c语言中如何在一个字符串里搜索出其中的字母和数字啊?谢谢 如何用c语言分离字符串中的字母和数字并分别输出?

C\u8bed\u8a00\u95ee\u9898\uff1a\u5982\u4f55\u4ece\u4e00\u4e2a\u7531\u5b57\u6bcd\u548c\u6570\u5b57\u7ec4\u6210\u7684\u5b57\u7b26\u4e32\u4e2d\u63d0\u53d6\u51fa\u76f8\u5e94\u7684\u5b57\u6bcd\uff1f

#include int main(int argc, char const *argv[]){ char line[1024] = "\0"; // = 'a' and line[i] = 'A' and line[i] <= 'Z') ) printf("%c",line[i]); } printf("\n"); return 0;}\u8fd0\u884c\uff1a
Cat808her_+in_+e87Catherine

\u628a\u5b57\u7b26\u4e32\u5b58\u653e\u5230\u6570\u7ec4\u91cc\u9762,\u4e00\u4e2a\u4e00\u4e2a\u6bd4\u5bf9\uff08\u5faa\u73af\uff09\u540e\u8f93\u51fa
\u5224\u65ad\u6570\u5b57\uff1a
for (i=0;i<n;i++){
if ((p[i]>='0') && (p[i]<='9'))
printf();
\u5224\u65ad\u5b57\u6bcd\uff1a
for (i=0;i<n;i++){
if ((p[i]>='a') && (p[i]<='Z'))
printf();

\u6269\u5c55\u8d44\u6599\uff1a
\u901a\u5e38\u4ee5\u4e32\u7684\u6574\u4f53\u4f5c\u4e3a\u64cd\u4f5c\u5bf9\u8c61\uff0c\u5982\uff1a\u5728\u4e32\u4e2d\u67e5\u627e\u67d0\u4e2a\u5b50\u4e32\u3001\u6c42\u53d6\u4e00\u4e2a\u5b50\u4e32\u3001\u5728\u4e32\u7684\u67d0\u4e2a\u4f4d\u7f6e\u4e0a\u63d2\u5165\u4e00\u4e2a\u5b50\u4e32\u4ee5\u53ca\u5220\u9664\u4e00\u4e2a\u5b50\u4e32\u7b49\u3002\u4e24\u4e2a\u5b57\u7b26\u4e32\u76f8\u7b49\u7684\u5145\u8981\u6761\u4ef6\u662f\uff1a\u957f\u5ea6\u76f8\u7b49\uff0c\u5e76\u4e14\u5404\u4e2a\u5bf9\u5e94\u4f4d\u7f6e\u4e0a\u7684\u5b57\u7b26\u90fd\u76f8\u7b49\u3002\u8bbep\u3001q\u662f\u4e24\u4e2a\u4e32\uff0c\u6c42q\u5728p\u4e2d\u9996\u6b21\u51fa\u73b0\u7684\u4f4d\u7f6e\u7684\u8fd0\u7b97\u53eb\u505a\u6a21\u5f0f\u5339\u914d\u3002\u4e32\u7684\u4e24\u79cd\u6700\u57fa\u672c\u7684\u5b58\u50a8\u65b9\u5f0f\u662f\u987a\u5e8f\u5b58\u50a8\u65b9\u5f0f\u548c\u94fe\u63a5\u5b58\u50a8\u65b9\u5f0f\u3002
\u53c2\u8003\u8d44\u6599\u6765\u6e90\uff1a\u767e\u5ea6\u767e\u79d1-\u5b57\u7b26\u4e32

那大概就是这样

#include "stdio.h"
#include "string.h"
#include "stdlib.h"
int main(){
char str[1000]; //字符串
memset(str,1000,0);
scanf("%s",str);
char ch;
int pos1(0),pos2(0);
char s1[500],s2[500];
memset(s1,500,0);
memset(s2,500,0);

for(int i=0;i<strlen(str);i++){
ch=str[i];
if(ch<='9'&& ch>='0'){ //统计数字个数
s1[pos1++]=ch;
}
if( (ch<='z'&&ch>='a') ||(ch>='A'&&ch<='Z') ){
s2[pos2++]=ch;
}
}
printf("%s\n",s1);
printf("%s\n",s2);
system("pause");
return 0;
}

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