电阻的计算公式、串联和并联的 电阻串联和并联功率怎么计算?

\u5e76\u8054\u7535\u963b\u8ba1\u7b97\u516c\u5f0f\u8ba1\u7b97\u65b9\u6cd5

\u603b\u7535\u963b\u503c\u7684\u8ba1\u7b97
1/R\u603b=1/R1+1/R2+\u2026\u2026+1/Rn\uff0c\u5373\u603b\u7535\u963b\u7684\u5012\u6570\u7b49\u4e8e\u5404\u5206\u7535\u963b\u7684\u5012\u6570\u4e4b\u548c
\u7279\u522b\u7684\uff0c\u4e24\u7535\u963b\u5e76\u8054\u603b\u503c\u4e3a\uff1a R\u603b=\uff08R1*R2)/\uff08R1+R2\uff09
\u5bf9\u4e8en\u4e2a\u76f8\u7b49\u7684\u7535\u963b\u5e76\u8054\uff0c\u516c\u5f0f\u5c31\u7b80\u5316\u4e3aR\u5e76=R/n\u3002

\u6bd4\u5982\u95ee\u9898\u4e2d\u4e00\u4e2a\u7535\u963b20\u6b27\uff0c\u53e6\u4e00\u4e2a\u7535\u963b\u662f40\u6b27\uff0c\u5e76\u8054\u5728\u4e00\u8d77\u603b\u7535\u963b\u8ba1\u7b97\u65b9\u6cd5
\u2460\u5229\u7528\u516c\u5f0f R\u603b=\uff08R1*R2)/\uff08R1+R2\uff09
R\u603b=20*40/\uff0820+40\uff09=40/3
\u2461\u6309\u7167\u7535\u963b\u5e76\u8054\u516c\u5f0f 1/R\u603b=1/R1+1/R2+\u2026\u2026+1/Rn\uff0c\u5c06\u6bcf\u4e2a\u5206\u7535\u963b\u7684\u5012\u6570\u76f8\u52a0\uff0c\u518d\u6c42\u548c\u7684\u5012\u6570\u5c31\u662f\u5e76\u8054\u7684\u603b\u7535\u963b \u3002\u53731/20+1/40=3/40 \u90a3\u4e48\u603b\u7535\u963b\u5c31\u662f= 40/3\u3002
\u2460\u2461\u4e24\u79cd\u8ba1\u7b97\u7ed3\u679c\u76f8\u540c\uff0c\u5747\u662f40/3\uff0c\u7ea6\u7b49\u4e8e13.3\u3002
\u6269\u5c55\u8d44\u6599\uff1a1\u3001\u5e76\u8054\u7535\u8def\uff1a\u5e76\u8054\u7684\u5404\u652f\u8def\u7535\u538b\u76f8\u7b49\uff0c\u5e72\u8def\u7535\u6d41\u7b49\u4e8e\u5404\u4e2a\u652f\u8def\u548c\u3002
\u8868\u8fbe\u5f0f\uff1a\u7535\u963bR1R2R3\u2026\u2026Rn\u5e76\u8054,\u7535\u538bU1=U2=\u2026\u2026=Un\u5e72\u8def\u7535\u6d41\uff1aIn=I1+I2+\u2026\u2026+In\u7531\u4e8eP=UI,I=U/R\uff0c\u4ee3\u5165\uff0c\u5e76\u8054\u7535\u963b\u7684\u529f\u7387\u6bd4P1:P2:P3\u2026\u2026\uff1aPn=U1^2/R1:U2^2/R2\u2026\u2026Un^2/Rn=1/R1:R2\u2026\u20261/Rn\u7531\u4e8e\u662f\u7eaf\u7535\u963b\uff0c\u53d1\u70ed\u6bd4Q1:Q2\u2026\u2026\uff1aQn=Pn\u6bd4=1/R1:R2\u2026\u20261/Rn\u3002
2\u3001\u5e76\u8054\u7535\u8def\u4e2d\u7684\u5173\u7cfb
\u7535\u538b\u7684\u5173\u7cfb\uff1aU=U1=U2
\u7535\u6d41\u7684\u5173\u7cfb\uff1aI=I1+I2
\u7535\u963b\u7684\u5173\u7cfb\uff1a1/R=1/R1+1/R2
\u7535\u529f\u7684\u8ba1\u7b97\uff1aW=UIt
\u7535\u529f\u7387\u7684\u5b9a\u4e49\u5f0f\uff1aP=W/t
\u5e38\u7528\u516c\u5f0f\uff1aP=UI
\u7126\u8033\u5b9a\u5f8b\uff1aQ\u653e=I^2Rt
\u5bf9\u4e8e\u7eaf\u7535\u963b\u7535\u8def\u800c\u8a00\uff1aQ\u653e=I^2Rt =U^2t/R=UIt=Pt=UQ=W
\u7167\u660e\u7535\u8def\u7684\u603b\u529f\u7387\u7684\u8ba1\u7b97\uff1aP=P1+P1+\u2026\u2026
\u53c2\u8003\u8d44\u6599\uff1a\u767e\u5ea6\u767e\u79d1-\u5e76\u8054\u7535\u963b

\u7535\u963b\u4e32\u5e76\u8054\u529f\u7387\u90fd\u76f8\u52a0\uff0c\u7eaf\u7535\u963b\u7535\u8defP=UI\uff0c\u5982\u679c\u4e0d\u662f\u7eaf\u7535\u963b\u7535\u8def\uff0c\u5c31\u7528\u7535\u963b\u5206\u5f97\u7535\u538b\u4e58\u7535\u6d41
1\u3001\u7535\u963b\uff08resistance\uff09\u7f29\u5199\u4e3aR\uff0c\u5b83\u662f\u5bfc\u4f53\u7684\u4e00\u79cd\u57fa\u672c\u6027\u8d28\uff0c\u4e0e\u5bfc\u4f53\u7684\u5c3a\u5bf8\u3001\u6750\u6599\u3001\u6e29\u5ea6\u6709\u5173\u3002\u6b27\u59c6\u5b9a\u5f8b\u6307\u51fa\u7535\u538b\u3001\u7535\u6d41\u548c\u7535\u963b\u4e09\u8005\u4e4b\u95f4\u7684\u5173\u7cfb\u4e3aI=U/R\uff0c\u4ea6\u5373R=U/I\u3002\u7535\u963b\u7684\u57fa\u672c\u5355\u4f4d\u662f\u6b27\u59c6\uff0c\u7528\u5e0c\u814a\u5b57\u6bcd\u201c\u03a9\u201d\u6765\u8868\u793a\u3002
2\u3001\u901a\u5e38\u201c\u7535\u963b\u201d\u6709\u4e24\u91cd\u542b\u4e49\uff0c\u4e00\u79cd\u662f\u7269\u7406\u5b66\u4e0a\u7684\u201c\u7535\u963b\u201d\u8fd9\u4e2a\u7269\u7406\u91cf\uff0c\u53e6\u4e00\u4e2a\u6307\u7684\u662f\u7535\u963b\u8fd9\u79cd\u7535\u5b50\u5143\u4ef6\u3002\u7535\u963b\u5143\u4ef6\u7684\u7535\u963b\u503c\u5927\u5c0f\u4e00\u822c\u4e0e\u6e29\u5ea6\uff0c\u6750\u6599\uff0c\u957f\u5ea6\uff0c\u8fd8\u6709\u6a2a\u622a\u9762\u79ef\u6709\u5173\uff0c\u8861\u91cf\u7535\u963b\u53d7\u6e29\u5ea6\u5f71\u54cd\u5927\u5c0f\u7684\u7269\u7406\u91cf\u662f\u6e29\u5ea6\u7cfb\u6570\uff0c\u5176\u5b9a\u4e49\u4e3a\u6e29\u5ea6\u6bcf\u5347\u9ad81\u2103\u65f6\u7535\u963b\u503c\u53d1\u751f\u53d8\u5316\u7684\u767e\u5206\u6570\u3002
3\u3001\u7535\u963b\u7684\u4e3b\u8981\u7269\u7406\u7279\u5f81\u662f\u53d8\u7535\u80fd\u4e3a\u70ed\u80fd\uff0c\u4e5f\u53ef\u8bf4\u5b83\u662f\u4e00\u4e2a\u8017\u80fd\u5143\u4ef6\uff0c\u7535\u6d41\u7ecf\u8fc7\u5b83\u5c31\u4ea7\u751f\u5185\u80fd\u3002\u7535\u963b\u5728\u7535\u8def\u4e2d\u901a\u5e38\u8d77\u5206\u538b\u3001\u5206\u6d41\u7684\u4f5c\u7528\u3002\u5bf9\u4fe1\u53f7\u6765\u8bf4\uff0c\u4ea4\u6d41\u4e0e\u76f4\u6d41\u4fe1\u53f7\u90fd\u53ef\u4ee5\u901a\u8fc7\u7535\u963b\u3002

电阻R1和电阻R2串联后,等效为:R串=R1+R2
电阻R1和电阻R2并联后,等效为:(1/R并)=(1/R1)+(1/R2) ,或:R并=(R1*R2)/(R1+R2)

电阻串联:阻值直接相加。并联:总电阻的倒数等各个并联电阻的倒数之和。
如果4个电阻全串联:电流I=200V/(4*5)=10A
如果4个电阻全并联:总电阻R=1.25,总电流I=200A/1.25=160A

串联R=R1+R2+R3+。。。,即所有电阻之和。并联公式比较复杂。1/R=1/R1+1/R2+...,即总电阻的倒数等于分电阻倒数和。用I=U/R,用总电压比总电阻。



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