c语言编程,一维数组,从数组中找数 C语言编程 求大神 从键盘输入一数,然后在一个整型一维数组a...

C\u8bed\u8a00\u7f16\u7a0b\uff0c\u4ece\u952e\u76d8\u8f93\u5165N\u4e2a\u6574\u6570\u5b58\u653e\u5728\u4e00\u7ef4\u6570\u7ec4A\u4e2d,\u67e5\u627eA\u6570\u7ec4\u4e2d\u5305\u4e0d\u5305\u62ec\u6570\u636eX

int main()
{
int a[100],i,x,n;
printf("\u8bf7\u8f93\u5165\u6574\u6570\u4e2a\u6570")\uff1b
scanf("%d",n);
printf("\u8bf7\u8f93\u5165%d\u4e2a\u6574\u6570",n)\uff1b
for(i=0;i<n;i++)
scanf("%d",a[i]);
printf("\u8bf7\u8f93\u5165\u8981\u67e5\u8be2\u7684\u6570");
scanf("%d",x);
for(i=0;i<n;i++)
{
if(a[i] == x) break;
}
if(i<n)printf("\u6709\u6570\u636e%d",x);
else printf("\u6ca1\u6709\u6570\u636e%d",x);
return 0;
}

//1.cpp#includeint Pos(int *arr,int left,int right,int key){//\u5728\u95ed\u533a\u95f4[left,right]\u4e2d\u67e5\u627ekey int mid=(left+right)/2; if(key==arr[mid])return mid; else if(left==right)return -1; if(key<=arr[mid])return Pos(arr,left,mid,key); else return Pos(arr,mid+1,right,key);}int main(){ int arr[21]; int i; int key; int res for(i=1;i<=20;i++) {//\u9ed8\u8ba4\u6570\u7ec4\u5347\u5e8f\u6392\u5217 arr[i]=i*2; printf("%d ",arr[i]); } printf("\n"); printf("\u8bf7\u8f93\u5165\u8981\u67e5\u627e\u7684\u503c:"); scanf("%d",&key); res=Pos(arr,1,20,key); if(res==-1) printf("\u4e0d\u5b58\u5728\n"); else printf("\u4f4d\u7f6e:%d\n",res); return 0;}

#include <stdio.h>
#define N 10
int main()
{
int arr[N];
int n;
int i;
int flag;
for (i = 0; i < N; i++)
{
printf("请输入第%d个元素", i + 1);
scanf("%d", &arr[i]);
}

while (1){
flag = 0;
printf("请输入要查找的n的值:");
scanf("%d", &n);
for (i = 0; i < N; i++)
{
if (arr[i] == n)
{
flag = 1;
printf("数组中存在与待查找的n(%d)相等的数组元素,其下标为:%d\n", n, i);
}
}
if (flag==0)
printf("未找到n\n");
}
}

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