这个方程组如何用matlab求结果，未知数为x，c，R为常数。
\u5982\u4f55\u7528matlab\u89e34\u4e2a\u672a\u77e5\u6570\u7684\u6307\u6570\u65b9\u7a0b\u7ec4syms a b c
A = solve('0.0009=a+b*(1-exp(-10*c)', '0.0015=a+b*(1-exp(-100000*c))', '0.003=a+b*(1-exp(-100000000*c))','a','b','c')
\u4f60\u628asolve\uff08\uff09\u62ec\u53f7\u5185\u5355\u5f15\u53f7\u548c\u7b49\u53f7\u53bb\u6389\uff0c\u628a\u7b49\u5f0f\u6539\u4e3a\u7b97\u5f0f\uff0c\u5982'(t1-t)*c=sqrt((x1-x)^2+(y1-y)^2)'\uff0c\u6539\u4e3a (t1-t)*c-sqrt((x1-x)^2+(y1-y)^2)\uff0c\u8fd9\u6837\u53ef\u4ee5\u5f97\u5230\u5177\u4f53\u7684\u6570\u503c\u3002
>> R=40.1924;syms x c real
f=sqrt(R^2-x^2*(sin(c+0.31319*pi))^2)-sqrt(R^2-x^2*(sin(c))^2)+0.003;
g=sqrt(R^2-x^2*(sin(c+0.45996*pi))^2)-sqrt(R^2-x^2*(sin(c))^2)+0.005;
[x,c]=solve(f,g,'x','c')
x =
0.66122909582222451712899448050802
c =
62.701883760084846728852163405302
绛旓細濡備笅锛歩nclude<stdio.h> include<math.h> disc=b*b-4*a*c;p=-b/(2.0*a);q=sqrt(disc)/(2.0*a);x1=p+q;x2=p-q;printf("x1=%7.2f\nx2=%7.2f\n",x1,x2);return 0銆
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绛旓細L0 = 2500;R = 200;length = 100;h2 = 350;h1 = h2+250;L2 = (L0-R+length)/2;syms L1 L3 ex1 = L3+sqrt(L1^2-R^2)-H+h1;ex2 = sqrt(L1^2-(L3+R)^2)-H+h1+h2;[L1,L3] = solve(ex1,ex2,'L1,L3');L1 = double(L1)L3 = double(L3)L1 = 1.0e+003 1.6249...
绛旓細syms x1 x2 x2=solve('sin(x1)=2*sin(x2)','x2');y=-0.15*cos(x1)+0.3*cos(x2)ezplot(y,[0 pi])
