c语言:(用数组与指针法,不使用strupr函数)任意输入一串字符串,将其全部变为大写并反序输出。

C\u8bed\u8a00\u7528strupr\u51fd\u6570\u5c06\u5b57\u7b26\u4e32\u4e2d\u5c0f\u5199\u5b57\u6bcd\u8f6c\u6362\u6210\u5927\u5199\u5b57\u6bcd\uff0c\u5176\u4ed6\u5b57\u7b26\u4e0d\u8f6c\u6362\u3002\u8c22\u8c22

\u539f\u578b\uff1aextern char *strupr(char *s);

\u7528\u6cd5\uff1a#include

\u529f\u80fd\uff1a\u5c06\u5b57\u7b26\u4e32s\u8f6c\u6362\u4e3a\u5927\u5199\u5f62\u5f0f

\u8bf4\u660e\uff1a\u53ea\u8f6c\u6362s\u4e2d\u51fa\u73b0\u7684\u5c0f\u5199\u5b57\u6bcd\uff0c\u4e0d\u6539\u53d8\u5176\u5b83\u5b57\u7b26\u3002\u8fd4\u56de\u6307\u5411s\u7684\u6307\u9488\u3002

\u4e3e\u4f8b\uff1a


// strupr.c

#include
#include

main()
{
char *s="Copywrite 1999-2000 GGV Technologies";

clrscr();

printf("%s",strupr(s));

getchar();
return 0;
}

(A\uff09 s\u548cp\u5b8c\u5168\u76f8\u540c
a\u7684\u7c7b\u578b\u662fcha\u6570\u7ec4
p\u7684\u7c7b\u578b\u662fchar\u6307\u9488
\u4e0d\u4e00\u6837
\uff08B\uff09\u6570\u7ec4s\u4e2d\u7684\u5185\u5bb9\u548c\u6307\u9488\u53d8\u91cfp\u4e2d\u7684\u5185\u5bb9\u60f3\u7b49
\u6570\u7ec4s\u4e2d\u7684\u5185\u5bb9\u662f: "china"
\u6307\u9488\u53d8\u91cfp\u4e2d\u7684\u5185\u5bb9\u662f: s[0]\u7684\u5730\u5740\uff08&s[0]\uff09
\u4e00\u4e2a\u662f\u5b57\u7b26\u4e32 \u4e00\u4e2a\u662f\u5730\u5740
\u4e0d\u4e00\u6837

\uff08C\uff09s\u6570\u7ec4\u957f\u5ea6\u548cp\u6240\u6307\u5411\u7684\u5b57\u7b26\u4e32\u957f\u5ea6\u76f8\u7b49
s\u6570\u7ec4\u957f\u5ea6\u5305\u62ec '\0'\u7684\u4f4d\u7f6e
p\u6240\u6307\u5411\u7684\u5b57\u7b26\u4e32\u957f\u5ea6\u4e0d\u5305\u62ec '\0'\u7684\u4f4d\u7f6e
s\u6570\u7ec4\u957f\u5ea6 == p\u6240\u6307\u5411\u7684\u5b57\u7b26\u4e32\u957f\u5ea6 + 1 (1\u5c31\u662f'\0'\u5360\u6709\u7684\u4f4d\u7f6e)
\u663e\u7136 \u4e0d\u76f8\u7b49

#include<stdio.h>int count = 0; void reverse() { char ch = getchar(); if (ch == '\n') { return; } else { reverse(); if (ch>= '0'&&ch<= '9') { ++count; } if (ch>= 'a'&&ch<= 'z') { ch = ch - 'a' + 'A'; } putchar(ch); } } int main() { reverse(); printf("\nThe number of 0 ~ 9: %d.\n", count); return 0; }

int i;char a[n],*p=a;for(i=0;i<n;i++){if(*p+i>='a'&&*p+i<=z)printf("%s",*p);}for(i<n;i>=0;i--)printf("%s",*p);

#include<stdio.h>
#include<string.h>
int main()
{
char a[100],*p;
int len;
while(scanf("%s",a)!=EOF)
{
len=strlen(a);
p=a;
for(;p<a+len;p++)
if(*p>='a'&&*p<='z')
{
*p=*p-32;
}
for(p=a+len-1;p>=a;p--)
printf("%c",*p);
printf("\n");
}
return 0;
}

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