关于c语言的函数问题,紧急,多谢!!

c\u8bed\u8a00\u91cc\u51fd\u6570\u95ee\u9898

\u4e24\u4e2a\u5730\u65b9\u7684\u9519\u8bef\uff1a
1\u3001\u5728power\u51fd\u6570\u4e2d\uff0creturn ( x*power(x, n-1 );
2\u3001\u5728\u4e3b\u51fd\u6570\u4e2d\uff0cpower( x, n ); \u628a\u8fd9\u4e00\u884c\u7684\u6240\u6709double\u90fd\u53bb\u6389\u5c31OK\u4e86\u3002
\u53c8\u53d1\u73b0\u4e00\u4e2a\u95ee\u9898\uff0c\u4f60\u7684\u8f93\u5165\u6709\u95ee\u9898\u554a\uff0c\u6539\u6210 scanf("%lf%d", &x, %n ); \u5176\u4e2d f \u524d\u9762\u7684\u662f\u5b57\u6bcd l\uff0c\u53e6\u5916\uff0c\u4f60\u6c42\u5f97\u4e86x\u7684n\u6b21\u5e42\u540e\u8be5\u8f93\u51fa\u3002
\u628a\u6700\u540e\u4e00\u884c\u5199\u6210 printf("%f\n", power(x,n));

#include
float average(int a[],int n);
int main(void)
{
int arrA[5],int arrB[8];
float avgA,avgB;
scanf("%d%d%d%d%d",&arrA[0],&arrA[1],&arrA[2],&arrA[3],&arrA[4]);
scanf("%d%d%d%d%d%d%d%d",&arrB[0],&arrB[1],&arrB[2],&arrB[3],&arrB[4],&arrB[5],&arrB[6],&arrB[7]);
avgA=average(arrA,5);
printf("\n%.1f",avgA);
avgB=average(arrB,8);
printf("\n%.1f\n",avgB);
return 0;
}
float average(int a[],int n)
{
int i;
float s=0.0;
for(i=0;i<n;i++)
s=s+a[i];
return s/n;
}

#include <iostream.h>
#include <string.h>
char *power( char *s)
{
int n=strlen(s);
char t;
for(int i=0,j=n-1;i<j;i++,j--)
{
t=s[i];s[i]=s[j];s[j]=t;
}
return s;
}
int main()
{
cout<<"请输入一个字符串:"<<endl;
char str[100];
cin.getline(str,100);
cout<<"逆序后结果为:"<<endl;
cout<<power(str)<<endl;
return 0;
}

给个递归的
#include<stdio.h>
void fun(int n)
{
int next;
if(n<1)
{
next=getchar();
putchar(next);
}

else
{
next=getchar();
fun(n-1);
putchar(next);
}
}
void main()
{
int n;
printf("请输入所要输入的字符的个数:");
scanf("%d",&n);
fun(n);
//getch();
}

123

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