在使用打点计时器研究物体做匀加速直线运动时,一位同学得到了几条比较理想的纸带,他已经在每条纸带上按
\u67d0\u540c\u5b66\u5728\u505a\u6253\u70b9\u8ba1\u65f6\u5668\u7684\u5b9e\u9a8c\u65f6\uff0c\u5f53\u7269\u4f53\u505a\u5300\u52a0\u901f\u76f4\u7ebf\u8fd0\u52a8\u65f6\uff0c\u5f97\u5230\u4e86\u51e0\u6761\u8f83\u4e3a\u7406\u60f3\u7684\u7eb8\u5e26\u3002\u4ed6\u5df2\u5728\u6bcf\u6761\u7eb8\u5e26\u4e0a\uff081\uff09\u6309\u7167\u76f8\u540c\u7684\u65f6\u95f4\u95f4\u9694\uff0c\u5728\u7eb8\u5e26\u4e0a\u8fde\u7eed\u6253\u70b9\u7684\uff082\uff09B
\uff081\uff09\u6253\u70b9\u8ba1\u65f6\u5668\u662f\u4f7f\u7528\u4ea4\u6d41\u7535\u6e90\u7684\u4eea\u5668\uff1b\uff082\uff09\u6839\u636e\u5300\u53d8\u901f\u76f4\u7ebf\u8fd0\u52a8\u7684\u7279\u70b9\uff08\u76f8\u90bb\u7684\u65f6\u95f4\u95f4\u9694\u4f4d\u79fb\u4e4b\u5dee\u76f8\u7b49\uff09\u5f97\u51fa\uff1ax34-x23=x23-x12=x12-x01=6.11cm-3.00cm=3.11cm\uff0c\u5219x34-x12=2\u00d73.11cm=6.22cm\u5f97\uff1ax34=6.22cm+6.11cm=12.31cm\u6545\u4ece\u7eb8\u5e26A\u6495\u4e0b\u7684\u662f\u4e59\u56fe\uff1b\uff083\uff09\u6839\u636e\u8fd0\u52a8\u5b66\u516c\u5f0f\u25b3x=at2\u5f97\uff1aa=\u25b3xt2=0.0611?0.030\uff0e12m/s2=3.11m/s2\u5229\u7528\u5300\u53d8\u901f\u76f4\u7ebf\u8fd0\u52a8\u7684\u63a8\u8bbav1=x02t02=0.456m/s\u6545\u7b54\u6848\u4e3a\uff1a\uff081\uff09\u4ea4\u6d41\uff1b\uff082\uff09\u4e59\uff1b\u3000\uff083\uff093.11m/s2\u3000\u24620.456\uff0e
(1)电源频率是50Hz,则打点的时间间隔T=1 |
f |
(2)由图示可知,纸带A上相邻计数点间的间隔是6mm,图C中4、5点间的间隔与A上1、2点间的间隔之差是18mm,正好是6mm的3倍,则纸带C是从A上撕下的.
(3)纸带A的加速度a=
x12?x01 |
t2 |
0.036?0.030 |
(0.1)2 |
(4)纸带A上,打点1时的瞬时速度v=
x02 |
2t |
0.030+0.036 |
2×0.1 |
故答案为:(1)0.02; (2)C; (3)0.6; (4)0.33.
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