矩阵相减的一个matlab问题 Matlab中矩阵相减
Matlab\u91cc\u600e\u4e48\u628a\u4e24\u77e9\u9635\u7684\u5bf9\u5e94\u5143\u7d20\u76f8\u51cf\uff1f\u5e76\u6c42\u6240\u5f97\u6240\u6709\u5143\u7d20\u7684\u5e73\u65b9\u548c\uff1f\u5047\u5982\u4e24\u4e2a\u77e9\u9635\u662fA\u548cB
\u5bf9\u5e94\u5143\u7d20\u76f8\u51cf\uff0c\u5b58\u5165C\u4e2d\uff1a
C = A - B;
\u518d\u6c42C\u4e2d\u6240\u6709\u5143\u7d20\u7684\u5e73\u65b9\u548c\uff1a
s = sum(sum(C .^ 2));
4.1 \u6570\u7ec4\u8fd0\u7b97\u548c\u77e9\u9635\u8fd0\u7b97
\u4ece\u5916\u89c2\u5f62\u72b6\u548c\u6570\u636e\u7ed3\u6784\u6765\u770b,\u4e8c\u7ef4\u6570\u7ec4\u548c\u6570\u5b66\u4e2d\u7684\u77e9\u9635\u6ca1\u6709\u533a\u522b.\u4f46\u662f,\u77e9\u9635\u4f5c\u4e3a\u4e00\u79cd\u53d8\u6362\u6216\u6620\u5c04\u7b97\u7b26\u7684\u4f53\u73b0,\u77e9\u9635\u8fd0\u7b97\u6709\u7740\u660e\u786e\u800c\u4e25\u683c\u7684\u6570\u5b66\u89c4\u5219.\u800c\u6570\u7ec4\u8fd0\u7b97\u662fMATLAB\u8f6f\u4ef6\u6240\u5b9a\u4e49\u7684\u89c4\u5219,\u5176\u76ee\u7684\u662f\u4e3a\u4e86\u6570\u636e\u7ba1\u7406\u65b9\u9762,\u64cd\u4f5c\u7b80\u5355,\u6307\u4ee4\u5f62\u5f0f\u81ea\u7136\u548c\u6267\u884c\u8ba1\u7b97\u6709\u6548.\u6240\u4ee5,\u5728\u4f7f\u7528MATLAB\u65f6,\u7279\u522b\u8981\u660e\u786e\u641e\u6e05\u6570\u7ec4\u8fd0\u7b97\u548c\u77e9\u9635\u8fd0\u7b97\u7684\u533a\u522b.\u88684.1.1\u5217\u51fa\u4e86\u4e24\u79cd\u8fd0\u7b97\u6307\u4ee4\u5f62\u5f0f\u7684\u5b9e\u8d28\u5185\u6db5\u7684\u5f02\u540c.
4.1.1 \u6570\u7ec4\u8fd0\u7b97\u548c\u77e9\u9635\u8fd0\u7b97\u6307\u4ee4\u5f62\u5f0f\u548c\u5b9e\u8d28\u5185\u6db5
\u6570\u7ec4\u8fd0\u7b97
\u77e9\u9635\u8fd0\u7b97
\u6307\u4ee4
\u542b\u4e49
\u6307\u4ee4
\u542b\u4e49
A.'
\u975e\u5171\u8f6d\u8f6c\u7f6e
A'
\u5171\u8f6d\u8f6c\u7f6e
A=s
\u628a\u6807\u91cfs\u8d4b\u7ed9\u6570\u7ec4A\u7684\u6bcf\u4e2a\u5143\u7d20
s+B
\u628a\u6807\u91cfs\u5206\u522b\u4e0e\u6570\u7ec4B\u7684\u6bcf\u4e2a\u5143\u7d20\u76f8\u52a0
s-B, B-s
\u6807\u91cfs\u5206\u522b\u4e0e\u6570\u7ec4B\u7684\u5143\u7d20\u4e4b\u5dee
s.*A
\u6807\u91cfs\u5206\u522b\u4e0e\u6570\u7ec4A\u7684\u5143\u7d20\u4e4b\u79ef
s*A
\u6807\u91cfs\u5206\u522b\u4e0e\u77e9\u9635A\u7684\u5143\u7d20\u4e4b\u79ef
s./B, B.\s
\u6807\u91cfs\u5206\u522b\u88ab\u6570\u7ec4B\u7684\u5143\u7d20\u9664
s*inv(B)
\u77e9\u9635B\u7684\u9006\u4e58\u6807\u91cfs
A.^n
\u6570\u7ec4A\u7684\u6bcf\u4e2a\u5143\u7d20\u7684n\u6b21\u65b9
A^n
A\u4e3a\u65b9\u9635\u65f6,\u77e9\u9635A\u7684n\u6b21\u65b9
A+B
\u6570\u7ec4\u5bf9\u5e94\u5143\u7d20\u7684\u76f8\u52a0
A+B
\u77e9\u9635\u76f8\u52a0
A-B
\u6570\u7ec4\u5bf9\u5e94\u5143\u7d20\u7684\u76f8\u51cf
A-B
\u77e9\u9635\u76f8\u51cf
A.*B
\u6570\u7ec4\u5bf9\u5e94\u5143\u7d20\u7684\u76f8\u4e58
A*B
\u5185\u7ef4\u76f8\u540c\u77e9\u9635\u7684\u4e58\u79ef
A./B
A\u7684\u5143\u7d20\u88abB\u7684\u5bf9\u5e94\u5143\u7d20\u9664
A/B
A\u53f3\u9664B
B.\A
\u4e00\u5b9a\u4e0e\u4e0a\u76f8\u540c
B\A
A\u5de6\u9664B(\u4e00\u822c\u4e0e\u53f3\u9664\u4e0d\u540c)
exp(A)
\u4ee5e\u4e3a\u5e95,\u5206\u522b\u4ee5A\u7684\u5143\u7d20\u4e3a\u6307\u6570,\u6c42\u5e42
expm(A)
A\u7684\u77e9\u9635\u6307\u6570\u51fd\u6570
log(A)
\u5bf9A\u7684\u5404\u5143\u7d20\u6c42\u5bf9\u6570
logm(A)
A\u7684\u77e9\u9635\u5bf9\u6570\u51fd\u6570
sqrt(A)
\u5bf9A\u7684\u79ef\u5404\u5143\u7d20\u6c42\u5e73\u65b9\u6839
sqrtm(A)
A\u7684\u77e9\u9635\u5e73\u65b9\u51fd\u6570
50 0 15 20 0 25;
0 15 0 10 20 0;
40 20 10 0 10 25;
25 0 20 10 0 55;
10 25 0 25 55 0]
a =
0 50 0 40 25 10
50 0 15 20 0 25
0 15 0 10 20 0
40 20 10 0 10 25
25 0 20 10 0 55
10 25 0 25 55 0
>> (a==0)
ans =
1 0 1 0 0 0
0 1 0 0 1 0
1 0 1 0 0 1
0 0 0 1 0 0
0 1 0 0 1 0
0 0 1 0 0 1
>> eye(6)
ans =
1 0 0 0 0 0
0 1 0 0 0 0
0 0 1 0 0 0
0 0 0 1 0 0
0 0 0 0 1 0
0 0 0 0 0 1
>> (a==0)-eye(6)
ans =
0 0 1 0 0 0
0 0 0 0 1 0
1 0 0 0 0 1
0 0 0 0 0 0
0 1 0 0 0 0
0 0 1 0 0 0
绛旓細4.1 鏁扮粍杩愮畻鍜鐭╅樀杩愮畻 浠庡瑙傚舰鐘跺拰鏁版嵁缁撴瀯鏉ョ湅,浜岀淮鏁扮粍鍜屾暟瀛︿腑鐨勭煩闃垫病鏈夊尯鍒.浣嗘槸,鐭╅樀浣滀负涓绉嶅彉鎹㈡垨鏄犲皠绠楃鐨勪綋鐜,鐭╅樀杩愮畻鏈夌潃鏄庣‘鑰屼弗鏍肩殑鏁板瑙勫垯.鑰屾暟缁勮繍绠楁槸MATLAB杞欢鎵瀹氫箟鐨勮鍒,鍏剁洰鐨勬槸涓轰簡鏁版嵁绠＄悊鏂归潰,鎿嶄綔绠鍗,鎸囦护褰㈠紡鑷劧鍜屾墽琛岃绠楁湁鏁.鎵浠,鍦ㄤ娇鐢∕ATLAB鏃,鐗瑰埆瑕佹槑纭悶娓呮暟缁...
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