急求:100ml 0.1mol/l 的NaOH溶液中,含NaOH的质量是多少g?计算过程 配制1L0.1mol/L的NaOH溶液,需称取NaOH固体多...

\u67d0100mL\u7269\u8d28\u7684\u91cf\u6d53\u5ea6\u4e3a1mol/L\u7684NaOH\u6eb6\u6db2\uff0e\u8bd5\u8ba1\u7b97\uff1a\uff081\uff09\u8be5\u6eb6\u6db2\u4e2dNaOH\u7684\u8d28\u91cf\uff0e\uff082\uff09\u4e0a\u8ff0\u6eb6\u6db2\u4e0e\u7269\u8d28\u7684\u91cf\u6d53

\uff081\uff09n\uff08NaOH\uff09=0.1L\u00d71mol/L=0.1mol\uff0c\u6545m\uff08NaOH\uff09=0.1mol\u00d740g/mol=4.0g\uff0c\u7b54\uff1a\u8be5\u6eb6\u6db2\u4e2dNaOH\u7684\u8d28\u91cf\u4e3a4.0g\uff1b\uff082\uff09\u6839\u636eNaOH+HCl=NaCl+H2O\uff0c\u53ef\u77e5\u9700\u8981HCl\u7269\u8d28\u7684\u91cf\u4e3a0.1mol\uff0c\u5219\u9700\u8981\u76d0\u9178\u7684\u4f53\u79ef\u4e3a0.1mol1mol/L=0.1l=100mL\uff0c\u7b54\uff1a\u9700\u8981\u76d0\u9178\u7684\u4f53\u79ef\u4e3a100mL\uff1b\uff083\uff09\u53cd\u5e94\u540e\u6eb6\u8d28\u4e3aNaCl\uff0c\u6839\u636e\u94a0\u79bb\u5b50\u5b88\u6052n\uff08NaCl\uff09=n\uff08NaOH\uff09=0.1mol\uff0c\u6545\u7b54\u6848\u4e3a\uff1a0.1\uff0e

\u5148\u7528\u6d53\u5ea6\u4e58\u4ee5\u4f53\u79ef\u7b49\u4e8e\u7269\u8d28\u7684\u91cf,\u518d\u7528\u7269\u8d28\u7684\u91cf\u4e58\u4ee5\u6469\u5c14\u8d28\u91cf\u7b49\u4e8e\u8d28\u91cf,
m=n* M=c*V*M=0.1mol/L * 1L * 40g/mol =4g

化学问题啊！
100ml/1000ml/l=0.1l
0.1l×0.1mol/l=0.01mol
1mol就是NaOH分子量23+16+1=40相当于40g/mol
所以
0.01mol*40g/mol=0.4g

n(NaOH)=100ml×0.1mol/L=0.01mol
m(NaOH)=0.01mol×40g/mol=0.4g
这是高中一年级最简单的计算题，希望你好好看看书，不要什么问题都让别人给你解决。

100ml=0.1l 0.1*0.1=0.01mol 0.01mol*40g/mol=0.4g

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