cos(–180°–a)可化为 sin(–a–180)等于多少

cos(a\u201390\u00b0)\u4e3a\u4ec0\u4e48\u7b49\u4e8ecos(90\u00b0\u2013a)

cos(a\u201390\u00b0)\u4e3a\u4ec0\u4e48\u7b49\u4e8ecos(90\u00b0\u2013a)?
\u4e09\u89d2\u51fd\u6570\u7684\u89d2\u5ea6\u8fd0\u8f6c\u5728\u56db\u4e2a\u8c61\u9650\u4e4b\u4e2d\uff0c\u51b3\u5b9a\u4e86\u7b80\u5316\u540e\u6b63\u8d1f\u5173\u7cfb\uff0c\u6bd4\u5982
\u4e0a\u8ff0
cos(a\u201390\u00b0)\u4ece\u8868\u793a\u5f0f\u6765\u770b\u5f53a\u5c0f\u4e8e90\u5ea6\uff0c\u5e94\u5f53\u5728\u7b2c\u56db\u8c61\u9650\uff0c\u4f60\u53ef\u4ee5\u753b\u4e00\u4e0b\u5b83\u7684\u89d2\u5ea6\u662f90-a,\u5b83\u7684\u503c\u662fcos(90-a)

\u5982\u56fe

解:
cos(-180°-α)
=cos[-(180°+α)]
=cos(180°+α)
=-cosα



  • 楂樹腑鏁板闂
    绛旓細cos(-x)=cosx鏄垚绔嬬殑銆COS(鈥150掳)鍦ㄧ涓夎薄闄愶紝COS(150掳)鍦ㄧ浜岃薄闄愩侰OS(鈥150掳)=鈥揅OS150掳锛岃繖涓瓑寮忔槸閿欒鐨勩傝浣忎竴鐐癸紝cos锛坸)鍑芥暟鏃嬭浆锛屾槸x杞寸殑鍊煎湪鍙樺寲锛宻in锛坸锛夊嚱鏁版棆杞槸y杞存暟鍊煎湪鍙樺寲銆
  • sin(180鈥揳)绛変簬sin(a鈥180)鍚,浠栦滑鏈変粈涔堝尯鍒?
    绛旓細涓嶇瓑浜庯紝鍔犱釜璐熷彿
  • 姹傞珮涓樁娈靛悇涓嚱鏁扮殑鍩烘湰鍥惧儚鍜屼笁瑙掑嚱鏁扮殑鎵鏈夊叕寮
    绛旓細cos(a+b)=cos(a)cos(b)-sin(a)sin(b)sin(a-b)=sin(a)cos(b)-cos(a)sin(b)cos(a-b)=cos(a)cos(b)+sin(a)sin(b)tan(a+b)=tan(a)+tan(b)1-tan(a)tan(b)tan(a-b)=tan(a)-tan(b)1+tan(a)tan(b)3.鍜屽樊鍖栫Н鍏紡 sin(a)+sin(b)=2sin(a+b2)cos(a-b2)sin...
  • ...涓旀弧瓒砪sinA=a鈭3cosC.鈶犳眰瑙扖鐨勫ぇ灏忊憽姹傗垰3sinA鈥揷osB
    绛旓細鍥犱负锛歴inA>0 鎵浠ワ細sinC=鈭3cosC 鎵浠ワ細tanC=鈭3 鎵浠ワ細C=60掳 锛2锛堿+B=120掳 鈭3sinA-cosB =鈭3sinA-cos(120掳-A)=鈭3sinA+(1/2)cosA-(鈭3/2)sinA =(1/2)cosA+(鈭3/2)sinA =sin(A+30掳)褰揂+30掳=90掳鍗矨=B=60掳鏃讹紝sin(A+30掳)=1 鎵浠ワ細鈭3sinA-cosB鏈澶у间负...
  • 宸茬煡a.b.c鍒嗗埆涓轰笁瑙掑舰鐨勫唴瑙A.B.C鐨勫杈,涓攁cosC ccosA=2bccosB.姹...
    绛旓細= 2*2RsinBcosB => sin(A + C)= sin2B = sinB => 2B = B + 2k蟺鎴栬 2B = 蟺 - B + 2k蟺 锛宬鏄暣鏁般傛墍浠ュ綋涓斾粎褰搆 = 0 鏃讹紝B = 蟺/3 => C = 2蟺/3 鈥揂 => sinA + sinC = sinA + sin(2蟺/3 鈥揂)= sinA + sin(2蟺/3)cosA 鈥揷os(2蟺/3)sinA = ...
  • cos(x鈥70掳)鎬庢牱鎹㈡垚sin
    绛旓細cos锛蟺/2+伪锛=锛峴in伪锛宑os锛埾/2锛嵨憋級=sin伪锛宻in锛埾+伪锛= 鈥攕in伪锛宑os锛坸-70掳锛=cos锛90掳-锛160掳-x锛夛級=sin锛160掳-x锛=sin锛180掳+锛-20掳锛+x锛=-sin锛坸-20掳锛
  • 鍑犱綍棰樻眰瑙
    绛旓細甯﹀叆棰樼洰鏉′欢鍖栫畝寰 cosA =(c + a ) / 2b cosB =(c 鈥 a ) / 2a 鍙煡 c = 2b*cosA 鈥 a = 2a * cosB + a 鍖栫畝涓涓嬪緱锛歜 *cosA 鈥 a*cosB = a 鐢ㄦ寮﹀畾鐞嗗甫鍏 sinB*cosA 鈥 sinA*conB = sinA 鎵浠ユ湁 sin(B 鈥揂 ) = sinA 鎵浠ュ緱B-A=A 鎴 B 鈥 A = 180-A锛...
  • 鐗╃悊鍏紡
    绛旓細(5)鍚屼竴鐩寸嚎涓婂姏鐨勫悎鎴,鍙部鐩寸嚎鍙栨鏂瑰悜,鐢ㄦ璐熷彿琛ㄧず鍔涚殑鏂瑰悜,鍖栫畝涓轰唬鏁拌繍绠椼 鍥涖佸姩鍔涘(杩愬姩鍜屽姏) 1.鐗涢】绗竴杩愬姩瀹氬緥(鎯у畾寰):鐗╀綋鍏锋湁鎯,鎬讳繚鎸佸寑閫熺洿绾胯繍鍔ㄧ姸鎬佹垨闈欐鐘舵,鐩村埌鏈夊鍔涜揩浣垮畠鏀瑰彉杩欑鐘舵佷负姝 2.鐗涢】绗簩杩愬姩瀹氬緥:F鍚=ma鎴朼=F鍚/ma{鐢卞悎澶栧姏鍐冲畾,涓庡悎澶栧姏鏂瑰悜涓鑷磢 3.鐗涢】绗...
  • 涓夎褰㈠唴,cosC=鈥揷os(A+B)涔,涓轰粈涔,璋㈣阿
    绛旓細A+B+C=180掳 cosC=cos[180掳-(A+B)]=-cos(A+B)鐢ㄥ埌鐨勫叕寮忥細涓夎褰㈠唴瑙掑拰鍏紡锛欰+B+C=180掳 璇卞鍏紡锛歝os(蟺-伪)=-cos伪
  • 涓夎鍑芥暟璇卞鍏紡鐨勬帹瀵
    绛旓細杩欐槸璁板繂涓夎鍑芥暟璇卞鍏紡鐨勫彛璇銆備緥濡傝绠:sin240;tan240 sin240=sin(180+60)=-sin60锛泂in240=sin(270-30)=-cos30銆備互涓婄殑180搴︽槸90搴︾殑鍋舵暟锛2锛夊嶏紝缁撴灉浠嶇劧鏄師鏉ョ殑鍑芥暟锛堟寮︼級锛岃270搴︽槸90搴︾殑濂囨暟锛3锛夊嶏紝缁撴灉灏卞彉鎴愪簡鍘熷嚱鏁扮殑浣欏嚱鏁帮紙浣欏鸡锛夛紝鍥犱负鍘熸潵鐨勮240搴︽槸绗笁椤归檺鐨勮锛屽師...
  • 扩展阅读:仙女cos清凉服装 ... 水手服 cosplay ... cos一脸玩坏掉的表情 ... cosplay病态文化 ... 貂蝉cos一字马 ... 女生最火cos角色排行榜 ... 余弦值对照表0-180 ... 中国知名coser排名 ... cos圈真的很乱吗 ...

    本站交流只代表网友个人观点,与本站立场无关
    欢迎反馈与建议,请联系电邮
    2024© 车视网