380V的电压下,一台功率为75千瓦时的电机所通过的电流为多少? 电压380v的双电机75-55千瓦时正常情况下电流是多少
\u7535\u538b380v,0.75\u5343\u74e6\u6c34\u6cf5\uff0c\u6b63\u5e38\u8fd0\u884c\u65f6\u7535\u6d41\u662f\u591a\u5c11\uff1f\u6839\u636e\u53e3\u8bc0\u201c\u4e09\u76f8380V,\u7535\u529b\u52a0\u500d\u201d\u4f30\u7b97\u5f97\u7535\u6d41\u662f\u529f\u7387\u7684\u4e24\u500d\u30020.75KW*2=1.5A\u6b63\u5e38\u8fd0\u884c\u65f6\u5176\u7535\u6d41\u7ea61.97A
\u529f\u7387\u4e00\u5b9a\u65f6\u7535\u538b\u4e0e\u7535\u6d41\u6210\u53cd\u6bd4\uff0c\u7535\u538b\u8d8a\u5927\u7535\u6d41\u5c31\u8d8a\u5c0f\uff0c\u5f53\u7535\u538b\u589e\u81f3420V\u65f6\uff0c\u5176\u5de5\u4f5c\u7535\u6d41I=\u529f\u7387P/\u7535\u538bU=0.75KW/420V=1.78A
\u529f\u7387\uff08\u5355\u4f4dW\uff09=\u7535\u538b\uff08380V\uff09*\u7535\u6d41\uff08I\uff09*1.732*0,8
\u4e0a\u9762\u7684\u8ba1\u7b97\u516c\u5f0f\u9002\u7528\u4e8e\u4e09\u76f8\u7535380V\u7535\u52a8\u673a
根据公式:I=P/√3UCOS =75000/1.732×380×0.85×0.85 =157.73A谢谢采纳
P=U×I 所以I=P/U=19.74
绛旓細鐢靛姩鏈鸿浆鐭╁叕寮廡=9550P/n n杞 涓夌浉浜ゆ祦寮傛鐢靛姩鏈虹殑鏁堢巼锛毼=P/锛堚垰3*U*I*COS蠁锛夊叾涓紝P鈥旀槸鐢靛姩鏈鸿酱杈撳嚭鍔熺巼 U鈥旀槸鐢靛姩鏈虹數婧愯緭鍏ョ殑绾鐢靛帇 I鈥旀槸鐢靛姩鏈虹數婧愯緭鍏ョ殑绾跨數娴 COS蠁鈥旀槸鐢靛姩鏈鐨勫姛鐜鍥犳暟
绛旓細1銆佷笁鐩镐氦娴佸紓姝ョ數鍔ㄦ満鐨勬晥鐜囷細畏=P/锛堚垰3*U*I*COS蠁锛夊叾涓紝P鈥旀槸鐢靛姩鏈鸿酱杈撳嚭鍔熺巼 U鈥旀槸鐢靛姩鏈虹數婧愯緭鍏ョ殑绾鐢靛帇 I鈥旀槸鐢靛姩鏈虹數婧愯緭鍏ョ殑绾跨數娴 COS蠁鈥旀槸鐢靛姩鏈鐨勫姛鐜鍥犳暟 2銆佺數鍔ㄦ満鐨勮緭鍑哄姛鐜囷細鎸囩殑鏄數鍔ㄦ満杞磋緭鍑虹殑鏈烘鍔熺巼 3銆 杈撳叆鍔熺巼鎸囩殑鏄細鐢垫簮缁欑數鍔ㄦ満杈撳叆鐨勬湁鍔熷姛鐜 锛歅=鈭3*...
绛旓細1涓狵W绾2A鎵浠ュぇ姒傛槸35KW
绛旓細鐢垫満姣忕浉绾垮湀閲屾壙鍙楃殑鐢靛帇涓庣嚎鐢靛帇涓鑷村潎涓380V锛岃屽湪鏄熷舰鎺ユ硶鐘舵佷笅锛岀數鏈烘瘡鐩哥嚎鍦堥噷鎵垮彈鐨勭數鍘嬩负220V銆傝绠楅瀹氱數娴佺殑鏂规硶锛氬湪涓夌浉鐢电殑鎯呭喌涓嬫湁鍏紡锛歅=鈭3UICOS蠁 (鍔熺巼=鈭3*鐢靛帇*鐢垫祦*鍔熺巼鍥犳暟锛夐瀹氱數娴侊細 I=P/鈭3UCOS蠁 =7.5/锛1.732*0.38*0.85锛=13.41( A)...
绛旓細i=P/U*cos蠁*畏*鏍瑰彿涓 I=7/0.38*0.82*0.85*1.732=15.26
绛旓細I=7*1000/380*0.85*1.732*0.82
绛旓細)杞瓙鐢垫祦棰戠巼:(1000-971)/60*3=29/ 60*3=1.45hz ;(3)鐢电鍔熺巼:S=7.5/0.786+214.5+100+112.5=9.97kva ;(4)瀹氬瓙鐢垫祦I=7.5/(1.732*0.38*0.786)=14.45A 鏁堢巼=7.5/9.97=75.2
绛旓細鐢垫祦140-160涔嬮棿锛岀湅浣犵嚎璺杩滀簡锛熶及璁′綘杩欎釜鏈灏戣70骞虫柟鐨勭嚎浜嗭紝瀹冪殑鍚姩鐢垫祦澶ぇ锛70鐨勭嚎鍑嗚浇230A锛岃繕鍙兘鍦200绫冲唴浣跨敤锛岃秴杩囦簡灏辫鑰冭檻鍔犲ぇ绾垮緞浜嗭紝
绛旓細Pe=7*3+4.5*8+2.8*17+1.7*10=121.6kW Pjs=0.2*121.6=24.32kW Qjs=24.32*1.73=42.07kvar Sjs=24.32/0.5=48.64kV.A Ijs=48.64/(1.732*0.38)=73.9A
绛旓細鐢佃〃鍙鐢ㄥ姛鍔熺巼锛岄摥鐗屾爣棰濆畾鍔熺巼涓75kw鍗充负鐢ㄥ姛閮ㄥ垎銆傜數娴140A鎬荤數娴侊紝鐢垫祦涓110A鏈夊姛鐢垫祦銆傜數琛ㄥ彧璁$敤鍔熷姛鐜囷紝鍒欐瘡灏忔椂鑰楃數閲忥細75X1=75搴︺傛瘮濡備綘涓涓湀鐢ㄤ簡100灏忔椂灏辨槸75X100=7500搴︺傚鏋滀綘瑕佹寜鎶芥按閲忔潵绠楋紝鎶戒簡涓涓囧惃锛10000梅120X75=6250搴︺傚鏋滄寜鐓х數娴佷负110A绠楋紝瀹為檯鍔熺巼搴旇涓72KW锛...