求大师编写一个通达信选股公式:“一阳穿三线(5日、10日、20日均线)”后的第N个K线 求通达信选股公式一阳穿三线。均线分别是5,10,20要求当天...

\u8bf7\u8001\u5e08\u5e2e\u5199\u4e00\u4e2a 10\u65e5\u5747\u7ebf\u4e0a\u7a7f20\u65e5\u5747\u7ebf\u9009\u80a1\u516c\u5f0f\u3002\u8c22\u8c22

\u516c\u5f0f\u5982\u4e0b\uff0c\u5728\u901a\u8fbe\u4fe1\u4e2d\u6d4b\u8bd5\u901a\u8fc7\u3002XG:CROSS(MA(C,10),MA(C,20))\u3002
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10\u65e5\u7ebf\u662f\u804c\u4e1a\u5957\u5229\u8005\u80fd\u591f\u719f\u7ec3\u638c\u63e1\u7684\u6700\u77ed\u5747\u7ebf\uff0c\u4ed6\u662f\u7814\u5224\u9876\u90e8\u4e0e\u5e95\u90e8\u7684\u7b2c\u4e00\u4e2a\u63d0\u793a\u6280\u672f\uff0c\u5f53\u7136\u66f4\u4e3a\u7cbe\u786e\u7684\u5206\u6790\u5fc5\u987b\u7ed3\u5408\u6210\u4ea4\u91cf\u80fd\u3001\u4e3b\u529b\u4e60\u60ef\u65f6\u95f4\u6bb5\u3001\u7ecf\u5178K\u7ebf\u4e0e\u957f\u7ebf\u6307\u6807(\u5982\u5fc3\u7406\u7ebf\u4e0e\u968f\u673a\u6307\u6807\u4e2d\u7684\u5468KDJ\u7ebf)\u3002
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AA:=L=MA(C,5) AND C>=MA(C,10) AND C>=MA(C,20) AND C>O;
STICKLINE(AA,O,C,2,0),COLORyellow,LINETHICK3;

您的描述有未来函数嫌疑,应该是N个K线前,一阳穿三线(5日、10日、20日均线
ma5:=ma(c,5);
ma10:=ma(c,10);
ma20:=ma(c,20);
N:=barslast(l<ma5 and l<ma10 and l<ma20 and h>ma5 and h>ma10 and h>ma20)+1;

N就是发生条件后N线个数

N:=5;
N1:=10;
M:=20;
E1:=MA(CLOSE,N);
E2:=MA(CLOSE,N1);
E3:=MA(CLOSE,M);
穿三线:CROSS(CLOSE,E1) AND CROSS(CLOSE,E2) AND CROSS(CLOSE,E3);

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