=3鎴朮-1=-3锛屽苟杩涜屾眰鍒癤銆傚叾瀹炲畬鍏ㄥ钩鏂瑰叕寮忕殑琛ㄨ堪鏄繖鏍风殑锛歛鍔犱笂b鐨勫拰鐨勫钩鏂瑰氨绛変簬a鐨勫钩鎴垮姞b鐨勫钩鏂癸紝鍐鍔犱笂2鍊嶇殑a涔樹互b锛涜宎鍑忓幓b鐨勫樊鐨勫钩鏂瑰氨绛変簬a鐨勫钩鏂瑰噺b鐨勫钩鏂癸紝鍐鍑忓幓2鍊嶇殑a涔樹互b銆傚叾瀹炶繖閬撻杩樻湁鍙﹀涓绉嶅仛娉曪紝鍙滃崄瀛楃浉涔樻硶鈥濓紝浣嗘槸鍥犱负琛ㄨ堪璧锋潵鐩稿綋鍥伴毦...
绛旓細鍥犱负x^2-2x=2鎵浠(x-1)^2=3鏈夊洜涓猴紙x-1)鐨4娆℃柟=x^4-4x^3+6x^2-4x+3=(x^4-2x^3-2x^2)-2x^3+8x^2-4x+1鎵浠ュ師寮=(x-1)^4+2=(x-1)^2^2+2=3^2+2=11
绛旓細x骞虫柟-x=2 x骞虫柟-x-2=0 锛坸+1锛夛紙x-2锛=0 x=-1鎴杧=2
绛旓細x^2-2x-2=0 瑙ｏ細x^2-2x=2 閰嶆柟寰楋細(x-1)^2=2+1 寮鏂瑰緱锛歺-1=卤鈭3 x-1=鈭3 鎴 x-1=-鈭3 x1=1+鈭3 x2=1-鈭3
