cost=1/2(e^jt e^-jt) 求函数f(t)=costsint的傅氏变换

\u590d\u53d8\u51fd\u6570\u9898\uff0c\uff0c\u6c42f(t)=sintcost\u7684\u5085\u91cc\u53f6\u53d8\u6362

sintcost=1/2sin2t
F(1/2sin2t)
=\u222b(-\u221e\uff0c+\u221e) 1/2sin2t \u00b7 e^-jwt dt
\u7528\u6b27\u62c9\u516c\u5f0f\u53ef\u5f97\u539f\u5f0f=
1/2\u222b(-\u221e\uff0c+\u221e) j/2( e^-2jt - e^2jt )e^-jwt dt
=j/4\u222b(-\u221e\uff0c+\u221e) e^-j(w+2)t - e^-j(w-2)t dt
\u7528\u03b4\u51fd\u6570\u7684\u5085\u6c0f\u53d8\u6362 \u5f97\u539f\u5f0f=
j/2 \u03c0[\u03b4(w+2)-\u03b4(w-2)]
\u6b27\u62c9\u516c\u5f0f: sin2t=j/2 (e^-2jt - e^2jt)
\u03b4\u51fd\u6570\u7684\u5085\u6c0f\u53d8\u6362:
F(e^jw\u3002t)=\u222b(-\u221e\uff0c+\u221e) e^j(w\u3002-w)t dt =2\u03c0\u03b4(w\u3002-w)
\u6269\u5c55\u8d44\u6599\u5e38\u7528\u5bfc\u6570\u516c\u5f0f\uff1a
1.y=c(c\u4e3a\u5e38\u6570) y'=0
2.y=x^n y'=nx^(n-1)
3.y=a^x y'=a^xlna\uff0cy=e^x y'=e^x
4.y=logax y'=logae/x\uff0cy=lnx y'=1/x
5.y=sinx y'=cosx
6.y=cosx y'=-sinx
7.y=tanx y'=1/cos^2x
8.y=cotx y'=-1/sin^2x
9.y=arcsinx y'=1/\u221a1-x^2
10.y=arccosx y'=-1/\u221a1-x^2
11.y=arctanx y'=1/1+x^2
12.y=arccotx y'=-1/1+x^2

sintcost=1/2sin2t
F(1/2sin2t)
=\u222b(-\u221e\uff0c+\u221e) 1/2sin2t \u00b7 e^-jwt dt
\u7528\u6b27\u62c9\u516c\u5f0f\u53ef\u5f97\u539f\u5f0f=
1/2\u222b(-\u221e\uff0c+\u221e) j/2( e^-2jt - e^2jt )e^-jwt dt
=j/4\u222b(-\u221e\uff0c+\u221e) e^-j(w+2)t - e^-j(w-2)t dt
\u7528\u03b4\u51fd\u6570\u7684\u5085\u6c0f\u53d8\u6362 \u5f97\u539f\u5f0f=
j/2 \u03c0[\u03b4(w+2)-\u03b4(w-2)]
\u6b27\u62c9\u516c\u5f0f: sin2t=j/2 (e^-2jt - e^2jt)
\u03b4\u51fd\u6570\u7684\u5085\u6c0f\u53d8\u6362:
F(e^jw\u3002t)=\u222b(-\u221e\uff0c+\u221e) e^j(w\u3002-w)t dt =2\u03c0\u03b4(w\u3002-w)
\u6269\u5c55\u8d44\u6599\uff1a
\u5085\u6c0f\u53d8\u6362\u7684\u610f\u4e49
\u5085\u91cc\u53f6\u539f\u7406\u8868\u660e\uff1a\u4efb\u4f55\u8fde\u7eed\u6d4b\u91cf\u7684\u65f6\u5e8f\u6216\u4fe1\u53f7\uff0c\u90fd\u53ef\u4ee5\u8868\u793a\u4e3a\u4e0d\u540c\u9891\u7387\u7684\u6b63\u5f26\u6ce2\u4fe1\u53f7\u7684\u65e0\u9650\u53e0\u52a0\u3002
\u800c\u6839\u636e\u8be5\u539f\u7406\u521b\u7acb\u7684\u5085\u91cc\u53f6\u53d8\u6362\u7b97\u6cd5\u5229\u7528\u76f4\u63a5\u6d4b\u91cf\u5230\u7684\u539f\u59cb\u4fe1\u53f7\uff0c\u4ee5\u7d2f\u52a0\u65b9\u5f0f\u6765\u8ba1\u7b97\u8be5\u4fe1\u53f7\u4e2d\u4e0d\u540c\u6b63\u5f26\u6ce2\u4fe1\u53f7\u7684\u9891\u7387\u3001\u632f\u5e45\u548c\u76f8\u4f4d\u3002
\u548c\u5085\u91cc\u53f6\u53d8\u6362\u7b97\u6cd5\u5bf9\u5e94\u7684\u662f\u53cd\u5085\u91cc\u53f6\u53d8\u6362\u7b97\u6cd5\u3002\u8be5\u53cd\u53d8\u6362\u4ece\u672c\u8d28\u4e0a\u8bf4\u4e5f\u662f\u4e00\u79cd\u7d2f\u52a0\u5904\u7406\uff0c\u8fd9\u6837\u5c31\u53ef\u4ee5\u5c06\u5355\u72ec\u6539\u53d8\u7684\u6b63\u5f26\u6ce2\u4fe1\u53f7\u8f6c\u6362\u6210\u4e00\u4e2a\u4fe1\u53f7\u3002
\u56e0\u6b64\uff0c\u53ef\u4ee5\u8bf4\uff0c\u5085\u91cc\u53f6\u53d8\u6362\u5c06\u539f\u6765\u96be\u4ee5\u5904\u7406\u7684\u65f6\u57df\u4fe1\u53f7\u8f6c\u6362\u6210\u4e86\u6613\u4e8e\u5206\u6790\u7684\u9891\u57df\u4fe1\u53f7\uff08\u4fe1\u53f7\u7684\u9891\u8c31\uff09\uff0c\u53ef\u4ee5\u5229\u7528\u4e00\u4e9b\u5de5\u5177\u5bf9\u8fd9\u4e9b\u9891\u57df\u4fe1\u53f7\u8fdb\u884c\u5904\u7406\u3001\u52a0\u5de5\u3002\u6700\u540e\u8fd8\u53ef\u4ee5\u5229\u7528\u5085\u91cc\u53f6\u53cd\u53d8\u6362\u5c06\u8fd9\u4e9b\u9891\u57df\u4fe1\u53f7\u8f6c\u6362\u6210\u65f6\u57df\u4fe1\u53f7\u3002
\u53c2\u8003\u8d44\u6599\u6765\u6e90\uff1a\u767e\u5ea6\u767e\u79d1-\u5085\u91cc\u53f6\u53d8\u6362

由欧拉公式:
e^(ix) = cost + i sint
e^(- ix) = cost - isint
相加e^(ix) + e^(- ix) = 2cost
得出cost = [ e^(ix) + e^(- ix) ]/2

  • 姹俢os(x鈭2)鐨勪笉瀹氱Н鍒
    绛旓細姹傚緱鍑烘潵鐨勶紝鍏堝皢cosx灞曞紑鎴恱鐨勫箓绾ф暟寰楋紝cosx=1-x^2/2锛+x^4/4锛+...+(-1)^n*x^(2n)/(2n)锛+... (1)浠=x^2锛宑os(x^2)=cost=1-t^2/2锛+t^4/4锛+... (2)灏唗=x^2浠e叆鍎(2)寮忎腑锛屽緱 cos(x^2)=1-x^4/2锛+x^8/4锛+...+(-1)^n*x^(4n)/(2n)锛
  • cost鐨勫洓娆℃柟鍔爏int鐨勫洓娆℃柟涓轰粈涔堢瓑浜2sint鐨勫钩鏂瑰噺1
    绛旓細鍥犱负cost=1-sint锛屼唬鍏ュ睍寮灏辨槸銆俕鍙嶈繃鏉ラ獙璇佷竴涓嬩究鐭ヤ笉鎴愮珛 鈭(cost)^2 d(sint)^2 = 鈭(cost)^2(2sintcost)dt = 鈭2sint(cost)^3dt 鈮 鈭(cost)^4 dt ^鈭 (sint)^4路(cost)^2 dt 锛濃埆(sint)^2路1/4路(sin(2t))^2dt 锛1/8鈭(1-cos(2t))(sin(2t))^2dt 锛1/8鈭(...
  • 宸茬煡鍑芥暟f(x)=sin(wx+蠁)鐨勫浘璞′笌鐩寸嚎y=b(-1<b<0)涓変釜鐩搁偦浜ょ偣鐨勬í鍧愭爣...
    绛旓細2蟺/3)x=t 鍒欙紝g(t)=cos2t+cost =(2cos^2 t-1)+cost =2cos^2 t+cost-1 =2[cos^2 t+(1/2)cost+(1/16)]-(9/8)=2[cost+(1/4)]^2-(9/8)鍥犱负cost鈭圼-1,1]鎵浠ワ紝g(t)鏈夋渶灏忓-9/8 褰cost=1鏃讹紝g(t)=2*(25/16)-(9/8)=2 鎵浠ワ紝g(x)鈭圼-9/8,2]...
  • 姹 鏇茬嚎 x^2+z^2=10 y^2+z^2=10 鍦ㄧ偣M(1,1.3) 澶勭殑鍒囩嚎 鍜 娉曞钩闈㈡柟 ...
    绛旓細鍏抽敭鏄妸鏇茬嚎鏂圭▼鍐欐垚鍙傛暟鏂圭▼褰㈠紡锛寈=鈭10cost y=鈭10cost z=鈭10sint M(1,1,3)瀵瑰簲鐨 t 婊¤冻锛氣垰10cost=1锛屸垰10sint=3 娉曞悜閲忎负锛(x',y',z')=(-鈭10sint锛-鈭10sint锛屸垰10cost)=(-3锛-3锛1)鍥犳鍒囩嚎涓猴細(x-1)/-3=(y-1)/-3=z-3 娉曞钩闈細-3(x-1)-3(y-1)+(z-...
  • 鈭(xe^arctanx)/(1+x²)^3/2dx绛変簬澶氬皯
    绛旓細鈭 sint*e^tdt=e^t(sint-cost)/2+C 瑙i杩囩▼濡備笅锛氳x=tant,t=arctanx,dx=(sect)^2dt cost=1/鈭(1+x^2),sint=x/鈭(1+x^2)鍘熷紡=鈭 tant*e^t*(sect)^2dt/([1+(tant)^2]^(3/2)=鈭 tant*e^t*(sect)^2dt/(sect)^3 =鈭 sint*e^tdt =e^t(sint-cost)/2+C =e...
  • 姹倄^3/(1+x^8)^2鐨勪笉瀹氱Н鍒,鐭ラ亾鐨勫憡璇涓涓,瑕佽繃绋,璋㈣阿浜
    绛旓細鍘熷紡=锛1/4锛夆埆d(x^4)/[1+(x^4)^2]^2 璁緐=x^4 鍘熷紡=锛1/4锛夆埆du/(1+u^2)^2 璁緐=tant,du =(sect)^2dt sect=鈭(1+u^2)cost=1/鈭(1+u^2)sint=u/鈭(1+u^2)鍘熷紡=锛1/4锛夆埆锛坰ect)^2dt/(sect)^4 =(1/4)鈭(cost)^2dt =(1/8)(1+cos2t)dt =t/8+(1...
  • take涓cost鏈変粈涔堝尯鍒?
    绛旓細1銆cost锛歯. 浠烽挶锛屼唬浠凤紱鑺辫垂锛岃垂鐢紱鐗虹壊锛涜瘔璁艰垂锛泇i. 浠烽挶涓猴紝鑺辫垂锛涗及璁℃垚鏈紱vt. 浠樺嚭浠d环锛涗及浠凤紱浣夸抚澶憋紱浣夸粯鍑哄姫鍔涖2銆併乼ake锛歷t. 閲囧彇锛涙嬁锛屽彇锛涙帴鍙楋紙绀肩墿绛夛級锛涜楄垂锛堟椂闂寸瓑锛夛紱vi. 鎷匡紱鑾峰緱锛沶. 闀滃ご锛涚湅娉曪紱鏀跺叆棰濓紱鍦烘櫙銆備簩銆佷娇鐢ㄧ敤娉曚笉鍚岋細1銆乧ost 鐨勪富...
  • x^2/1+x^2鐨勪笉瀹氱Н鍒嗘庝箞姹
    绛旓細璁 x=tant锛宒x=(sect)^2dt t=arctanx锛1+x^2=(sect)^2锛cost=1/鈭氾紙1+x^2)sint=x/鈭氾紙1+x^2)sin2t=2sintcost=2x/(1+x^2)鍘熷紡=鈭(tant)^2(sect)^2dt/*(sect)^4 =鈭(sint)^2*(cost)^2dt/(cost)^2 =鈭紙sint)^2dt =(1/2)鈭紙1-cos2t)dt =t/2-(1/4)sin2...
  • [cost sin(2t)]未(t)=1 涓轰粈涔
    绛旓細棰樼洰搴旇鏄痆cost+sin(2t)]未(t)=1鍚с傛牴鎹啿婵鍑芥暟涓庢櫘閫氬嚱鏁扮殑涔樼Н鐨勬ц川锛歠(t)未(t)=f(0)未(t)銆俒cost+sin(2t)]未(t)=[cos(0)+sin(0)]未(t)=[1+0]未(t)=1
  • cost鍜宼ake鐨勭敤娉曞尯鍒槸浠涔?
    绛旓細cost鍜宼ake鐨勭敤娉曞尯鍒湪浜庯細cost涓鑸寚鏌愮墿鑺辫垂浜嗕汉澶氬皯閲戦挶鎴栬呮椂闂达紱take涓鑸寚鑺辫垂浜哄灏戞椂闂村幓鍋氭煇浜嬨備竴銆佽闊充笉鍚 cost 鑻盵kɒst]缇嶽kɔːst]take 鑻盵teɪk]缇嶽teɪk]浜屻侀噴涔変笉鍚 cost n. 璐圭敤; 鑺辫垂; 浠烽挶; 鎴愭湰; (涓哄仛鏌愪簨娑夊強鐨)鍔姏锛屼唬浠凤紝鎹熷け;...
  • 扩展阅读:mac蜜桃奶茶314 ... e人e本a2 ... 17173.com ... www.sony.com.cn ... 日本资生堂色谱柱 ... e人e本t8s ... www.vivo.com ... c c++ c# ... cbi ...

    本站交流只代表网友个人观点,与本站立场无关
    欢迎反馈与建议,请联系电邮
    2024© 车视网