如何将16进制整型转换成字符串,例如0x5ff转换成5ff,0xa45转换成a45,转换后要存进数组

C# \u8f93\u516516\u8fdb\u5236\u5b57\u7b26\u4e32\u5728\u8f93\u5165\u6846\u8f6c\u6362\u6210\u6570\u7ec4

\u597d\u529e~~
string str = "00 07 E4 7F 6A EF";
string[] ss = str.Split(' ');
\u8bb0\u4f4f~~~
str.Split(' ');\u91cc\u9762\u662f\u5355\u5f15\u53f7\u7a7a\u683c~
\u6570\u7ec4ss\u5c31\u662f\u4f60\u8981\u7684\u6570\u7ec4\u54af\u3002\u3002
\u5b8c\u6bd5\uff01\uff01

byte array[3]={0x11,0x0f,0xac}\uff1b
char c[16];
sprintf(c,"%02x%02x%02x",array[0],array[1],array[2]);
printf("%s",c);



\u5173\u952e\u5c31\u5728printf\u7684\u683c\u5f0f\u7b26%02x \u8868\u793a\u8f93\u51fa2\u4f4d\u5341\u516d\u8fdb\u5236\u6570\u5e76\u5728\u524d\u9762\u88650

#include <stdio.h>
char intTochar(int num){
char letter;
if (num<=9)
{
letter='0'+num;
}
else
{
letter='a'+num-10;
}
return letter;
}
void main(){
char arr[50]={'\0'};
int count=0,i=0,num;
printf("请输入一个十六进制整数:");
scanf("%X",&num);
while (num/16!=0)
{
arr[i++]=intTochar(num%16);
num/=16;
count++;
}
if(num!=0){
arr[i]=intTochar(num);
count++;
}
for (i=0;i<count/2;i++){//高低位互换
char mid=arr[i];
arr[i]=arr[count-i-1];
arr[count-i-1]=mid;
}
printf("%s\n",arr);
}

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