平方差公式分解因式 过程

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=a(a^2-b^2)=a(a+b)(a-b)
=(x-y)(m^2-n^2)=(x-y)(m+n)(m-n)
=2(1-m^4)=2(1+m^2)(1-m^2)=2(1+m)(1-m)(1+m^2)
=3[(x+y)^2-9]=3(x+y+3)(x+y-3)
=(b-1)(a^2-b^2)=(b-1)(a+b)(a-b)
=(3m^2-n^2+m^2-3n^2)(3m^2-n^2-m^2+3n^2)=8(m^2-n^2)(m^2+n^2)=8(m+n)(m-n)(m^2+n^2)
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1.x^2-(a+b-c)^2
=(x+(a+b-c))(x-(a+b-c))
=(x+a+b-c)(x-a-b+c)

2.(a-b)(3a+b)^2+(a+3b)^2(b-a)
=(a-b)(3a+b)²-(a+3b)²(a-b)
=(a-b)[(3a+b)²-(a+3b)²]
=(a-b)[(3a+b+a+3b)(3a+b-a-3b)]
=(a-b)(4a+4b)(2a-2b)
=8(a-b)²(a+b)

1.x^6-1/4y^4
=(X^3)^2-(1/2Y^2)^2
=(X^3+1/2Y^2)(X^3-1/2Y^2)
2.(x+y)^2-(x-z)^2
=(X+Y+X-Z)(X+Y-X+Z)
=(2X+Y-Z)(Y+Z)

1.x^6-1/4y^4
=(x^3+1/2y^2)(x^3-1/2y^2)

2.(x+y)^2-(x-z)^2
=[(x+y)+(x-z)][(x+y)-(x-z)]
=(2x+y-z)(y+z)

1.(x^3-1/2y^2)(x^3+1/2y^2)
2.[(x+y)+(x-z)][(x+y)-(x-z)]=(x+y+x-z)(x+y-x+z)=(2x+y-z)(y+z)

自己多好好看看书吧！