求lim (tanx-sinx)/x³ (x→0) 高数题 lim(x趋于0)(tanx-sinx)/x^3的极...

lim tanx-x/x-sinx x\u21920

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\u53c2\u8003\u8d44\u6599\u6765\u6e90\uff1a\u767e\u5ea6\u767e\u79d1\u2014\u2014\u6781\u9650

LIM(X\u8d8b\u54110\uff09tanx-sinx/x3\u6b21\u65b9=lim(x->0)tanx(1-cosx)/x³=lim(x->0)(x\u00b7x²/2)/x³=1/2

上式可变为lim【sin x*(cos x-1)】/x3;
又因为 sin x~x,(cos x-1)~1/2 X2
所以答案为1/2.
你的解答是步骤2错了,步骤1得出的式子不符合洛必达法则条件,当x趋近于0时,分子不趋近于0,不能像你那样再用罗比达法则

0/0型 分子分母同时分别求导
=lim(sinx/x)*lim(secx-1)/x^2
=1*lim(secxtanx)/2x

=1*lim(sinx/2x*cos^2x)
=lim(1/2cos^2x)
=1/2

  用洛比达法则:
   lim(x→0)(tanx-sinx)/x³ (0/0)
  = lim(x→0)[(secx)^2-cosx]/3x^2
  = lim(x→0)[1-(cosx)^3]]/[3(x^2)(cosx)^2] (化简)

  = lim(x→0){[1+cosx+(cosx)^2]/[3(cosx)^2]}{(1-cosx)/x^2}

  = (3/3)(1/2)
  = 1/2。
  还可用Taylor公式,……

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