c++代码:在n个数中,求两个最小的数。(第一小,第二小) 怎样在c++中实现:输入n个数,找到其中最小的数和最大的数?

C++\u4e2d\u600e\u4e48\u627e\u51fa\u4e00\u7ef4\u6570\u7ec4\u4e2d\u6700\u5c0f\u7684\u4e24\u4e2a\u6570

\u3000\u3000\u53ef\u4ee5\u5148\u6392\u5e8f\u518d\u8f93\u51fa\u6700\u5c0f\u7684\u4e24\u4e2a\u6570
\u3000\u3000\u4e5f\u53ef\u4ee5\u91c7\u7528\u4e0b\u9762\u7684\u65b9\u6cd5\uff0c\u4e0d\u7528\u6392\u5e8f\u76f4\u63a5\u7ed9\u51fa\u6700\u5c0f\u7684\u4e24\u4e2a\u6570
\u3000\u3000\u601d\u8def\uff1a\u6570\u7ec4\u4e2d\u6570\u548c\u4e24\u4e2a\u6570\u4f9d\u5e8f\u6bd4\u8f83\uff0c\u6bd4\u8fd9\u4e24\u4e2a\u4e2d\u7684\u4e00\u4e2a\u5c0f\uff0c\u5219\u4e0e\u5176\u4ea4\u6362
void getmin(int array[],int arraylen,int out[],int outlen){//outlen\u5e94\u8be5\u4e3a2 int i,j; for(i=0;i<outlen;i++)out[i] = 0x7FFFFFFF;//\u8fd9\u662f\u4e00\u4e2a\u6700\u5927\u6574\u6570\u503c for(i=0;i<arraylen;i++){//\u904d\u5386\u6570\u7ec4 for(j=0;j<outlen;j++){//\u904d\u5386\u6700\u5c0f\u6570\u5217\u8868 if(array[i]<out[j]){//array\u4e2d\u7684\u6570\u66f4\u5c0f out[j] = array[i];//\u8bb0\u5f55\u8be5\u6570 break; } //\u5982\u679cout\u4e2d\u7684\u6570\u5c0f\uff0c\u5219\u770b\u770b\u4e0b\u4e00\u4e2aout\u6570\u4f1a\u4e0d\u4f1a\u6bd4\u8fd9\u4e2a\u5927 } }}\u3000\u3000\u8fd9\u4e2a\u65b9\u6cd5\u53ef\u4ee5\u9002\u7528\u4e8e\u67e5\u627e\u4e00\u7ef4\u6570\u7ec4\u4e2d\u6700\u5c0f\u7684n\u4e2a\u6570

\u3000\u53ef\u4ee5\u5148\u6392\u5e8f\uff0c\u518d\u8f93\u51fa
#include#include using namespace std;int main(){cout>N;cout>a[i];sort(a,a+N);cout<<"The biggest number is "<<a[N-1]<<endl;cout<<"The smallest number is "<<a[0]<<endl;return 0;}\u7ed3\u679c\u5982\u4e0b

\u4e0a\u9762\u662f\u4e3a\u4e86\u5927\u5bb6\u7c98\u8d34\u4ee3\u7801\u65b9\u4fbf\uff0c\u4e0b\u9762\u6211\u662f\u4ee3\u7801\u548c\u7ed3\u679c\u4e00\u8d77\uff0c\u6211\u8fd9\u8fb9\u786e\u5b9e\u662f\u53ef\u4ee5\u8fd0\u884c

由于你给的细节不够,我只能当着这样写了。(当输入的数中有两个最小的数的时候,第二小的数=第一小的数) 可以直接复制过去编译。(我写的这个是可以你任意的输入N个数比较的,更灵活,别的都是固定死的)
#include "stdafx.h"
#include <iostream>
using namespace std;
int _tmain(int argc, _TCHAR* argv[])
{
cout<<"请输入你要比较的数的个数n:"<<endl;
int n;
cin>>n;
cout<<"请输入你要比较的"<<n<<"个数:"<<endl;
int *a=new int[n];
for (int i=0;i<n;i++)
{
cin>>a[i];
}
int Min_F,Min_S;
if (a[0]>a[1])
{
Min_F=a[1];
Min_S=a[0];
}
else Min_F=a[0],Min_S=a[1];
for (int j=2;j<n;j++)
{
if (a[j]<=Min_F)
{
Min_S=Min_F;
Min_F=a[j];
}
else if (Min_F<a[j]&&Min_S>=a[j])
{
Min_S=a[j];
}

}
cout<<"第一小数为:"<<Min_F<<endl;
cout<<"第二小数为:"<<Min_S<<endl;
delete []a;
}

#include <iostream.h>
#define N 10000

void main(){
int s[N];
int m1,m2,n,i;
cout<<"输入要输入的数字个数n>=2:";
cin>>n;
for(i=0;i<n;i++)
cin>>s[i];
if(s[0]<s[1]){
m1 = s[0];
m2 = s[1];
}else{
m2 = s[0];
m1 = s[1];
}
for(i = 2; i < n; i++){
if(s[i] <= m2){
if(s[i]<m1){
m2 = m1;
m1 = s[i];
}else{
m2=s[i];
}
}
}
cout<<"最小:"<<m1<<'\n'<<"第二小:"<<m2<<'\n';
}

#include<iostream>
using namespace std;

int main()
{
int a[] = {12,5,8,3,9,23};
int first,second,i;
first = a[0];
second = a[0];
for ( i=1;i<6;i++)
{
if (a[i] < second)
{
if (a[i] < first)
{
second = first;
first = a[i];
}
else second = a[i];
}
}
cout<<"最小的数:"<<first<<",第二小的数:"<<second<<endl;
return 0;
}
也可以用排序的,然后输出两个最小的数

#include "stdio.h"
#define N 10
void main()
{
int a[] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9};
int min1 = 100;
int min2 = 100;
for (int i = 0; i < N; i++)
{
if (a[i] < min1)
{
min1 = a[i];
}
if (a[i] < min2 && a[i] > min1)
{
min2 = a[i];
}
}
printf("%d%d",min1,min2);
}

#include"iostream"
using namespace std;
class min
{
public:
float a[n];
void input()
{
scanf("%d",&n);
int i;
for(i=0;i<n;i++)
scanf("%f",a[i]);
for(i=0;i<n;i++)
printf("输入的数据:",a[i]);
}
private:
int i,n;
};
void min::compare()
{
int min1,min2;
int i;
if(a[0]<a[1]){
min1 =a[0];
min2 =a[1];
}else{
min2 = a[0];
min1 = a[1];
}
for(i = 2; i < n; i++){
if(a[i] <= min2){
if(a[i]<min1){
min2 = min1;
min1 = a[i];
}else
min2=a[i];
}
cout<<"第一个:"<<min1<<"第二个:"<<min2<<endl;
}
void main()
{
min T;
T.input();
T.compare();
}

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