配平化学方程式C3H8+O2------CO2+H2O 用 归一法 C2H6+O2----CO2+H2O这个化学方程式如何配平？
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1.\u5148\u914d\u5e73\u78b3\u539f\u5b50C2H6+O2----2CO2+H2O2.\u518d\u914d\u5e73\u6c22\u539f\u5b50C2H6+O2----2CO2+3H2O3.\u518d\u914d\u5e73\u6c27\u539f\u5b50\uff0c\u53ef\u4ee5\u7528\u5206\u6570\u6765\u914d\u5e73C2H6+7/2O2----2CO2+3H2O4.\u5404\u7cfb\u6570\u4e58\u4ee52\uff0c\u53bb\u6389\u5206\u65702C2H6+7O2=4CO2+6H2O
C3H8+O2------CO2+H2O1，设最复杂的为1
所以C3H8前为1
1C3H8+O2------CO2+H2O
2，根据氢守恒，那么水前面是4
1C3H8+O2------CO2+4H2O
3，根据碳守恒，CO2 前是3
1C3H8+O2------3CO2+4H2O
4，根据氧守恒配平氧气前为5
1C3H8+5O2------3CO2+4H2O
5，正好配平，写上反应条件和写上箭头
C3H8+5O2---点燃---3CO2+4H2O
不懂问
2C2H2+5O2-----4CO2+2H2O
CH4+2O2----CO2+2H2O
C2H5OH+3O2--2CO2+3H2O
2CH3OH+2O2---2CO2+2H2O
C3H8+5O2=3CO2+4H2O
C3H8+5O2=3CO2+4H2O
1 .5 .3. 4
什么归一法？能配平就行了
绛旓細鐐圭噧 C3H8+5O2===4H2O+3CO2 (涓嶉渶瑕佸崌闄嶇鍙,鍥犱负涓嶆槸婧舵恫鍙嶅簲鐢熸垚鍥轰綋,鍙嶅簲鐗╀篃鏈夋皵浣)
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绛旓細C3H8+5O2---3CO2+4H2O 4FeS2+11O2=2Fe2O3+8SO2 Cu2(OH)2CO3=2CuO+H2O+CO2
绛旓細涓欑兎涓虹噧鏂 鎵浠鏂圭▼寮灏辨槸 C3H8 + O2 == CO2 + H2O 鐢佃В璐ㄦ槸铻嶈瀺鐨勭⒊閰哥洂锛屾彁渚涚殑鏄紙CO3锛2- O2 + CO2 + e- == 锛圕O3锛2- C3H8 + [锛圕O3锛2-] - e- == CO2 + H2O 浜ゆ祦浜ゆ祦 瀛︿範杩涙
绛旓細C3H8+5O2=3CO2+4H2O
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绛旓細锛1锛2銆2銆3 锛2锛夋槸C3H8,1銆5銆3銆4 锛3锛2銆3銆1銆3 锛4锛3銆2銆3銆1銆3 锛5锛1銆4銆3銆4
绛旓細姝ｆ瀬: 5o2 +20e-+ 20H+ = 10H2O 鐢垫睜鎬诲弽搴旓細C3H8+5O2=3CO2+4H2O 纰辨э細璐熸瀬:C3H8 - 20 e- + 26OH- = 3CO32- + 17H2O 姝ｆ瀬: 5O2 + 20 e- + 10H2O = 20OH- 鎬诲弽搴: C3H8 + 5O2 + 6OH- = 3CO32- + 7H2O 涓э細璐熸瀬锛5O2+20e-+10H2O=20OH- 姝ｆ瀬锛欳3H8-20e-+6...
