如何用C语言编写一个程序,输入任意输入一个正整数,反序输出每一位 编程,c语言中通过函数调用从键盘上任意输入一个正整数的反序数...

C\u8bed\u8a00\u7f16\u5199\u7a0b\u5e8f :\u8f93\u5165\u4e00\u4e2a\u6b63\u6574\u6570\uff0c\u5c06\u5176\u9006\u5e8f\u8f93\u51fa\u3002\u4f8b\u5982\uff0c\u8f93\u516512345\uff0c\u8f93\u51fa54321. \u8dea\u6c42\u5927\u795e\u7528\u5faa\u73af\u8bed\u53e5

#include
int main()
{
int num;
scanf("%d",&num);
int a,i;
for(i = 0;num > 0;i++)
{
a = num % 10;
printf("%d",a);
num = num/10;
}
return 0;
}

\u5206\u6790\uff1a\u9996\u5148\uff0c\u8f93\u5165\u7684\u662f\u4e00\u4e2a\u6574\u6570\uff0c\u56e0\u6b64\u6700\u524d\u9762\u4e00\u4f4d\u6570\u4e0d\u662f\u96f6\uff0c\u6240\u4ee5\u6211\u4eec\u53ef\u4ee5\u7528\u966410\u53d6\u4f59\u6cd5\u5199\u3002
a = num % 10
\u5c31\u662f\u8f93\u51fa\u6570\u5b57\u7684\u6700\u540e\u4e00\u4f4d
\u7136\u540e\u966410\u5254\u9664\u6570\u5b57\u6700\u540e\u4e00\u4f4d\uff0c\u8fd9\u6837\u6570\u5b57\u5012\u6570\u7b2c\u4e8c\u4f4d\u5c31\u4f1a\u8f93\u51fa\u3002\u4ee5\u6b64\u7c7b\u63a8\uff0c\u5c31\u80fd\u9006\u5e8f\u8f93\u51fa\u6570\u5b57\u3002
\u62d3\u5c55\u8d44\u6599
for\u5faa\u73af\u662f\u7f16\u7a0b\u8bed\u8a00\u4e2d\u4e00\u79cd\u5f00\u754c\u7684\u5faa\u73af\u8bed\u53e5\uff0c\u800c\u5faa\u73af\u8bed\u53e5\u7531\u5faa\u73af\u4f53\u53ca\u5faa\u73af\u7684\u7ec8\u6b62\u6761\u4ef6\u4e24\u90e8\u5206\u7ec4\u6210\uff0cfor\u5faa\u73af\u5176\u5728\u5404\u79cd\u7f16\u7a0b\u8bed\u8a00\u4e2d\u7684\u5b9e\u73b0\u4e0e\u8868\u8fbe\u6709\u6240\u51fa\u5165\uff0c\u4f46\u57fa\u672c\u4e3a\u4ee5C\u8bed\u8a00\u548cpascal\u8bed\u8a00\u4ee3\u8868\u7684\u4e24\u79cd\u5f62\u5f0f\u3002
C\u8bed\u8a00\u4e2d\u7684for\u5faa\u73af\u5982\u4e0b
1.\u8bed\u53e5\u6700\u7b80\u5f62\u5f0f\u4e3a\uff1a
for( ; ; )
2.\u4e00\u822c\u5f62\u5f0f\u4e3a\uff1a
for\uff08\u5355\u6b21\u8868\u8fbe\u5f0f;\u6761\u4ef6\u8868\u8fbe\u5f0f;\u672b\u5c3e\u5faa\u73af\u4f53\uff09
{
\u4e2d\u95f4\u5faa\u73af\u4f53\uff1b
}

#include
int fan(int n);
void main(){
int n;
printf("\u8bf7\u8f93\u5165\u4e00\u4e2a\u4e09\u4f4d\u6570\u4ee5\u5185\u7684\u6b63\u6574\u6570\uff1a");
scanf("%d", &n);
n = fan(n);
printf("%d\n", n);
}
int fan(int n) {
int x, y, z;
if (n <= 9)
return n;
else if (n >= 10 && n <= 99) {
x = n / 10;
y = n - 10 * x;
z = 10 * y + x;
return z;
}
else {
x = n / 100;
y = (n - 100 * x) / 10;
z = n - 100 * x - 10 * y;
n = 100 * z + 10 * y + x;
return n;
}
}

\u62b1\u6b49\u56fe\u7247\u4e0a\u6ca1\u770b\u5230\u7528\u51fd\u6570\u6765\u5b8c\u6210\uff0c\u4ee3\u7801\u662f\u5bf9\u7684\uff0c\u56fe\u7247\u662f\u4e0d\u7528\u51fd\u6570\u7684\u5f62\u5f0f\u3002

#include <stdio.h>
int main()
{
int n;
scanf("%d", &n);
do
{
printf("%d", n % 10);
}while(n /= 10);
printf("\n");
return 0;
}

#include<iostream>
using namespace std;
void print(int n)
{
int t=n,sum=0;
while(t!=0)
{
sum*=10;
sum+=t%10;
t/=10;
}
cout<<sum<<endl;
}
int main()
{
int n;
cout<<"输入你想转换的数:"<<endl;
while(cin>>n)
{
print(n);
}
return 0;
}

#include<stdio.h>
#include<math.h>
void main()
{
int n;
scanf("%d",&n);
int i=0;//表示数字的长度。
while(pow(10.0,(double)i)<=n)
{
i++;
}
for(int j=0;j<i;j++)
{
printf("%d\n",(n/(int)pow(10.0,(double)j))%10);
}
}

#include<iostream>
#include<string>
#include<cstring>
using namespace std;

void main ()
{
string s;
cout<<"输入数字:"<<endl;
cin>>s;
for (int i=strlen(s)-1;i>=0;i--)
cout<<s[i]<<' ';
}

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