用C语言编一个小游戏,注明编码,(简单易懂的游戏,不要复杂) 求助,用C语言做一个小游戏(不要太复杂),最最最基础的C语言...

\u7528C\u8bed\u8a00\u7f16\u4e00\u4e2a\u5c0f\u6e38\u620f\uff0c\u6ce8\u660e\u7f16\u7801\uff0c\uff08\u7b80\u5355\u6613\u61c2\u7684\u6e38\u620f\uff0c\u4e0d\u8981\u590d\u6742\uff09

//C\u8bed\u8a00\u5199\u7684\uff0c\u4e00\u4e2a\u73a9\u77f3\u5934\u3001\u526a\u5200\u3001\u5e03\u7684\u5c0f\u6e38\u620f\u3002\u4e0b\u9762\u662f\u6e90\u7801\u3002
#include
#include

int main()
{
char cq[][10]={"\u77f3\u5934","\u526a\u5200","\u5e03"};
int guess=-1,r,youwin=0,mewin=0,daping=0,total=0;

srand(time(NULL));
while(1)
{
r=(int)((rand()/(RAND_MAX+1.0))*3);
printf("0\u3001\u77f3\u5934\n1\u3001\u526a\u5200\n2\u3001\u5e03\n3\u3001\u9000\u51fa\n\u6211\u5df2\u51fa\uff0c\u8bf7\u4f60\u51fa\uff1a");
scanf("%d",&guess);
if(3==guess)
{
break;
}
else
{
total++;
printf("\u8fd9\u4e00\u6b21\u4f60\u51fa\u7684\u662f%s,\u6211\u51fa\u7684\u662f%s\uff0c\u6240\u4ee5",cq[guess],cq[r]);
if(0==guess&&1==r || 1==guess&&2==r || 2==guess&&0==r)
{
youwin++;
printf("\u4f60\u8d62\u4e86\uff01\n");
}
else if(guess==r)
{
daping++;
printf("\u6211\u4eec\u6253\u5e73\u4e86\uff01\n");
}
else
{
mewin++;
printf("\u6211\u8d62\u4e86\uff01\n");
}
}
}
printf("\u603b\u5171\u73a9\u4e86%d\u6b21\uff0c\u4f60\u8d62\u4e86%d\u6b21\uff0c\u6211\u8d62\u4e86%d\u6b21\uff0c\u6253\u5e73%d\u6b21\uff01\n",total,youwin,mewin,daping);
system("PAUSE");
return EXIT_SUCCESS;
}

\u731c\u6570\u5b57 \u8d85\u7b80\u5355 \u53bb\u6389\u8bf4\u660e\u6587\u5b57\uff0c\u4e5f\u5c31\u5341\u51e0\u884c
\u7b80\u5355\u8bf4\u660e\u89c1\u6ce8\u91ca
#include
#include
#include
int main()
{
int i;
int a;
int t;

printf("\u6b22\u8fce\u73a9\u731c\u6570\u5b57\u5c0f\u6e38\u620f!\n");
printf("\u73a9\u6cd5\u4ecb\u7ecd:\n");
printf("\u6bcf\u6b21\u6e38\u620f\u4f1a\u8bbe\u7f6e\u4e00\u4e2a\u6570\u5b57(1-100)\uff0c\u8bf7\u8f93\u5165\u4f60\u731c\u7684\u6570\u5b57\n");
printf("\u7cfb\u7edf\u4f1a\u63d0\u793a\u4f60\u8f93\u5165\u7684\u6570\u5b57\u6bd4\u7b54\u6848\u5927\u6216\u8005\u5c0f\n");
printf("\u5f53\u8f93\u5165\u6570\u5b57\u548c\u7b54\u6848\u76f8\u540c\u65f6\u80dc\u5229\n");
printf("\u597d\u8fd0\u54e6!\n");
srand(time(NULL));//\u8bbe\u7f6e\u968f\u673a\u6570\u79cd\u5b50
while(1)
{
a = rand()%100+1;//\u83b7\u53d61-100\u95f4\u968f\u673a\u6570\u5b57
printf("\u6211\u60f3\u597d\u4e86\u4e00\u4e2a\u6570\u5b57\uff0c1-100\u4e4b\u95f4\uff0c\u4f60\u6765\u731c\u5427\n");
t = 0;
while(1)
{
scanf("%d", &i);//\u8f93\u5165\u6570\u5b57
t++;
//\u5224\u65ad\u5408\u6cd5\u6027
if(i 100)
{
printf("\u7b28\u86cb\uff0c\u4e0d\u662f\u544a\u8bc9\u4f60\u662f1-100\u4e4b\u95f4\u7684\u5417!\n");
continue;
}
//\u5224\u65ad\u5927\u5c0f
if(i > a) printf("\u6bd4\u6211\u60f3\u7684\u8981\u5927\u54e6\n");
else if(i < a) printf("\u6bd4\u6211\u60f3\u7684\u8981\u5c0f\u54e6\n");
else
{
printf("\u731c\u5bf9\u4e86\uff0c\u5c31\u662f%d\uff0c\u4f60\u7528\u4e86%d\u6b21\n", i,t);
break;//\u6210\u529f \u7ed3\u675f\u672c\u6b21\u6e38\u620f
}
}
printf("\u8fd8\u8981\u7ee7\u7eed\u73a9\u5417? \u7ee7\u7eed\u8bf7\u8f93\u51651\n");

scanf("%d", &i);
if(i != 1) break;
}
printf("\u518d\u89c1\u5566!\n");
return 0;
}

我这有许多C的小游戏。给你一个基础的简单的汉诺塔程序。你看看:
这是个汉诺塔程序,在调试的时候,输入的数字最好不要大于15,因为每大一个数
所得的结果的步骤都会多一倍。如果你有耐心等待结果的话除外。汉诺塔是在欧洲
流行的一种游戏,有a,b,c三个竿。a竿上有若干个由大到小的圆盘,大的在下面,
小的在上面,b,c都是空杆,请你把a杆上的圆盘都倒到别的杆上,或b或c,在倒盘
的过程中不可以大的压小的,实例程序如下:

#include <stdio.h>
int i=0;
main()
{
unsigned n;
printf("Please enter the number of discs: ");
scanf("%d",&n);
printf("\tneedle:\ta\t b\t c\n");
movedisc(n,'a','c','b');
printf("\t Total: %d\n",i);
getch();
}
movedisc(n,fromneedle,toneedle,usingneedle)
unsigned n;
char fromneedle,toneedle,usingneedle;
{
if(n>0)
{
movedisc(n-1,fromneedle,usingneedle,toneedle);
i++;
switch(fromneedle)
{
case 'a':switch(toneedle)
{
case 'b':printf("\t[%d]:\t%2d------>%2d\n",i,n,n);
break;
case 'c':printf("\t[%d]:\t%2d------------->%2d\n",i,n,n);
break;
}
break;
case 'b':switch(toneedle)
{
case 'a':printf("\t[%d]:\t%2d<----------%2d\n",i,n,n);
break;
case 'c':printf("\t[%d]:\t\t%2d------>%2d\n",i,n,n);
break;
}
break;
case 'c':switch(toneedle)
{
case 'a':printf("\t[%d]:\t%2d<--------------%2d\n",i,n,n);
break;
case 'b':printf("\t[%d]:\t\t%2d<--------%2d\n",i,n,n);
break;
}
break;
}
movedisc(n-1,usingneedle,toneedle,fromneedle);
}
}

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