求10KV两组电流互感器取得三相电流的接线原理图 三相电中两个电流互感器与三个电流互感器有什么区别？
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绛旓細鐢垫祦浜掓劅鍣鍙樻瘮锛3000/5=600锛10kv绾胯矾锛屽簲璇ヨ繕鏈夌數鍘嬩簰鎰熷櫒锛屽彉姣旓細锛10x1000锛/100=100锛屼袱鑰呬箣绉氨鏄妱瑙佺數搴︽暟搴旀墿灞曠殑鍊嶆暟銆600x100=60000锛岀湡瀹炵數搴︽暟鏄 锛堟湰娆℃妱琛ㄦ暟-涓婃鎶勮〃鏁帮級x60000銆
绛旓細10kv鐨勫紑鍏虫煖锛鐢垫祦浜掓劅鍣鍙樻瘮涓3000/5A锛岃繖涓椂鍊欑殑鐢甸噺璁＄畻鏂规硶鏄繖鏍风殑锛氱數閲=(鏈湀鐢佃〃璁℃暟鍊-涓婃湀鐢佃〃璁℃暟鍊)脳鐢垫祦浜掓劅鍣ㄥ嶇巼脳鐢靛帇浜掓劅鍣ㄥ嶇巼銆傛牴鎹綘鎵缁欑殑鐢垫祦浜掓劅鍣ㄥ嶇巼涓3000/5A鐨勮瘽锛屼綘灏卞彲浠ョ洿鎺ョ敤锛3000梅5=600杩欎釜鏁板拰鐢靛帇浜掓劅鍣ㄥ嶇巼锛10000/100=100杩欎袱涓暟鍘讳笌鐢佃〃璁℃暟宸肩浉涔橈紝寰...
绛旓細10kv琛ュ伩鐢靛鍣ㄦ槸鍧囪 璐熻浇锛鐢垫祦浜掓劅鍣鐢ㄤ笁鐩歌繕鏄敤涓ょ浉鏁堟灉鏄竴鏍风殑锛屽彧鏄璁＄悊蹇典笂鐨勫尯鍒
绛旓細瀹炴祴闆跺簭鐢垫祦涓嶄负闆讹紝鍗冲彲鍒ゆ柇璇ョ嚎璺晠闅滐紝鎵浠ワ紝闇瑕侀厤缃笁鐩窩T鏉ヨ绠楅浂搴忕數娴併傚浜庣數缂嗗嚭绾胯岃█锛屽湪楂樺帇锛10kV锛夌數缂嗕笂閰嶇疆浜嗕笓鐢ㄧ殑闆跺簭鐢垫祦浜掓劅鍣锛屼笉闇瑕佸啀鐢ㄤ笁鐩窩T涔嬪拰鏉ヨ绠楋紝鎵浠ラ厤缃瓵銆丆涓ょ浉CT鏉ュ疄鐜颁繚鎶ゅ姛鑳藉嵆鍙 涓嬪浘鏄110kv绯荤粺 閮芥槸瀹夎涓変釜浜掓劅鍣ㄧ殑锛屽苟涓嶆槸浣犺鐨勯珮鍘嬮兘鏄袱涓 ...
绛旓細P=1.732UIcos蠁 U:10KV I:涓娆＄數娴,绛変簬宸茬煡鐨勪簩娆＄數娴伱鐢垫祦浜掓劅鍣鍙樻瘮 cos蠁:璇ョ嚎璺繍琛屾椂鐨勫姛鐜囧洜鏁
绛旓細10 KV绯荤粺 瑁鐢垫祦浜掓劅鍣鐨勫師鍥 涓昏鏄敤浜 淇濇姢 浣庡帇绯荤粺瑁呯數娴佷簰鎰熷櫒鐨勫師鍥犱富瑕佹槸鐢ㄤ簬 璁￠噺鍜屽弽鏄犵數娴 閭ｄ负浠涔 鐢ㄤ簬淇濇姢灏卞彲浠ヨ涓や釜鍛 鑰屼笉瑁呬笁涓 鍥犱负锛氳涓や釜鍙互淇濇姢绾胯矾鐨勪笁鐩哥煭璺佷袱鐩哥煭璺備綘涓嶈闂垜 濡傛灉B鐩 鐭矾 閭ｆ庝箞鍔烇紵 鍏跺疄鐢靛姏绯荤粺杩樻湁鍏朵粬鐨勪繚鎶ら厤鍚堢殑 锛堥浂搴忎繚鎶ゃ佽繎鍚庡銆...
绛旓細涓や釜鍦堜唬琛ㄨ鐢垫祦浜掓劅鍣鏈浜涓粫缁勶紝涓変釜鍦堜唬琛ㄨ鐢垫祦浜掓劅鍣ㄦ湁涓変釜缁曠粍锛涘10KV寮鍏虫煖鏉ヨ锛屼簩涓粫缁勭殑涓鑸槸涓涓粫缁勫甫娴嬮噺浠〃锛堝鐢垫祦琛級锛屽彟涓涓粫缁勫甫鐢垫祦缁х數鍣紙濡侸GL-15鍨嬪弽鏃堕檺缁х數鍣級锛涗笁涓粫缁勭殑锛屾湁浜岀鍙兘锛屼竴绉嶅彲鑳芥槸涓涓粫缁勫甫娴嬮噺浠〃锛堝鐢垫祦琛級锛屼竴涓粫缁勫甫杩囨祦缁х數鍣紙濡侱L...
绛旓細鏍规嵁鍏紡S =鏍规暟3 * U * I锛孖 = S /鏍规暟3 * U鍙互璁＄畻锛孲鏄彉鍘嬪櫒瀹归噺锛孶鏄數鍘嬬數骞筹紝铏界劧瀹冩槸10kV锛屼絾鍥犱负100KVA鍙樺帇鍣ㄦ槸閫氬父楂樹綆鏁伴噺锛屾墍浠搴旈夋嫨浣庣锛屽嵆0.38KV銆傛牴鏁3绾︾瓑浜1.732锛屽洜姝よ繖閲孖 = 100 / 1.732 * 0.38 = 151.9锛屽簲浣跨敤150/5銆傚鏋滆浣跨敤200/5锛屽彲鑳戒細瀵艰嚧娴嬮噺...
绛旓細鐩搁噺Ia+Ib+Ic=0锛屾樉绀虹殑鏄悎鎴愮殑B鐩鐢垫祦锛
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