七年级数学幂的运算和解方程计算题 解方程要一元一次方程,o(∩
一元一次方程：1.2(x-2)-3(4x-1)=9(1-x)
2.11x+64-2x=100-9x
3.15-(8-5x)=7x+(4-3x)
4.3(x-7)-2[9-4(2-x)]=22
5.3/2[2/3(1/4x-1)-2]-x=2
6.2(x-2)+2=x+1
7.0.4(x-0.2)+1.5=0.7x-0.38
8.30x-10(10-x)=100
9.4(x+2)=5(x-2)
10.120-4(x+5)=25
11.15x+863-65x=54
12.12.3(x-2)+1=x-(2x-1)
13.11x+64-2x=100-9x
14.14.59+x-25.31=0
15.x-48.32+78.51=80
16.820-16x=45.5×8
17.(x-6)×7=2x
18.3x+x=18
19.0.8+3.2=7.2
20.12.5-3x=6.5
21.1.2(x-0.64)=0.54
22.x+12.5=3.5x
23.8x-22.8=1.2
24.1\ 50x+10=60
25.2\ 60x-30=20
26.3\ 3^20x+50=110
27.4\ 2x=5x-3
28.5\ 90=10+x
29.6\ 90+20x=30
30.7\ 691+3x=700
31 x+5=8
32 3x＋5(138－x) = 540
33 x-5=3
1 2x-10.3x=15
2 0.52x-(1-0.52)x=80
3 x/2+3x/2=7
4 3x+7=32-2x
5 3x+5(138-x)=540
6 3x-7(x-1)=3-2(x+3)
7 18x+3x-3=18-2(2x-1)
8 3(20-y)=6y-4(y-11)
9 -(x/4-1)=5
10 3[4(5y-1)-8]=6
11 2(x-2)+2=x+1
12 2(x-2)-3(4x-1)=9(1-x)
13 x/3 -5 = (5-x)/2
14 2(x+1) /3=5(x+1) /6 -1
15 (1/5)x +1 =(2x+1)/4
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