定义集合A与集合B的"差集"为:A-B={x丨x∈A且x不属于B},则A-(A-B)=? 我想要详细的解答谢谢！
\u82e5\u5b9a\u4e49\u96c6\u5408A\u4e0e\u96c6\u5408B\u7684\u5dee\u96c6\u4e3a\uff1aA-B={x|x\u2208A\u4e14x?B}\uff0c\u5219A-\uff08A-B\uff09\u6052\u7b49\u4e8e______\u2235A-B={x|x\u2208A\u4e14x?B}\uff0c\u2234A-B=A\u2229CuB\uff0c\u2234A-\uff08A-B\uff09=A\u2229B\uff0e\u6545\u7b54\u6848\u4e3a\uff1aA\u2229B\uff0e
\u7535\u8111\u4e0a\u4e00\u4e9b\u7b26\u53f7\u53ef\u80fd\u770b\u4e0d\u51fa\u3002\u6211\u5c31\u6309\u6211\u7406\u89e3\u7684\u7b97\u7b97\u3002\u6ce8\u610f\u96c6\u5408\u4e2d\u53d6\u503c\u7b26\u53f7\u201c|\u201d
\u5bf9\u4e8e\u96c6\u5408A\u3001B\u5b9a\u4e49\u5dee\u96c6A-B={x|x\u2208A,\u4e14X\u4e0d\u5c5e\u4e8eB}\uff0c\u82e5A{x|-1/2\uff1cX\uff1ca}\uff0cB={x|3x-1/2x+1\u22641}\uff0c\u4e14A-B=\u7a7a\u96c6\uff0c\u6c42\u5b9e\u6570A\u7684\u53d6\u503c\u8303\u56f4
\u5982\u679cA-B=\u7a7a\u96c6\uff0c\u4e0d\u5b58\u5728\u5c5e\u4e8eA\u4f46\u4e0d\u5c5e\u4e8eB\u7684\u5143\u7d20\uff0c\u5c31\u8bf4\u660e\uff0c\u5c5e\u4e8eA\u7684\u5143\u7d20\uff0c\u90fd\u5c5e\u4e8eB\uff0c\u5373\uff0cA\u662fB\u7684\u5b50\u96c6\u3002\u5305\u62ecA\u4e3a\u7a7a\u96c6\uff0cAB\u76f8\u7b49\u4e24\u79cd\u7279\u6b8a\u60c5\u51b5\u3002
\u8fd9\u6837\u5c31\u597d\u7b97\u4e86\u7684\u3002\u5206\u522b\u89e3\u51faA\uff0cB\uff0c\u5217\u51fa\u6570\u8f74\u5c31\u53ef\u4ee5\u4e86\u3002
A-(A-B)=A-A+B=B
就是集合B
理解：A-B={x丨x∈A且x不属于B}，即A-B中只有A中元素，没有B中元素
A-(A-B)={x丨x∈A且x不属于A-B}，即把除B中元素不存在的再扔掉，那么正好就只有B中的元素了
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