化学题，急求解答
\u5316\u5b66\u9898\u89e3\u7b54\u89e3\u6790\uff1a
\u76f8\u5173\u65b9\u7a0b\u5f0f\uff1a
2KClO3 \u2015\uff08\u25b3\uff0cMnO2\uff09\u2192 2KCl + 3O2\u2191
\u5269\u4f59\u8d28\u91cf\u4e3a \u6c2f\u5316\u94be\u8d28\u91cf+\u4e8c\u6c27\u5316\u9530\u8d28\u91cf
\u6240\u4ee5KCl\u8d28\u91cf = 15.4g - 0.5g = 14.9g
\u8bbeKClO3\u8d28\u91cf\u4e3a x g\uff0cO2\u8d28\u91cf\u4e3a y g
2KClO3 \u2015\uff08\u25b3\uff0cMnO2\uff09\u2192 2KCl + 3O2\u2191
x 14.9g y
245 149 96
\u89e3\u5f97\uff1ax = 24.5g\uff0cy = 9.6g
X\uff1aN Y\uff1aNa Z\uff1aAl W\uff1aS R\uff1aCl
(1)X\u4f4d\u4e8e\u7b2c\u4e8c\u5468\u671f\u7b2cVA\u65cf
(2)\u7565
(3)\u540c\u5468\u671f\uff0c\u4ece\u5de6\u5230\u53f3\uff0c\u7535\u79bb\u80fd\u8d8a\u6765\u8d8a\u5927\uff0c\u6545Al<Cl
\u4e0d\u540c\u5468\u671f\uff0c\u5468\u671f\u6570\u8d8a\u5c0f\uff0c\u7535\u79bb\u80fd\u8d8a\u5927\uff0c\u6545Cl<N
\u7efc\u4e0a\uff1aAl<Cl<N
HCl + NaOH =NaCl +H2O
36.5 40
0.365g 0.4g
HCl%=0.365g/50g=0.73%
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