用C语言做出空心菱形 用c语言怎样打出菱形和空心菱形

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1\u3001\u9996\u5148\uff0c\u8f93\u5165\u9884\u5904\u7406\u6307\u4ee4#include \u4e0e\u51fd\u6570\u539f\u578bvoid print(int n)\u3002\u5176\u4e2d\uff0cn\u8868\u793a\u884c\u6570\u3002

2\u3001\u7136\u540e\uff0c\u5bf9\u8f93\u5165\u7684n\u8fdb\u884c\u63d0\u524d\u5224\u65ad\uff0c\u82e5\u5c0f\u4e8e0\u6216\u4e3a\u5076\u6570\uff0c\u5219\u7ed3\u675f\u6253\u5370\u3002

3\u3001\u63a5\u7740\u5bf9\u4e0a\u534a\u4e2a\u83f1\u5f62\u8fdb\u884c\u8f93\u51fa(\u5305\u62ec\u6700\u957f\u7684\u884c)\u3002\u4f7f\u7528\u4e24\u5c42\u5faa\u73af\u8fdb\u884c\u8f93\u51fa\uff0c\u5206\u522b\u63a7\u5236\u884c\u6570\u4e0e\u884c\u5185\u7684\u4f4d\u7f6e\u3002

4\u3001\u63a5\u7740\u5bf9\u4e0b\u534a\u4e2a\u83f1\u5f62\u8fdb\u884c\u8f93\u51fa(\u5305\u62ec\u6700\u957f\u7684\u884c)\u3002\u4e5f\u4f7f\u7528\u4e24\u5c42\u5faa\u73af\u8fdb\u884c\u8f93\u51fa\uff0c\u5206\u522b\u63a7\u5236\u884c\u6570\u4e0e\u884c\u5185\u7684\u4f4d\u7f6e\u3002

5\u3001\u5bf9n=5\u4e0en=7\u8fdb\u884c\u8f93\u51fa\u6d4b\u8bd5\u3002

6\u3001\u5f97\u5230\u6700\u540e\u7ed3\u679c\u3002

\u5148\u627e\u89c4\u5f8b
\u6bcf\u884c\u7a7a\u683c\u7684\u4e2a\u6570
*\u7684\u4e2a\u6570
\u7136\u540e\u5faa\u73af\u6253\u5370
\u6bd4\u5982\u83f1\u5f62
\u5982\u679c\u9ad8\u5ea6\u4e3an
\u90a3\u4e48 \u6bcf\u884c\u7a7a\u683c\u7684\u4e2a\u6570\u4f9d\u6b21\u4e3an-1 n-2 ... 0
*\u4e2a\u6570\u4e3a1 3 5 7 ... 2*n+1
\u6253\u5370\u4e0a\u534a\u90e8\u4e4b\u540e \u518d\u540c\u7406\u6253\u5370\u4e0b\u534a\u90e8\u3002

\u800c\u7a7a\u5fc3\u83f1\u5f62\uff0c\u5219\u662f\u591a\u4e00\u6b65\u8ba1\u7b97\uff0c\u4e2d\u95f4\u7684\u7a7a\u683c\u6570\u3002\u7a0d\u590d\u6742\u4e00\u70b9\u70b9\u800c\u5df2\u3002

这是你要的图形:
#include<stdio.h>
int main()
{ int a=0,b=0,c=0;
for(a=1;a<=4;a++)
{ for(b=1;b<=5-a;b++) printf(" ");
for(c=1;c<=2*a-1;c++)
{ if(c==1||c==2*a-1) printf("*");
else printf(" ");
}
printf("\n");
}
for(a=1;a<=3;a++)
{ for(b=1;b<=a+1;b++) printf(" ");
for(c=1;c<=7-2*a;c++)
{ if(c==1||c==7-2*a)printf("*");
else printf(" ");
}
printf("\n");
}
getch();
return 0;
}
这是输入行数画出图形。
#include<stdio.h>
int main()
{ int a=0,b=0,c=0,d=0;
scanf("%d",&d);
for(a=1;a<=d/2+1;a++)
{ for(b=1;b<=d/2+2-a;b++) printf(" ");
for(c=1;c<=2*a-1;c++)
{ if(c==1||c==2*a-1) printf("*");
else printf(" ");
}
printf("\n");
}
a=0,b=0,c=0;
for(a=1;a<=d/2;a++)
{ for(b=1;b<=a+1;b++) printf(" ");
for(c=1;c<=d-2*a;c++)
{ if(c==1||c==d-2*a)printf("*");
else printf(" ");
}
printf("\n");
}
getch();

return 0;
}

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