这几道矩阵题怎么解 矩阵题怎么解
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A的转置乘以A那么，所得矩阵对角线上是A中的元素平方和相加，因为矩阵是零矩阵，所以每个元素必须为零，你可以用个2*2的矩阵试下。
首先知道，A^2=E，按照将矩阵A和E看成数，可用公式知，原式=A^7-E^7=A-E=(-12 4)
-30 10
3. A^t=A, 证明B^tAB是对称阵只需证明 B^tAB=(B^tAB)^t. 证明：(B^tAB)^t=B^tA^tB=B^tAB,命题得证。
4. A^t=A, B^t=-B, (AB)^t=B^tA^t=-BA, 如果AB为反对称矩阵，可知应该 -BA=-AB, 即AB=BA
希望能采纳！
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绛旓細|-|A|A| =|-2A| =(-2)^3|A| =-8|A| =(-8)(-2)=16
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