sql取字符串中间的字符串/取字符串‘adfaadsfa’第二到第五个字母 sql 获取字符串的首字母是按什么规则

SQL\u4e2d\uff0c\u53d6\u5b57\u7b26\u4e32\u4ece\u53f3\u8fb9\u7b2c2\u4e2a\u5b57\u7b26\u5230\u5de6\u8fb9\u7684\u6240\u6709\u5b57\u7b26\uff0c\u6c42\u8bed\u53e5\uff1f

SQL\u4e2d\uff0c\u53d6\u5b57\u7b26\u4e32\u4ece\u53f3\u8fb9\u7b2c2\u4e2a\u5b57\u7b26\u5230\u5de6\u8fb9\u7684\u6240\u6709\u5b57\u7b26\u53ef\u4ee5\u53c2\u8003\u4e0b\u9762\u7684\u4ee3\u7801\uff1a
oracle
select substr('\u5b57\u7b26\u4e32',0,Len('\u5b57\u7b26\u4e32')-2) from dual;
Sql Server
select substr('\u5b57\u7b26\u4e32',0,Len('\u5b57\u7b26\u4e32')-2)

\u6269\u5c55\u8d44\u6599\uff1a
sql\u8bed\u53e5
\u66f4\u65b0\uff1aupdate table1 set field1=value1 where \u8303\u56f4
\u67e5\u627e\uff1aselect * from table1 where field1 like \u2019%value1%\u2019 \uff08\u6240\u6709\u5305\u542b\u2018value1\u2019\u8fd9\u4e2a\u6a21\u5f0f\u7684\u5b57\u7b26\u4e32\uff09
\u6392\u5e8f\uff1aselect * from table1 order by field1,field2 [desc]
\u6c42\u548c\uff1aselect sum(field1) as sumvalue from table1
\u53c2\u8003\u8d44\u6599\u6765\u6e90\uff1a\u767e\u5ea6\u767e\u79d1-SQL\u8bed\u53e5\u5927\u5168

\u5982\u679c\u662f\u5728\u4e00\u4e2a\u5b57\u7b26\u4e32\u4e2d\u627e\u51fa\u7b2c\u4e00\u4e2a\u5b57\u6bcd\uff0c\u53ef\u7528REGEXP_INSTR\u51fd\u6570\u6765\u5b9e\u73b0\u3002
\u4f8b\uff1aSELECT REGEXP_INSTR('123Arter','[[:alpha:]]') FROM dual;
\u8fd4\u56de\u7ed3\u679c\u662f4\u3002

用substr('adfaadsfa', 2, 4)函数,substr()是取字符串的子串的函数,2表示从第二个字符开始, 4 表示总共取4个字符。

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