python怎么输入一个数组矩阵? python如何输入二维数组

python:\u5b9a\u4e49\u51fd\u6570,\u8f93\u5165\u4e00\u4e2am\u7ef4\u6570\u7ec4X\u548c\u4e00\u4e2a\u6574\u6570n,\u8f93\u51fa\u4e00\u4e2an*m\u7684\u77e9\u9635M,\u5176\u4e2d M[i] [j]=

# Python3.6import numpy as npwhile True: x = input("\u8f93\u5165\u4e00\u4e2am\u7ef4\u6570\u7ec4,\u5143\u7d20\u4ee5\u7a7a\u683c\u5206\u5f00\uff1a") try: # split input x = x.split() s = [] # iterate:str-->int for i in x: s.append(int(i)) x = s break except: print("\u8f93\u5165\u6709\u9519\uff0c\u8bf7\u91cd\u65b0\u8f93\u5165\u3002")while True: n = input("\u6574\u6570n\uff1a") try: n = int(n) break except: print("\u8f93\u5165\u6709\u9519\uff0c\u8bf7\u91cd\u65b0\u8f93\u5165\u3002")# map object -->list objectlst = [i for i in x]# list object -->numpy.array objectmtrx = np.array(lst)# copy the 1st line of matrix as a templatemtrx_1 = np.copy(mtrx)k = len(mtrx)# reshape (k,) to (1,k) for concatenatemtrx = np.reshape(mtrx, (1, k))# calculate left linesfor i in range(1, n): tmp = np.power(mtrx_1, i+1) tmp = np.reshape(tmp, (1, k)) mtrx = np.concatenate((mtrx, tmp), axis=0)print(mtrx)

\u4e5f\u80fd\u8f93\u5165\u5427\uff0c\u7528eval\u5904\u7406\u4e00\u4e0b\u3002
# -*- coding: utf8 -*-arrayString = input('\u8f93\u5165\u4e00\u4e2a\u4e8c\u7ef4\u6570\u7ec4:')array = eval(arrayString)print(array)\u8f93\u5165\u4e00\u4e2a\u4e8c\u7ef4\u6570\u7ec4:[[1,2],[3,4]][[1, 2], [3, 4]]

下面是基于python3.4的数组矩阵输入方法:

1.import numpy as np
2.arr = [1,2,3,4,5,6,7,8,9]
3.matrix_a = np.array(arr)2.
4.手动定义一个空数组:arr =[],链表数组:a = [1,2,[1,2,3]]。  



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