一道C语言的基础题:输入一个小写字母,然后转换成大写,比如在输入时候是“a”,输出的时候是“A”。 C语言基础问题[输入的A到Z的字母,大写变小写,小写变大写。...

C\u8bed\u8a00\u9898\u76ee\u63cf\u8ff0\uff1a \u4ece\u952e\u76d8\u4e0a\u8f93\u5165\u4e00\u4e2a\u5c0f\u5199\u5b57\u6bcd\uff0c\u7136\u540e\u5c06\u5c0f\u5199\u5b57\u6bcd\u88c5\u6362\u6210\u5927\u5199\u5b57\u6bcd\u8f93\u51fa\uff01

\u53ef\u4ee5\u53c2\u8003\u4e0b\u9762\u7684\u4ee3\u7801\uff1a
#include
void main()
{
char ch;
scanf("%c",&ch);
if(ch>='A'&&ch<='Z')
{
ch=ch+32;
printf("%c\n\n",ch);
}else{
printf("%c\n\n",ch);
}
}

\u6269\u5c55\u8d44\u6599\uff1a
1\u3001printf()\u51fd\u6570
printf()\u51fd\u6570\u662f\u683c\u5f0f\u5316\u8f93\u51fa\u51fd\u6570, \u4e00\u822c\u7528\u4e8e\u5411\u6807\u51c6\u8f93\u51fa\u8bbe\u5907\u6309\u89c4\u5b9a\u683c\u5f0f\u8f93\u51fa
\u4fe1\u606f\u3002\u5728\u7f16\u5199\u7a0b\u5e8f\u65f6\u7ecf\u5e38\u4f1a\u7528\u5230\u6b64\u51fd\u6570\u3002\u51fd\u6570\u7684\u539f\u578b\u4e3a\uff1a
int printf(const char *format, ...);
\u51fd\u6570\u8fd4\u56de\u503c\u4e3a\u6574\u578b\u3002\u82e5\u6210\u529f\u5219\u8fd4\u56de\u8f93\u51fa\u7684\u5b57\u7b26\u6570\uff0c\u8f93\u51fa\u51fa\u9519\u5219\u8fd4\u56de\u8d1f\u503c\u3002
2\u3001if\u8bed\u53e5
\u662f\u6307\u7f16\u7a0b\u8bed\u8a00\uff08\u5305\u62ecc\u8bed\u8a00\u3001C++\u3001C#\u3001java\u3001VB\u3001\u6c47\u7f16\u8bed\u8a00\u7b49\uff09\u4e2d\u7528\u6765\u5224\u5b9a\u6240\u7ed9\u5b9a\u7684\u6761\u4ef6\u662f\u5426\u6ee1\u8db3\uff0c\u6839\u636e\u5224\u5b9a\u7684\u7ed3\u679c\uff08\u771f\u6216\u5047\uff09\u51b3\u5b9a\u6267\u884c\u7ed9\u51fa\u7684\u4e24\u79cd\u64cd\u4f5c\u4e4b\u4e00\uff0cif\u7684\u8fd4\u56de\u503c\u4e3a\u771f\u6216\u5047\uff0c\u53ef\u4ee5\u7528bool\u578b\u53d8\u91cf\u8fdb\u884c\u5b58\u50a8\uff0c\u5360\u7528\u4e00\u5b57\u8282\u3002
\u53c2\u8003\u8d44\u6599\u6765\u6e90\uff1a\u767e\u5ea6\u767e\u79d1-printf()
\u53c2\u8003\u8d44\u6599\u6765\u6e90\uff1a\u767e\u5ea6\u767e\u79d1-if\u8bed\u53e5

#include
#include
void main()
{
char sz[200];
printf("\u8bf7\u8f93\u5165\u5b57\u7b26\u4e32\uff08\u4e0d\u80fd\u8d85\u8fc7200\u4e2a\u5b57\u7b26\uff09\uff1a");
scanf("%s",sz);
char* t = sz;
while( *t != '\0')
{
if( *t>'a' && *t<'z' ) //\u5047\u8bbe\u8f93\u5165\u7684\u5168\u90e8\u662f\u5b57\u7b26\u6ca1\u6709\u6570\u5b57
{
*t -= 32;
}
else
{
*t += 32;
}
t++;
}
printf("%s",sz);
}

“a”的ASCII码值比“A“大32,所以只要减去32然后输出字符就会变成大写,你可以查一下ASCII表,具体程序:
char a_to_A(char a)
{
return (a-32);
}接受输入的数,调用这个函数,然后输出函数返回值就好了

#inlcude <stdio.h>
int main()
{
char c;
while((c = getchar()) != EOF);
printf("%c\n", c - 32);
return 0;
}

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