谁会用c语言编一个“音乐播放器”。。。要涉及‘编码、数组、函数、文件’等知识。。。十万火急, 用c++写出查找函数的实现代码,数组名array,数组长度l...

\u6c42\u95ee\u4e2ac\u8bed\u8a00\u95ee\u9898\u3001\u4efb\u610f\u4e00\u4e2a\u56db\u4f4d\u6570\uff0c\u53d6\u540e\u4e09\u4f4d\u5b58\u5165\u6570\u7ec4\uff0c\u8fd9\u6837\u7684\u4ee3\u7801\u8981\u600e\u6837\u5199\uff0c\u6709\u53ef\u4ee5\u6ee1\u8db3\u7684\u6e90\u51fd\u6570\u5417

\u6211\u64e6\uff0c\u6ca1\u5206\u554a\u3002\u3002
#include

int main()
{
int n = 1234;
int buf[4];
buf[0] = n % 10; // 4
n /= 10; // n: 123
buf[1] = n % 10; // 3
n /= 10; // n: 12
buf[2] = n % 10; // 2
n /= 10;
buf[3] = n; // 1
printf("%d %d %d %d \n", buf[0], buf[1], buf[2], buf[3]);
return 0;
}
\u5177\u4f53\u7684\u89e3\u91ca\u3002\u3002\u3002\u641c \u201dC/C++\u5b66\u4e60\u6307\u5357 \u90b5\u53d1" \u7684\u8fd9\u4e2a\u4e66\u5427\uff0c\u5728\u7b54\u7591\u5e73\u53f0\u4e0a\u6709\u7684\u3002

int i;for(i=0;i<length;i++){ if(array[i]==x)//\u5982\u679c\u627e\u5230x,\u5219\u8fd4\u56de\u4e0b\u6807\uff0c\u5426\u5219\u7ee7\u7eed\u5faa\u73af { return i;//\u8fd4\u56dei\u7684\u540c\u65f6\uff0c\u7ed3\u675f\u8be5\u51fd\u6570\u7684\u8fd0\u884c\uff0c\u8fd4\u56de\u5230\u8c03\u7528\u51fd\u6570 }}return -1;//\u6267\u884c\u5230\u8fd9\u4e00\u6b65\u7684\u8bdd\uff0c\u5c31\u8bf4\u660e\u4e4b\u524d\u6ca1\u6709\u627e\u5230\uff0c\u6240\u4ee5\u8fd4\u56de-1

#include <dos.h>
#include <stdio.h>
#include <stdlib.h>
#include <malloc.h>
#include <string.h>
#include <conio.h>
void main()
{
void set(int *set1,int *set2,char *f,char *n,int *t,int rate,int num);
void music(int *set1,int *set2,int num);
int flag=0;
FILE *f1;
int t;
int rate;
char in[3];
int i;
int n;
char *frequency;
char *note;
int *time;
int *set1;
int *set2;
int menu;
int FileName[30];
while(1)
{
f1=NULL;
flag=0;
frequency=NULL;
note=NULL;
time=NULL;
set1=NULL;
set2=NULL;
i=n=0;
printf("1 播放程序自带的音乐music1\n");
printf("2 播放程序自带的音乐music2\n");
printf("3 通过输入文件名进行音乐的播放\n");
printf("4 退出\n");

while(1)
{
scanf("%d",&menu);
if(menu==1)
{
strcpy(FileName,"music1.txt");
break;
}
if(menu==2)
{
strcpy(FileName,"music2.txt");
break;
}
if(menu==3)
{
scanf("%s",FileName);
break;
}
if(menu==4)
exit(1);

}
printf("\n该文件的音乐编码如下:\n");

/*-------------------------------------*/
if((f1=fopen(FileName,"r"))==NULL)
{
printf("不能打开文件!\n");
exit(1);
}
/*-------------------------------------*/

fscanf(f1,"%d",&rate);

frequency=(char *)malloc(sizeof(char));

note=(char *)malloc(sizeof(char));

time=(int *)malloc(sizeof(int));

while(!feof(f1)&&flag!=1)
{
fscanf(f1,"%s%d",in,&t);
if(t!=-1)
{
printf("%s %d ",in,t);
frequency[i]=in[0];
note[i]=in[1];
time[i]=t;
i++;
n++;
frequency=(char *)realloc(frequency,(i+1)*sizeof(char));
note=(char *)realloc(note,(i+1)*sizeof(char));
time=(int *)realloc(time,(i+1)*sizeof(int));
}
else
flag=1;
}
fclose(f1);

for(i=0;i<n;i++)
{
switch(frequency[i])
{

case 'h':
switch(note[i])
{
case '1':
note[i]=523;
time[i]=time[i]*rate;
break;
case '2':
note[i]=587;
time[i]=time[i]*rate;
break;
case '3':
note[i]=659;
time[i]=time[i]*rate;
break;
case '4':
note[i]=698;
time[i]=time[i]*rate;
break;
case '5':
note[i]=784;
time[i]=time[i]*rate;
break;
case '6':
note[i]=880;
time[i]=time[i]*rate;
break;
case '7':
note[i]=988;
time[i]=time[i]*rate;
break;
}
break;
case 'm':
switch(note[i])
{
case '1':
note[i]=262;
time[i]=time[i]*rate;
break;
case '2':
note[i]=296;
time[i]=time[i]*rate;
break;
case '3':
note[i]=330;
time[i]=time[i]*rate;
break;
case '4':
note[i]=349;
time[i]=time[i]*rate;
break;
case '5':
note[i]=392;
time[i]=time[i]*rate;
break;
case '6':
note[i]=440;
time[i]=time[i]*rate;
break;
case '7':
note[i]=494;
time[i]=time[i]*rate;
break;
}
break;
case 'l':
switch(note[i])
{
case '1':
note[i]=131;
time[i]=time[i]*rate;
break;
case '2':
note[i]=147;
time[i]=time[i]*rate;
break;
case '3':
note[i]=165;
time[i]=time[i]*rate;
break;
case '4':
note[i]=175;
time[i]=time[i]*rate;
break;
case '5':
note[i]=196;
time[i]=time[i]*rate;
break;
case '6':
note[i]=220;
time[i]=time[i]*rate;
break;
case '7':
note[i]=247;
time[i]=time[i]*rate;
break;
}
break;

}
for(i=0;i<n;i++)
{
sound(note[i]);
delay(time[i]);
nosound();
}

free(frequency);
free(note);
free(time);
free(set1);
free(set2);
putchar('\n');
}

}

}

曾经用汇编编过一个类似的程序,用c语言编就非常简单了

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