一到简单的C语言题目 C语言的简单题目
\u8d85\u7b80\u5355\u7684C\u8bed\u8a00\u521d\u5b66\u8005\u9898\u76ee\u91c7\u7eb3\u8981\u52a0\u70b9\u60ac\u8d4f\u54e6
\u4e00\u3002
#include
void main()
{
int i,num;
printf("please input a number");
scanf("%d",num);
i = 2;
while(i < num/2)
{
i++;
if(num%i==0)
{printf("This is not a prime");break;}
else
{ printf("This is a prime."); break;}
}
}
\u4e8c\u3002
include
void main()
{
int i,j;
for(i=1;i<10;i++)
{
for(j=1;j<=i;j++)
printf("%d * %d = %d \t",i,j,i*j);
printf("\n");
}
}
\u4e09
include
void main()
{
int i,k,m,p,m1=1,k1=1;
scanf("%d%d",k,m);
for(i=1;i<m;i++)
k1*=i;
m-=k;
for(i=1;i<m;i++)
m1*=i;
p = k1 / m1;
printf("%d",p);
}
***********\u7b2c\u4e00\u9898**********
long a; //\u964c\u751f\u4eba\u7ed9\u5bcc\u7fc1\uff0c\u5355\u4f4d\u4e07
long b; //\u5bcc\u7fc1\u7ed9\u964c\u751f\u4eba\uff0c\u5355\u4f4d\u5206
int main()
{
int i;
long todaygive;
todaygive=1;
for(i=0;i<30;i++)
{a+=10;
b+=todaygive;
todaygive*=2;
}
printf("\u964c\u751f\u4eba\u7ed9\u5bcc\u7fc1:%ld0000\u5143\n",a);
printf("\u5bcc\u7fc1\u7ed9\u964c\u751f\u4eba:%ld.%ld\u5143",b/100,b%100);
getchar();
}
***********\u7b2c\u4e8c\u9898**********
struct student{
char name[20];
int score[3];
int ave;
}student[5];
int input()
{
int i;
for(i=0;i<5;i++)
{
printf("Student %d:",i+1);
gets(student[i].name);
printf("\u8bed\u6587:");
scanf("%d",&student[i].score[0]);
printf("\u6570\u5b66:");
scanf("%d",&student[i].score[1]);
printf("\u8ba1\u7b97\u673a:");
scanf("%d",&student[i].score[2]);
getchar();
student[i].ave=student[i].score[0]+student[i].score[1]+student[i].score[2];
student[i].ave/=3;
}
}
int print()
{
int i;
int max=0;
int maxid=0;
printf("%20s%5s%5s%7s%5s\n","\u59d3\u540d","\u8bed\u6587","\u6570\u5b66","\u8ba1\u7b97\u673a","\u5e73\u5747");
for(i=0;i<5;i++)
{if(student[i].ave>=60)
printf("%20s%5d%5d%7d%5d\n",student[i].name,student[i].score[0],student[i].score[1],student[i].score[2],student[i].ave);
if(student[i].ave>max) {maxid=i; max=student[i].ave;}
}
printf("\u6700\u9ad8\u5206:%s",student[maxid].name);
}
int main()
{
input();
print();
getchar();
getchar();
}
**************\u7b2c\u4e09\u9898****************
int main()
{
int i=0,j=0,k=0,l=0;
int count=0;
printf("%4s%4s%4s%4s\n","10\u5143","5\u5143","2\u5143","1\u5143");
for(i=1;i<10;i++)
for(j=1;j<20;j++)
for(k=1;k<40;k++)
for(l=1;l<40;l++)
{
if(i+j+k+l==40&&i*10+j*5+k*2+l==100)
{printf("%4d%4d%4d%4d\n",i,j,k,l);
count++;
}
}
printf("\u5171\u6709%d\u79cd\u6362\u6cd5.",count);
getchar();
}
************\u7b2c\u56db\u9898***********
int b1,b2,b3;
char color[4][7]={"Red","While","Yellow","Blue"};
int count;
int main()
{
for(b1=0;b1<4;b1++)
for(b2=0;b2<4;b2++)
for(b3=0;b3<4;b3++)
if(b1!=b2&&b2!=b3&&b3!=b1)
{printf("%7s%7s%7s\n",color[b1],color[b2],color[b3]);
count++;
}printf("Total:%d",count);
getchar();
}
\u56de\u7b54\u8005\uff1asoyboydoy - \u52a9\u7406 \u4e09\u7ea7 6-21 19:03
\u7b54\u4e86\u8fd9\u4e48\u591a\u5efa\u8bae\u52a0\u6700\u4f73
#define pi 3.14
void lab1(double r,double *s,double *v);
void lab2(double r,double *s,double *v);
void lab3(double r,double h,double *s,double *v);
int main()
{
int k;
double r,h,l,s,v;
printf("请输入您所要求的图形名称，输入1是求球体的体积和表面积，输入2是求立方体的体积和表面积，输入3是求圆柱体的体积和表面积 ：\n");
scanf("%d",&k);
switch(k)
{
case 1:
printf("请输入球体的半径：");
scanf("%lf",&r);
lab1(r,&s,&v);
printf("您要求的球体体积为%lf,表面积为%lf",v,s);
break;
case 2:
printf("请输入立方体的边长：");
scanf("%lf",&l);
lab2(l,&s,&v);
printf("您要求的立方体体积为%lf,表面积为%lf",v,s);
break;
case 3:
printf("请输入圆柱的半径和高：");
scanf("%lf%lf",&r,&h);
lab3(r,h,&s,&v);
printf("您要求的圆柱体的体积为%lf,表面积为%lf",v,s);
break;
}
return 0;
}
void lab1(double r,double *s,double *v)
{
*s=4*pi*r*r;
*v=4/3.0*pi*r*r*r;
}
void lab2(double r,double *s,double *v)
{
*s=6*r*r;
*v=r*r*r;
}
void lab3(double r,double h,double *s,double *v)
{
*s=2*pi*r*r+2*pi*r*h;
*v=pi*r*r*h;
}
case 1:printf("请输入球体的半径：");scanf("%lf",&r);lab1(r,s,v);printf("您要求的球体体积为%lf,表面积为%lf",*v,*s);break;
case 2:printf("请输入立方体的边长：");scanf("%lf",&l);lab2(l,s,v);printf("您要求的立方体体积为%lf,表面积为%lf",*v,*s);break;
case 3:printf("请输入圆柱的半径和高：");scanf("%lf%lf",&r,&h);lab3(r,h,s,v);printf("您要求的圆柱体的体积为%lf,表面积为%lf",*v,*s);break;
这一段代码里lab1，lab2，lab3 这三个函数的参数类型和函数声明的参数类型不不匹配，这里是double型，你声明的函数里是double型指针，希望能帮助你，望采纳
double *ps,*pv;//指针声明
double r,h,l,s,v;
ps=&s;
pv=*v;//指针初始化
switch(k)
{
case 1:printf("请输入球体的半径：");
scanf("%lf",&r);
lab1(r,ps,pv);
printf("您要求的球体体积为%lf,表面积为%lf",*v,*s);
break;
}
void lab1(double r,double *s,double *v)
{
*ps=4*pi*r*r;
*pv=4/3.0*pi*r*r*r; //后面的两个你自己改吧
}
纯手打望采纳
switch(k)
{
case 1:printf("请输入球体的半径：");scanf("%lf",&r);lab1(r,s,v);printf("您要求的球体体积为%lf,表面积为%lf",*v,*s);break;
case 2:printf("请输入立方体的边长：");scanf("%lf",&l);lab2(l,s,v);printf("您要求的立方体体积为%lf,表面积为%lf",*v,*s);break;
case 3:printf("请输入圆柱的半径和高：");scanf("%lf%lf",&r,&h);lab3(r,h,s,v);printf("您要求的圆柱体的体积为%lf,表面积为%lf",*v,*s);break;
你直接把求体积和表面积的函数分开 ，你只需要在主函数调用函数时用一个半径做实参 ，然后返回一个值就不行了
你怎么用这么多指针？真是舍近求远，给自己找麻烦
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