用2.4mol/L的H2SO4溶液配制100mL浓度为0.2mol/L的稀H2SO4，回答下列问题：（1）需用量筒量取2.4mol/L的H2 现用98%的浓H2SO4（密度为1.84g/cm3）来配制5...
\u75282.4mol/L\u7684H 2 SO 4 \u6eb6\u6db2\u914d\u5236100mL\u6d53\u5ea6\u4e3a0.2mol/L\u7684\u7a00H 2 SO 4 \uff0c\u56de\u7b54\u4e0b\u5217\u95ee\u9898\uff1a\uff081\uff09\u9700\u7528\u91cf\u7b52\u91cf\u53d62.4m\uff081\uff09\u6839\u636e\u7a00\u91ca\u5b9a\u5f8b\uff0c\u7a00\u91ca\u524d\u540e\u6eb6\u8d28\u786b\u9178\u7684\u7269\u8d28\u7684\u91cf\u4e0d\u53d8\uff0c\u8bbe\u6d53\u786b\u9178\u7684\u4f53\u79ef\u4e3axmL\uff0c\u6240\u4ee5xmL\u00d72.4mol/L=100mL\u00d70.2mol/L\uff0c\u89e3\u5f97\uff1ax\u22488.3\uff0c\u6240\u4ee5\u5e94\u91cf\u53d6\u7684\u786b\u9178\u4f53\u79ef\u662f8.3mL\uff1b\u6545\u7b54\u6848\u4e3a\uff1a8.3mL\uff1b\uff082\uff09\u914d\u5236\u6b65\u9aa4\u6709\u91cf\u53d6\u3001\u7a00\u91ca\u3001\u79fb\u6db2\u3001\u6d17\u6da4\u3001\u5b9a\u5bb9\u3001\u6447\u5300\u7b49\u64cd\u4f5c\uff0c\u752810mL\u91cf\u7b52\u91cf\u53d6\uff08\u7528\u5230\u80f6\u5934\u6ef4\u7ba1\uff09\u786b\u9178\uff0c\u5728\u70e7\u676f\u4e2d\u7a00\u91ca\uff0c\u5e76\u7528\u73bb\u7483\u68d2\u6405\u62cc\uff0c\u51b7\u5374\u540e\u8f6c\u79fb\u5230100mL\u5bb9\u91cf\u74f6\u4e2d\uff0c\u5e76\u7528\u73bb\u7483\u68d2\u5f15\u6d41\uff0c\u6d17\u6da4\u70e7\u676f\u4e0e\u73bb\u7483\u68d22\uff5e3\u6b21\uff0c\u5e76\u79fb\u5165\u5bb9\u91cf\u74f6\u5185\uff0c\u5f53\u52a0\u6c34\u81f3\u6db2\u9762\u8ddd\u79bb\u523b\u5ea6\u7ebf1\uff5e2cm\u65f6\uff0c\u6539\u7528\u80f6\u5934\u6ef4\u7ba1\u6ef4\u52a0\uff0c\u76d6\u597d\u74f6\u585e\uff0c\u53cd\u590d\u98a0\u5012\u6447\u5300\uff0c\u6545\u64cd\u4f5c\u987a\u5e8f\u4e3aCAFDBEG\uff1b\u6545\u7b54\u6848\u4e3a\uff1a\u80f6\u5934\u6ef4\u7ba1\uff0c100mL\u5bb9\u91cf\u74f6\uff0cCAFDBEG\uff1b\uff083\uff09\u767d\u8272\u6c89\u6dc0\u662f\u786b\u9178\u94a1\uff0c\u786b\u9178\u94a1\u7684\u7269\u8d28\u7684\u91cf\u4e3a 0.48g 233g/mol = 0.48 233 mol\uff0c\u6240\u4ee5n\uff08H 2 SO 4 \uff09=n\uff08BaSO 4 \uff09= 0.48 233 mol\uff0c\u6545\u6240\u914d\u786b\u9178\u6eb6\u6db2\u7684\u6d53\u5ea6\u4e3a 0.48 233 mol 0.01L =0.21mol/L\uff1e0.2mol/L\uff1bA\uff0e\u5b9a\u5bb9\u65f6\u4fef\u89c6\u5bb9\u91cf\u74f6\uff0c\u6240\u914d\u6eb6\u6db2\u4f53\u79ef\u504f\u5c0f\uff0c\u914d\u5236\u4eba\u4e00\u6837\u7684\u6d53\u5ea6\u504f\u5927\uff0c\u6545A\u7b26\u5408\uff1bB\uff0e\u7528\u91cf\u7b52\u53d62.4mol/LH 2 SO 4 \u6eb6\u6db2\u65f6\u4fef\u89c6\u8bfb\u6570\uff0c\u91cf\u53d6\u786b\u9178\u6eb6\u6db2\u7684\u4f53\u79ef\u504f\u5c0f\uff0c\u6240\u914d\u6eb6\u6db2\u7684\u6d53\u5ea6\u504f\u5c0f\uff0c\u6545B\u4e0d\u7b26\u5408\uff1bC\uff0e\u914d\u5236\u9700\u52a0\u6c34\u5b9a\u5bb9\uff0c\u4f7f\u7528\u5bb9\u91cf\u74f6\u524d\u672a\u5e72\u71e5\uff0c\u5bf9\u6240\u914d\u6eb6\u6db2\u6d53\u5ea6\u65e0\u5f71\u54cd\uff0c\u6545C\u4e0d\u7b26\u5408\uff1bD\uff0e\u4f7f\u7528\u7684\u70e7\u676f\u548c\u73bb\u7483\u68d2\u672a\u6d17\u6da4\u5f7b\u5e95\uff0c\u79fb\u5165\u5bb9\u91cf\u74f6\u5185\u6eb6\u8d28\u786b\u9178\u7684\u7269\u8d28\u7684\u91cf\u504f\u5c0f\uff0c\u6240\u914d\u6eb6\u6db2\u6d53\u5ea6\u504f\u5c0f\uff0c\u6545D\u4e0d\u7b26\u5408\uff1bE\uff0e\u5b9a\u5bb9\u65f6\u5c06\u84b8\u998f\u6c34\u6d12\u5728\u5bb9\u91cf\u74f6\u5916\u9762\uff0c\u53ef\u4ee5\u7ee7\u7eed\u52a0\u6c34\uff0c\u5bf9\u6240\u914d\u6eb6\u6db2\u6d53\u5ea6\u65e0\u5f71\u54cd\uff0c\u6545E\u4e0d\u7b26\u5408\uff1b\u6545\u7b54\u6848\u4e3a\uff1a\u5927\u4e8e\uff0cA\uff0e
\uff081\uff09\u6d53H2SO4\u7684\u7269\u8d28\u7684\u91cf\u6d53\u5ea6c=1000\u00d71.84\u00d798%98mol/L=18.4mol/L\uff0c\u6839\u636e\u7a00\u91ca\u5b9a\u5f8b\uff0c\u7a00\u91ca\u524d\u540e\u6eb6\u8d28\u7684\u7269\u8d28\u7684\u91cf\u4e0d\u53d8\uff0c\u6765\u8ba1\u7b97\u6d53\u786b\u9178\u7684\u4f53\u79ef\uff0c\u8bbe\u6d53\u786b\u9178\u7684\u4f53\u79ef\u4e3axmL\uff0c\u6240\u4ee5xmL\u00d718.4mol/L=500mL\u00d70.2mol/L\uff0c\u89e3\u5f97\uff1ax\u22485.4\uff0c\u6240\u4ee5\u5e94\u91cf\u53d6\u7684\u6d53\u786b\u9178\u4f53\u79ef\u662f5.4mL\uff0e\u6545\u7b54\u6848\u4e3a\uff1a5.4mL\uff0e \uff082\uff09\u914d\u5236\u6b65\u9aa4\u6709\u91cf\u53d6\u3001\u7a00\u91ca\u3001\u79fb\u6db2\u3001\u6d17\u6da4\u3001\u5b9a\u5bb9\u3001\u6447\u5300\u7b49\u64cd\u4f5c\uff0c\u752810mL\u91cf\u7b52\u91cf\u53d6\uff08\u7528\u5230\u80f6\u5934\u6ef4\u7ba1\uff09\u79f0\u91cf\uff0c\u5728\u70e7\u676f\u4e2d\u7a00\u91ca\uff0c\u5e76\u7528\u73bb\u7483\u68d2\u6405\u62cc\uff0c\u51b7\u5374\u540e\u8f6c\u79fb\u5230500mL\u5bb9\u91cf\u74f6\u4e2d\uff0c\u5e76\u7528\u73bb\u7483\u68d2\u5f15\u6d41\uff0c\u5f53\u52a0\u6c34\u81f3\u6db2\u9762\u8ddd\u79bb\u523b\u5ea6\u7ebf1\uff5e2cm\u65f6\uff0c\u6539\u7528\u80f6\u5934\u6ef4\u7ba1\u6ef4\u52a0\uff0c\u4f7f\u7528\u4eea\u5668\u7684\u5148\u540e\u987a\u5e8f\u6392\u5217\u662f\u2461\u2465\u2462\u2466\u2464\u2465\u6545\u9009\uff1aD\uff0e\uff083\uff09\u6d53\u786b\u9178\u7a00\u91ca\u64cd\u4f5c\u4e3a\uff1a\u5c06\u6d53\u786b\u9178\u6cbf\u70e7\u676f\u58c1\u6162\u6162\u52a0\u5165\u88c5\u6709\u6c34\u7684\u70e7\u676f\u4e2d\uff0c\u5e76\u7528\u73bb\u7483\u68d2\u6405\u62cc\uff0e \u6545\u7b54\u6848\u4e3a\uff1a\u5c06\u6d53\u786b\u9178\u6cbf\u70e7\u676f\u58c1\u6162\u6162\u52a0\u5165\u88c5\u6709\u6c34\u7684\u70e7\u676f\u4e2d\uff0c\u5e76\u7528\u73bb\u7483\u68d2\u6405\u62cc\uff0e \uff084\uff09A\uff0e\u7528\u91cf\u7b52\u91cf\u53d6\u6d53\u786b\u9178\u65f6\uff0c\u4ef0\u89c6\u91cf\u7b52\u7684\u523b\u5ea6\uff0c\u6d53\u786b\u9178\u7684\u4f53\u79ef\u504f\u5927\uff0c\u6545\u6eb6\u6db2\u6d53\u5ea6\u504f\u5927\uff1bB\uff0e\u6700\u540e\u9700\u8981\u5b9a\u5bb9\uff0c\u5bb9\u91cf\u74f6\u4e0d\u5e72\u71e5\uff0c\u542b\u6709\u5c11\u91cf\u84b8\u998f\u6c34\uff0c\u5bf9\u6eb6\u6db2\u6d53\u5ea6\u65e0\u5f71\u54cd\uff1bC\uff0e\u6eb6\u6db2\u5177\u6709\u70ed\u80c0\u51b7\u7f29\u7684\u6027\u8d28\uff0c\u6d53\u786b\u9178\u7a00\u91ca\u653e\u51fa\u5927\u91cf\u70ed\uff0c\u672a\u51b7\u5374\u5230\u5ba4\u6e29\uff0c\u8d81\u70ed\u5c06\u6eb6\u6db2\u5230\u5165\u5bb9\u91cf\u74f6\uff0c\u5e76\u914d\u6210\u4e86\u6eb6\u6db2\uff0c\u4f1a\u5bfc\u81f4\u6eb6\u6db2\u4f53\u79ef\u504f\u5c0f\uff0c\u6eb6\u6db2\u6d53\u5ea6\u504f\u5927\uff1bD\uff0e\u5f80\u5bb9\u91cf\u74f6\u8f6c\u79fb\u65f6\uff0c\u6709\u5c11\u91cf\u6db2\u4f53\u6e85\u51fa\uff0c\u5bfc\u81f4\u786b\u9178\u7684\u7269\u8d28\u7684\u91cf\u51cf\u5c0f\uff0c\u6eb6\u6db2\u6d53\u5ea6\u504f\u4f4e\uff1bE\uff0e\u70e7\u676f\u672a\u8fdb\u884c\u6d17\u6da4\uff0c\u5c11\u91cf\u786b\u9178\u6cbe\u5728\u70e7\u676f\u58c1\u4e0e\u73bb\u7483\u68d2\u4e0a\uff0c\u786b\u9178\u7684\u5b9e\u9645\u7269\u8d28\u7684\u91cf\u51cf\u5c0f\uff0c\u6eb6\u6db2\u6d53\u5ea6\u504f\u4f4e\uff1bF\uff0e\u5728\u5bb9\u91cf\u74f6\u4e2d\u5b9a\u5bb9\u65f6\u4fef\u89c6\u5bb9\u91cf\u74f6\u523b\u5ea6\u7ebf\uff0c\u4f7f\u6eb6\u6db2\u7684\u4f53\u79ef\u504f\u4f4e\uff0c\u6240\u4ee5\u6eb6\u6db2\u6d53\u5ea6\u504f\u5927\uff1bG\uff0e\u6447\u5300\u540e\u6db2\u9762\u4e0b\u964d\uff0c\u4e00\u90e8\u5206\u6eb6\u6db2\u7559\u5728\u74f6\u585e\u4e0e\u74f6\u53e3\u4e4b\u95f4\uff0c\u518d\u52a0\u84b8\u998f\u6c34\u81f3\u523b\u5ea6\u7ebf\uff0c\u5bfc\u81f4\u6eb6\u6db2\u4f53\u79ef\u504f\u5927\uff0c\u6240\u4ee5\u6eb6\u6db2\u6d53\u5ea6\u504f\u4f4e\uff0e\u504f\u5927\u7684\u662f ACF\uff1b\u504f\u4f4e\u7684\u662fDEG\uff1b\u6ca1\u6709\u5f71\u54cd\u7684\u662fB\uff0e\u6545\u9009\uff1aACF
（1）根据稀释定律，稀释前后溶质硫酸的物质的量不变，设浓硫酸的体积为xmL，所以xmL×2.4mol/L=100mL×0.2mol/L，解得：x≈8.3，所以应量取的硫酸体积是8.3mL；故答案为：8.3mL；
（2）配制步骤有量取、稀释、移液、洗涤、定容、摇匀等操作，用10mL量筒量取（用到胶头滴管）硫酸，在烧杯中稀释，并用玻璃棒搅拌，冷却后转移到100mL容量瓶中，并用玻璃棒引流，洗涤烧杯与玻璃棒2～3次，并移入容量瓶内，当加水至液面距离刻度线1～2cm时，改用胶头滴管滴加，盖好瓶塞，反复颠倒摇匀，故操作顺序为CAFDBEG；
故答案为：胶头滴管，100mL容量瓶，CAFDBEG；
（3）白色沉淀是硫酸钡，硫酸钡的物质的量为
| 0.48g |
| 233g/mol |
| 0.48 |
| 233 |
| 0.48 |
| 233 |
| ||
| 0.01L |
A．定容时俯视容量瓶，所配溶液体积偏小，配制人一样的浓度偏大，故A符合；
B．用量筒取2.4mol/LH2SO4溶液时俯视读数，量取硫酸溶液的体积偏小，所配溶液的浓度偏小，故B不符合；
C．配制需加水定容，使用容量瓶前未干燥，对所配溶液浓度无影响，故C不符合；
D．使用的烧杯和玻璃棒未洗涤彻底，移入容量瓶内溶质硫酸的物质的量偏小，所配溶液浓度偏小，故D不符合；
E．定容时将蒸馏水洒在容量瓶外面，可以继续加水，对所配溶液浓度无影响，故E不符合；
故答案为：大于，A．
绛旓細鏁呯瓟妗堜负锛8.3mL銆傦紙2锛夐厤鍒舵楠ゆ湁閲忓彇銆佺█閲娿佺Щ娑层佹礂娑ゃ佸畾瀹广佹憞鍖绛夋搷浣滐紝鐢10mL閲忕瓛閲忓彇锛堢敤鍒拌兌澶存淮绠★級纭吀锛屽湪鐑ф澂涓█閲婏紝骞剁敤鐜荤拑妫掓悈鎷岋紝鍐峰嵈鍚庤浆绉诲埌100mL瀹归噺鐡朵腑锛屽苟鐢ㄧ幓鐠冩寮曟祦锛屾礂娑ょ儳鏉笌鐜荤拑妫2锝3娆★紝骞剁Щ鍏ュ閲忕摱鍐咃紝褰撳姞姘磋嚦娑查潰璺濈鍒诲害绾1锝2cm鏃讹紝鏀圭敤鑳跺ご婊寸婊村姞锛...
绛旓細鍥犱负n閰=1.8*2=3.6mol 浜х敓鐨凥2涔熸槸7.2/2=3.6mol 鍙鏄竴姣斾竴鐨勶紝鎵浠ユ槸浜屽厓閰 鐒跺悗閲戝睘鏄2.4mol 閲戝睘鍜岄吀鐨勬瘮渚嬫槸2姣3锛岃璇ラ噾灞炰负M 鎵浠ユ柟绋嬪紡涓2M+3H2__==...鎵浠ユ槸涓変环閲戝睘浜屽厓閰
绛旓細1銆佸亣璁捐閰嶅埗2.5mol/l鐨勭洂閰镐竴鍗囥2銆佸厛璁＄畻闇瑕佹隘鍖栨阿鐨勮川閲忊斺36.5*2.5=91.25鍏3銆佸啀璁＄畻鍘熸潗鏂欙紙鐜板湪鐩愰吀锛夌殑閲忥細X鈥斺91.25闄や互鍘熸潗鏂欑殑璐ㄩ噺鍒嗘暟4銆佸啀璁＄畻鎵闇婧跺墏鈥斺旀按鐨勮川閲;Y鈥斺1000-X5銆佹寜姝ゆ瘮渚嬮厤鍒跺嵆鍙
绛旓細杩欒〃鏄1L鐨勶紙婧舵恫锛燂級涓惈鏈2.4渭mol鐨勶紙婧惰川锛燂級澶囨敞锛氬叾涓1渭mol=1脳10^锛-9锛塵ol
绛旓細(1)0.8mol A,1.2mol B,1.2mol C,2.4mol D (2)1.4mol A,2.1mol B,0.6mol C,1.2mol D 杈惧埌骞宠 鍚,C鐨勮川閲忓垎鏁扮浉鍚,鍒檟鐨勫间负( ) A. 1 B. 2 C. 3 D. 4 瑙ｆ瀽:鍥犱负鍦ㄧ瓑娓┿佺瓑瀹逛笅骞宠 鏃,C鐨勮川閲忓垎鏁扮浉鍚,鍒欏睘浜庡悓涓骞宠 鐘舵,鍙樺寲鐨凙銆丅銆丆銆丏鐨勭墿璐ㄧ殑閲忎箣姣斾负:0.6鈭0.9鈭0.6鈭1.2=2鈭...
绛旓細鐢℉2琛ㄧず鐨勫弽搴旈熺巼涓0.12mol/(L路s)锛10s鍚嶩2鍙嶅簲浜0.12*10*2 = 2.4mol 閭ｄ箞锛孨2鍙嶅簲浜2.4/3=0.8 mol 鍒欙紝浣欎笅鐨凬2鐨勭墿璐ㄧ殑閲忔槸4-0.8=3.2mol 閫塀
绛旓細鍏堝亣璁綞鍙嶅簲浜2xmol,鐢ㄤ笁姝ヨ绠 2M + N == 2E 璧峰 0 0 2 鍙嶅簲 2x x 2x 骞宠 2x x 2-2x 渚濋鐩彲寰楀钩琛℃椂姘斾綋鎬婚噺涓 2*(1+20%)=2.4mol 鏍规嵁绛夋晥骞宠 ,鍏呭叆2mol M鍜1molN鐨勬贩鍚堟皵浣撳弽搴斿钩琛℃椂姘斾綋鐨勯噺涔熶负2.4mol 2M + N == 2E 璧峰...
绛旓細绛旓細銆愩戦厤鍒50ml娴撳害涓2.4鎽╂瘡鍗囩殑纭吀閾 [Al2锛圫O4锛3 ] 婧舵恫锛岄渶瑕佺～閰搁摑澶氬皯鍏 锛= 2.4 mol/L x50 m l/(1000ml/L)x 342 g/mol = 41.04 g 銆愩戞憾娑蹭腑纭吀鏍圭瀛愬拰閾濈瀛愮殑鐗╄川鐨勯噺鐨勬祿搴︼紵=3:2
绛旓細瑙ｏ細璁2min鏈笁姘у寲纭殑鐗╄川鐨勯噺涓篨 鍙嶅簲鐨勪簩姘у寲纭殑鐗╄川鐨勯噺涓4mol-1.6mol=2.4mol 2SO2+O2锕=锕2SO3 2 2 2.4mol X X=2.4mol 2min鏈笁姘у寲纭殑娴撳害=2.4mol/2L=1.2mol/L 鍙嶅簲鐨勪簩姘у寲纭殑娴撳害2.4mol/2L=1.2mol/L 2min鍐呬簩姘у寲纭殑骞冲潎鍙嶅簲閫熺巼1.2mol/L梅2min=0.6mo...
绛旓細鍙互鐢ㄦ瀬闄愭硶銆傦紙1锛夊彲浠ュ厛鍋囪鍙嶅簲鏄叏閮ㄧ敱SO3寮濮嬬殑銆傚洜涓篠O2锛孫2锛孲O3鐨勬祿搴﹀垎鍒槸锛2mol/L 0.8mol/L 2.4mol/L锛屾墍浠ュ鏋淥2鍏ㄩ儴鍙樺洖SO3锛屽垯瑕佷粠0.8鍙樺洖0锛屾鏃惰娑堣0.16mol/LSO2锛岃繖鏃跺欏氨鍗虫槸SO2锛孫2锛孲O3鐨勬祿搴﹀垎鍒槸0.4锛0锛4mol/L 浜嗐傛墍浠O2鍦ㄥ弽搴旇捣濮嬫祿搴﹁嚦灏戜负0.4....
